Question about Microsoft Computers & Internet

Ad

How many combinations of 6 numbers are there in the 20 numbers

as set out here . 2.4.6.12.18.20.24.26.28.30

5.7.9.15.17.21.23.25.29.31

Posted on Nov 10, 2013

Ad

Dear Sir/madam,

Read out the formula with examples of the Ms-word Help Menu. PERMUT, COMBIN. It will all teach you......

thanks

good luck

Posted on Aug 14, 2008

Ad

U have to go with a professional

Posted on Aug 14, 2008

Hi,

Have you tried "PERMUT" using MS Excel?

Hope this be of initial help/idea. Pls post back how things turned up or should you need additional information.

Good luck and kind regards. Thank you for using FixYa.

Posted on Aug 13, 2008

Too many to list (3,125). It would take you forever to get it unlocked. I would suggest bolt cutters and just spend the 20-30 bucks to buy a new one.

Aug 22, 2014 | Kensington Black Portable Combination Loc

One-number combinations: { 1 2 6 9 }

Two-number combinations: { 12 16 19 26 29 69 }

Three-number combinations: { 126 129 169 269 }

Four-number combinations { 1269 }

Or did you want permutations?

Two-number combinations: { 12 16 19 26 29 69 }

Three-number combinations: { 126 129 169 269 }

Four-number combinations { 1269 }

Or did you want permutations?

Jul 07, 2014 | Computers & Internet

There's only one six-digit combination possible, namely the digits 1, 2, 3, 4, 5, and 6.

If the order matters then there are 720 possible permutation. I'm not going to list them all. Start with 123456, then 123465, 123546, and so on to 654312 and 654321.

If the order matters then there are 720 possible permutation. I'm not going to list them all. Start with 123456, then 123465, 123546, and so on to 654312 and 654321.

Mar 25, 2014 | Computers & Internet

That depends on how many of those six numbers you take.

If you only take one number, there are six combinations: {1}, {2}, {3}, {4}, {5}, and {6}.

If you take two numbers, there are fifteen combinations: {1,2}, {1,3}, {1,4}, {1,5}, {1,6}, {2,3}, {2,4}, {2,5}, {2,6}, {3,4}, {3,5}, {3,6}, {4,5}, {4,6}, and {5,6}.

If you take three numbers, there are twenty combinations.

If you take four numbers, there are fifteen combinations.

If you take five numbers, there are six combinations.

If you take all six numbers, there is only one combination: {1,2,3,4,5,6}.

In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

If you only take one number, there are six combinations: {1}, {2}, {3}, {4}, {5}, and {6}.

If you take two numbers, there are fifteen combinations: {1,2}, {1,3}, {1,4}, {1,5}, {1,6}, {2,3}, {2,4}, {2,5}, {2,6}, {3,4}, {3,5}, {3,6}, {4,5}, {4,6}, and {5,6}.

If you take three numbers, there are twenty combinations.

If you take four numbers, there are fifteen combinations.

If you take five numbers, there are six combinations.

If you take all six numbers, there is only one combination: {1,2,3,4,5,6}.

In general, if you take 'm' objects out of a set of 'n' objects, the number of combinations is given by n!/[(m!)(n-m)!] where '!' is the factorial operator.

Apr 30, 2013 | Mathsoft Computers & Internet

The model number you listed 4638975, does not match any current Char-Broil models.

Please check again, confirm and let me know the correct model number.

Thanks for choosing FixYa.

Please check again, confirm and let me know the correct model number.

Thanks for choosing FixYa.

Sep 20, 2011 | Char-Broil CharBroil Master Flame Gas...

The terminals you listed are correct.

