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A 33 year old mother has a son 9. in how many years will the mother be twice as old as her son?

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33 + x = 2 (9+x)
33 + x = 18 + 2x
33 + x - 2x = 18
33 - x = 18
x = 15

In 15 years (The mother will be 48 and the son 24).

Posted on Jun 20, 2011

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