Questions & Answers for: SoftMath how to pi

I need to rewrite Y=5(sqrt2)sin(x)-5(sqrt2)cos(x) as Y=Asin(Bx-c) Use the fact that cos(pi/4)=sin(pi/4)= 1/square root(2). Trigonometric identity cos(a+b)=cos(a)cos(b)-sin(a)sin(b).

solve the following equation for the indicated value of x: y = 4 sin x; for x = pie Since X = pi, (3.141592...) I'm going to assume the problem is in radians not degrees. Substitute pi in for X in the

change to algebraic form (2arcsin(x)+arcsin(y)=pi) This link will help: http://www.analyzemath.com/Inverse-Trigonometric-Functions/questions.html

you can't have a negative radius meaningfully. If you do, the graph is in the 1st and 4th quadrants Pi * r^2 * h is always a positive answer anyway

...area an circumferance The circumference of a circle is given by the expression Circumference= 2* PI* Radius of circle C=2*Pi*R The area is given by Area of a disk with radius R = Pi* R*R or ...

... http://www.analyzemath.com/trigonometry/graph_sine.gif You can see that where sin(x) = -1, x = 3/2 Pi (270 degrees). So that is the first of many solutions, which recur every 2 Pi (or 360 degrees) ...