Look at these equations 11=6+a a+7=10+b use both equations to work out the value of b??

First, we will find y in terms of x. We will use the first equation to determine this.
4x+2y=2
We can subtract 4x from both sides:
2y=2-4x
And then divide both sides of the equation by two:
y=1-2x
Since we now have y in terms of x, we can substitute this into our second equation.
-3x-y=-3
-3x-(1-2x)=-3
Then, we can distribute the minus sign
-3x-1+2x=-3
-x-1=-3
Next, we can add 1 to both sides of the equation.


-x=-2
Finally, we divide both sides by negative one to isolate x.
x=2
Now that we have x's value, we can find y's value.
The first thing that we determined is:
y=1-2x
We can substitute in the value of x to this equation.
y=1-2x

y=1-4
y=-3
Therefore, we now have the values of both variables.
x=2
y=-3

If you have the equation of the line (of best fit), enter a value of x in the equation to get the value of y. Similarly, if you have a target value of y, enter it in the equation and solve for the value of x. That's about it.

In equation mode, you have system of linear equations (3 unknown) you have polynomial (quadratic and cubic), and solver. Use the solver foe any type of equation (nonlinear, polynomial of order higher than 4, trigonometric, exponential, logs).

Definition

A mathematical statement used to evaluate a value. An equation can use any combination of mathematical operations, including addition, subtraction, division, or multiplication. An equation can be already established due to the properties of numbers (2 + 2 = 4), or can be filled solely with variables which can be replaced with numerical values to get a resulting value. For example, the equation to calculate return on sales is: Net income ÷ Sales revenue = Return on Sales. When the values for net income and sales revenue are plugged into the equation, you are able to calculate the value of return on sales.

There are many types of mathematical equations.

1. Linear Equations y= mx + b (standard form of linear equation)
2. Quadratic Equations y= ax^2+bx+c
3. Exponential Equations y= ab^x
4. Cubic Equations y=ax^3+ bx^2+cx+d
5. Quartic Equations y= ax^4+ bx^3+ cx^2+ dx+ e
6. Equation of a circle (x-h)^2+(y-k)^2= r^2
7. Constant equation y= 9 (basically y has to equal a number for it to be a constant equation).
8. Proportional equations y=kx; y= k/x, etc.

First thing to do, before you enter the value of the equation to your calculator multiply the first term((1/3x+5) from the second term(1/3x+5) to make your answer simplified.Then after that you will observed that your answer look like in this pattern AX2 +BX+C it means that the equation is in general form of quadratic equation. So, in your problem,we are looking for a value of X1 and X2,when you used your calculator in solving this problem, First On you calculator then look for the mode then press it after that look for the equation(EQN).Then from the side of the word EQN there is a corresponding number to press,from my calculator it is number 5..Then press it.After you press it, there is a equations choices,look for the equation AX2 +BX+C then press it(given number to press). Now,enter the value of A, B and C from your simplified answer. After pressing the value of A press = sign from your calculator same as B and C.After you enter all the value of A,B and C continuously press = sign from your calculator till you get the answer, the value of X1 and X2.

OK, you just have to put those values into the equation, do the math, and see if it works.

-6 * 5/6 - 7 * (-2) = 9 does it?

-5 - (-14) = -5 + 14 = 9 yes it does

You can (and probably should) always check a solution by testing this way. The definition of a solution is a value or set of values that cause the equation to work out. If the test had failed (say we had gotten -6 = 9 before, which is obviously wrong), we'd know that the values weren't a solution.

You are looking for a line (y=m*x+b) and have two points. From this information you can generate two equations with two unknowns (m and b are unknown).
First plug in the first point (1,5) to the general form:
5(the y value of the point) = m*1(the x-value at this point)+b
Do the same for the second point you're given.
From here solve the first equation for m in terms of b.
Plug this value of 'm' into the second equation so you will end up with something like:
3=(something in terms of b)*(-2)+b
This final equation can be solved for b (try factoring)
You now have a value for the y-intercept. Plug that into y=m*x+b
Choose either of the two points, plug into the equation on the last line with the value of b known
You then know y, x, and b and have m as the remaining 1 unknown. Solve for that and put it all together for your final answer.

You cannot. The TI-30XA is a simple calculator lacking any symbolic algebra or equation processing. However, if your task is "given a value for x, what is the value for y" for the equation you give, you can rearrange it a little:



Thus, if you want to determine the value of y for x = 16, key in 5 [-] 16 [÷] 4 [=] and get the result y = 1. To double check, substitute x and y in the original equation:
16 + 4 x 1 = 16 + 4 = 20.

This expression 5x^2+15x+3 is not an equation, therefore it can have any value depending on the value of x. You have to make it an equation before looking for the particular value of x that satisfy your equation 5x^2+15x+3 =0

This calculator cannot solve equations because it does not have an equation solver.

I assume that if you want to input the equation it is with the intent to solve it. If that be the case then what follows will help you input and solve any equation (linear, quadratic, trig, etc.)

Make sure the calculator angle unit is the same as your problem requires (degree, radian, grad). Here are some screen capture to help you. Change the equation to yours.
To enter the equation in screen above, use the right arrow.


You have to enter an initial guess on line X=, a default value may be supplied by calculator: It depends on last value stored in X. Once a value is entered press the F6 key to SOLV


Press F1: Rept if you want to solve another equation.