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Re: Find the antilog on the TI-84 Plus for finding pH in...
I'm not specifically familiar with the TI83 or TI84 but I've used a lot of TI calculators in my time, so I'll give it a try. If your trying to find the antilog of a number in base 10 enter the number and hit the (10 to the X) button. If you're trying to find the antilog of a number in in base e (natural log), enter the number and hit the (e to the X) button.
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Your best bet would be trying a math package on ti-calc.org - you can usually find something that does what you want there. You'll need a cable and the software to download these programs to your calculator. Here's a link to the trig section:
The common antilog is the shifted function of the common log key (marked LOG, just to the left of the 7 key). The natural antilog is the shifted function of the natural log key (marked LN, just to the left of the 4 key).
As you well know the pH is the negative of the log in base 10 of the H+/H3O+ ion concentration. If we use [H+] to represent that concentration, then pH=-log[H+]. To obtain the [H+] you need to calculate the antilog. You write the definition in the form log[H+] =-pH and then calculate 10 to the power of each member. The equality remains valid as both members are treated similarly. Thus 10^( log[H+] ) = 10^(-pH) Since raising 10 to a power is the inverse function of taking the log in base 10, 10^(log(x))=log(10^(x)) = x (they are inverse of one another), you are left with
Your calculator has a function [10 to x] accessed by pressing the [2nd] function key. To use it you must enter the negative value of the pH, press the [2nd] function key then the [10 to x], then the = key to get the result (concentration) Exemple: let the pH=5.5, what is the H+ concentration? With [(-)] being the change sign key, then [H+]:[ (-) ] 5.5 [2nd][10 to x] [=] The result is 0.000003162 or 3.16 x 10^(-6)