How does gravity affect how objects fall to the ground

Prove gravity
The old same weighted objects falling from a determined hight as apposed to differently weighted objects falling from the same hight.

Weight and friction

It is probably not advisable, I believe engineers take the effects of gravity into consideration when designing things. Can you imagine those heavy components falling into electrical cabling, sounds like a hair raising experience!!!!!
Think I mean ,very emphatically, that you should not do it


GOOD LUCK

For any free-falling object, the distance traveled by that object can be represented as:

s = 1/2 g t2


where

s = distance traveled by the object, g = gravity, t = time

So, if we resolve for g, we get:

g = (2 x s) / t2

So, by replacing the known values we get the acceleration of gravity for that planet:

g = 7 m/s2

The same reason for the very small force of gravity between two PCs...why do you ask?

Gravity is a force that causes a mass/object to be attracted to another mass/object similar to magnetism. Gravity is not an object itself located in any particular place like earth or space.
The satellites stay in orbit around the earth because the force propelling the satellites forward away from the earth is balanced by the gravity pulling them back to earth.
The satellites move too slow and they fall back to earth. If they move too fast, they fly out further into space and out of orbit.
I hope this answers your question.

1st, Your alternator is charging real heavy. the lower yhe voltage the hidher the amps. 2nd, yes, Turn on one and the other dima is indicarive of a poor ground which would in turn affect the charging rate. Nowm The bad ground is more than likely the battery cable on the negative. But, Check the other end of the cable also. good luck- Ned

It does not affect the system. It enables normal running. But it slows down downloading.

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You could do a bit of research as i can't remember the math's from my college days, but, it is possible to calculate the distance something travels by using its rate of descent against the time it takes to reach the ground, for instance, if gravity is measured at 9.81N/m per sec squared, then an object must speed up at the same rate from standstil every time unless the earths gravitational pull changed. If you then timed how long it takes to hit the ground you could do a simple calculation offsetting the rate of descent against time which would then give your distance. The calculation is - distance = speed x time, but you would need to factor in the the rate of change in the speed of the object from standstill to finish which is the bit i can't remember.