Assuming an efficiency of 38.10%, calculate the actual yield of magnesium nitrate formed from 138.1 g of magnesium and excess copper(II) nitrate.

Download the Guide of Calculator form Texas Instruments official website BA II PLUS™ Guidebook - Texas Instruments - US and Canada (ti.com) and refer to page 82 (Reference Information)

That is 4 / 80 * 100 = 5%
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Make sure Z and Y are not defined as a variable in the flash memory, use the command to CLRVAR: Z,Y in your program.

Assuming you want the result in the form :
a) 120% (if positive) or 80% (if not), then percent = Actual / Budget * 100
b) 20% (if positive) or -20% (if not), then percent = (Actual / Budget * 100) - 100

This is NOT a forum for college problem solutions. How would you have a 20 KVA transformer and an Atlas Sound AF140... these are different animals... Autotransformer is a more efficient connection when it is possible... the transformer will step the 220 up to 2200+220 volts ignoring the copper loss voltage. For proper designed transformers the primary and secondary copper losses should be close to equal... but in autotransformer connection the efficiency is improved as the added voltage of the supply going to the high voltage winding power does NOT suffer and add to the current required in the primary of this connection. The purpose of this problem is for you to discover that the efficiency of autoformer connection is higher than of a simple step up connection. Now with this carefully work the problem... The ratio I have all but given you... It is unclear what is considered full load here so I would base it on regular connection at 20 KVA at 2200 volts to calculate what the currents would be primary and secondary.in normal connection... calculate resistance of primary and secondary ASSUMING equal losses primary and secondary. What isn't clear is if the loss figures are for the autoformer connection OR just the specs for normal connection. The power factor kink adds to the misery. Approach this problem by making an equivalent circuit of the transformer showing the primary and secondary resistances... again the question is are the loss figures the specs of the transformer or the actual running values for the system....

It's giving you the correct answer for the problem you've input. When you specified 1 for n, you told it one month. If you specify more digits, you'll see that the answer is 1.00833333.

By default, the calculator works with annual interest rates but counts periods in months.

http://www.understandfinance.com/yield-to-maturity/

Hi..my name is Keith..and im assuming you have OBD II..and the code 138 means that...O2 sensor circuit,high voltage(cyclinder bank #1,sensor #2)..i hope this will help you