White LEDs are re-purposed from a key chain flash light running on two CR2016 3 volt batteries at 90 mAh. There are 8 in total. Yellow flickering LEDs are re-purposed from a flickering candle running off a single CR2016 3 volt battery at 90 mAh. There was no resistor in the circuit.
With the explanation of nik you can solve the problem. All you need is a multimeter to measure the consumption of one LED an then you can determine the value of resistors and power of battery. Here is an electric circuit for you to figure the hole connection needed. It is advisable to divide the circuit in blocks in order lo achieve better performance. If one led became short circuit, only the segment where is located will be off. The requirements of power for resistors will be easier too. You can even divide in bore blocks, depending on the power of LEDs.
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The question is how do I use one power supply and separate the two parallel circuits with the appropriate resistors to run each separate parallel circuit of LEDs - orange and white - and what resistors are required to to provide the appropriate amperage for each circuit when running off 4 "D" size batteries?
Montejo gave you a great schematic. If you're a lazy experimenter like me, put a 10K potentiometer in place of the resistors marked R1, R2 etc, then slowly turn the pot till you get an acceptable brilliance on the LEDs. Measure the resistance of the pot, and there you have the necessary R value. If you don't have the same number of LEDs in each circuit, repeat the procedure for each leg.
As a rule of thumb, each LED on a 1.5 v power supply will require a resistor of between 200 Ohm and Ik Ohm.
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