Right Triangle ABC has vertices A (-4 2)B(-4 6) C (9 6)

Hi David:
You've got me confused.
A triangle has 3 sides. You have provided 4 lengths and no picture.
The hypotenuse is joins the 2 sides that are the "legs" of the right angle.
The length of the hypotenuse is the square root of the sum of the squares of the sides.
Just apply the "rule" to the appropriate dimensions.
Cheers

I find the easiest way to solve these is to sketch them first (I'm a visual learner;) We get a nice right-angled triangle, with the right-angle at B. The formula for the area of a triangle is 1/2 * base* height or (base * height)/2.

We can use BC or AB as the base.

If we use BC as the base, the length is 9-4 or 5. The height is 6-2 or 4.

We can now but the base and the height in the formula to figure out the area.

Good luck.

Paul

The area of a triangle is 1/2 times base times height. A sketch of the triangle in the coordinate plane will determine how easy or hard this will be to be. From the sketch, you will see that this is a right-angled triangle with B being the right-angle. This makes it easier because we can easily determine the base and the height to use in the formula.

We can chose AB or BC to be the base, while the other will be the height. If we choose the base of AB, its length is 4, the 6 - 2. The height is 9-(-4) or 13.

We can now put the length and height into the formula to calculate the area of the triangle.

Good luck.

Paul

The are of a triangle is 1/2 * the base * the height.

So if the triangle is 2 for the base and 4 for the height. it would be (2*4*1/2) or 2*4=8, 8*1/2=4. So the area of the triangle would be 4 square (until of measure).

Of course this assumes you know the base and the height of the particular triangle.
This site might be a bit more helpful for calculations where some of the numbers may not be known. Good luck!

http://www.wikihow.com/Calculate-the-Area-of-a-Triangle

Hi Dikita, is this for a math/trig question? Normally the points on the triangle is named A, B and C, then it is called triangle ABC. In your case they are talking about a triangle called PQR.

Let me know what the full question is, and what the diagram looks like... Good luck.

How does x relate to anything else in the problem?

Consider a minor translation of the problem: There are three cars. One is white, one is black, and one is red. What color is the pickup truck?

Let ABC be the equilateral triangle,
and PC be the line joining the mid point of A and C.
We know that equilateral triangle has equal angles which means

Now,
in triangle AHC
Sin(THETA) = AH/AC

That is...
Sin(60) = (7root3)/AC

or AC = (7root3)/Sin(60)

AC=14

Perimeter of equilateral triangle ABC = 3 x Side
= 3 x 14
= 42

In right triangle we are making 90 degree angle triangle, we can have problem for finding hypotenuse or finding sin or cos values of the side of the triangle. For ex,Find out the hypotenuse,sin and cos value of the right triangle with base 4 cm and perpendicular 3 cm Solution:Hypotenuse = SQRT(4^2 + 3^2) =SQRT(4*4 + 3*3) =SQRT(16+9)=SQRT(25)=5 cm For right triangle, sin(x)=3/5=0.6 cos(x)=4/5 =0.8

a. 49.93
b. 95.19
c. 50.93
d. 23.60
e. 122

C = 3B = 2(A+B)
3/2 B = A+B
1/2B = A
C = 2 (1/2B + B)
C = 3B

**A = 1/2B
C = 3B
B = B

1/2B + 3B + B = 4 1/2 B
180/4.5B => B = 40

If B = 40, then A = 1/2B = 20 and C = 3B = 120.

**answer: A = 20 degrees, B = 40 degrees and C = 120 degrees.