At time 'ZERO', the hat was at distance 'ZERO' from the starting-point.
At time 'T', the hat was at distance 'ONE MILE' from the starting point.
The speed of the boat was the MAXIMUM speed of the boat, MINUS the speed of the current.
At time 'T+5', the hat was being carried by the stream-current toward distance 'ZERO'.
At time 'T+10', the hat was at distance 'ZERO', and the boat was at distance 'ZERO'.
The speed of the boat for the most-recent '10' minutes was the MAXIMUM speed, PLUS the speed of the current.
So, calculate the distance travelled at the 'T+5' time:
DISTANCE = VELOCITY1 multiplied by TIME1.
DISTANCE = VELOCITY2 multiplied by TIME2.
where 'VELOCITY1' is the speed travelling AGAINST the current,
and 'VELOCITY2' is the speed travelling WITH the current.
Finish this "homework" assignment on your own.
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