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...you find a straight **line** that has a positive **slope** and itersects the y axis at y=2. To **graph** it [Diamond][Y=] on **line** Y1= enter X+2 [ENTER]. Then [Diamond][**GRAPH**] . Here is what you see. Hope it ...

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and b=y-intercept). 4x+2y=12 2y=-4x+12 y=-2x+6 From this you can easily read the **line**'s **slope** (-2) and y-intercept (6). You could also just set x=0 and solve for y, but this doesn't give you the **slope**

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...**line**. The "**slope**-intercept" form of a **line** is y = mx + b where m is the **slope** (change in y-value / change in x-value) and b is the y-intercept (the point where the **line** crosses the y-axis when x=0) ...

**slope** is just one number that characterises a **line**ar function. Rather you need to draw the **line**ar function.Press the Y= key to enter the function editor. On **line** Y1= type in a legitimate function such

...**line** that has the **slope** can be **graph**ed if you have its complete equation y=**slope***x + initial value. To **graph** a curve on the TI84 open the Y= editor, type in the second member (right side) of the ...

Question about TI-84 Plus Calculator

Calculate the **slope** of the secant **line** through the points on the **graph** where x=1 and x=3. You have to provide the **graph**. Depending on the **graph**, the **slope** of the secant **line** can be just about anything

...Since 0 divided by anything is 0, the rise must be zero, so the **slope** of 0 is a horizontal **line**. Put the point and the **slope** together, we have a horizontal **line** going through (-3,-3). Good luck. ...

...**slope** of -4 to get future points. Since it is negative, we go one unit to the left and up four units. So we have the point (-1,4). Using a ruler, we connect these points and continue on both sides to ...

**slope** of -4 to get future points. Since it is negative, we go one unit to the left and up four units. So we have the point (-1,4). Using a ruler, we connect these points and continue on both sides to ...

...of 18 (0,18) From this point, we can start **graph**ing the **line** by using the **slope** of -2. Since the **slope** is negative, it goes up to the left. So we go one to the left, and up two. Good luck. ...

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