T4 -T7 mated

T5 -T8 mated

T6 -T9 mated

10, 11, 12 combined connection

L1, L2, & L3 = output / line leads

However you should have 277 VAC line to ground and 480 VAC Line to line (Across any 2 phases)

So terminals 1, 2 or 3 to ground should be 277 VAC (L1 L2 or L3)

1-2 or 1-3 = 480 VAC

any combination of

1 , 2, or 3 to each other = 480 VAC

As a "generator man" with 19 solutions one being "You might have to sting it" you should know this and be able to use the diagram on the power head to get your desired voltages unless the wiring data plate is missing. I have had to dial in voltage regulators when switching between 240 and 480 to prevent automatic shut downs from over / under voltage.

Kelly

T4 -T7 mated

T5 -T8 mated

T6 -T9 mated

10, 11, 12 combined connection

L1, L2, & L3 = output / line leads

However you should have 277 VAC line to ground and 480 VAC Line to line (Across any 2 phases)

So terminals 1, 2 or 3 to ground should be 277 VAC (L1 L2 or L3)

1-2 or 1-3 = 480 VAC

any combination of

1 , 2, or 3 to each other = 480 VAC

As a "generator man" with 19 solutions one being "You might have to sting it" you should know this and be able to use the diagram on the power head to get your desired voltages unless the wiring data plate is missing. I have had to dial in voltage regulators when switching between 240 and 480 to prevent automatic shut downs from over / under voltage.

Kelly

Sep 18, 2011 | Electrical Supplies

Internet browsing requires rubics discused

1. the appropiate words have to typed into the search spaces to achieve any list of results.

2. the search spaces on the internet browsers allow only certain alphebet and number combinations.

3. A symbol typed into the search spaces could generate a list of codes humanly undiciperable

1. the appropiate words have to typed into the search spaces to achieve any list of results.

2. the search spaces on the internet browsers allow only certain alphebet and number combinations.

3. A symbol typed into the search spaces could generate a list of codes humanly undiciperable

Dec 06, 2010 | Hitachi Computers & Internet

I cannot find a MQU8057AEW in the Maytag library. I did find a MQU2056AEW that is 20 cu ft.

May 05, 2010 | Maytag 20 cu. ft. Upright Freezer MQU2056B

just change the T9 to english or ienglish.

Mar 06, 2008 | Samsung SYNC SGH-A707 Cellular Phone

Jul 15, 2017 | Microsoft Computers & Internet

455 people viewed this question

Usually answered in minutes!

Thanks for your help but I know how to calculate how many permutations I will get what I need is to list each one of them out in 6 columns on an excel spreadsheet so I need formula to post that I can fill down in each column.

eg 111111, 111112, 111113, 111114 ... 223456 etc and so on there should be 9x9x9x9x9x9=531,441 permutations in my final list with none repeating.

I am using Microsoft excel version 2007. The CHAR I refer to is a formula option like ROUND or PERMUT. Sorry for the confusion.

I have been e-mailed to tell me that there is a new comment on this problem but there is nothing new here!!

I have not really had a response to this problem yet. Can anyone help as I need to get this list pronto!!

Thanks to all who have answered but you have all told me how to calculate how many permutations which I already know. I need formula to put at the top of each column in cells a1 to f1 which I can then fill down to give me a long column of all the combinations

eg

111111

111112

111113

111114

I have the formula for picking three alphabetical characters from ABCDEFGHIJK.

In cell A1 type =CHAR(65+TRUNC((ROW()-1)/144))

In cell B1 type =CHAR(65+MOD(TRUNC((ROW()-1)/12),12))

In cell C1 type =CHAR(65+MOD(ROW()-1,12))

This does work but I do not know how to expand it to 6 columns with 9 options. I know that CHAR 49 is the ASCII ref for number 1 and 50 is for number 2 etc so I can substitute that and I assume that the 12 will be replaced with 9 but apart from that I do not understand the logic of the formula.

I hope this helps you find me a solution.

Sue

Sorry I am new to the site. If an expert just sends a comment that says I know tha answer how do I look at it without knowing what it is?

Solved problem myself thankyou. No need to further respond.

×