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Anonymous Posted on Jan 15, 2011

How do i enter this question on a ti 89? 5 sin(2 pi 2000 t +60 degrees) does anybody know i would appreciate it.

  • Anonymous Jan 16, 2011

    Oneplusgh
    I appreciate the help, I did get the same as you did . What i was looking for is the amplitude of the signal out of this question. . Is there another step i have to take to get this answer? Im looking for a 5 vpp or 3.535 vrms something on this order out of this question . Thank you

  • Anonymous Jan 17, 2011

    Thanks this has help out alot. I really appreicate it.

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  • Posted on Jan 16, 2011
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Hi ssmith63,
Put the calculator in radian angle mode. The top answer is in AUTO mode and, The bottom is in Approx mode.

how do i enter this question on a ti 89? 5 sin(2 - oneplusgh_47.jpg
I converted 60 degrees into pi/3 radian which equals 1.0472 radians. I figured 5 significant digits was good enough since, you only went 4. If you have any question just post them and, I'll respond quickly.

  • 1 more comment 
  • Anonymous Jan 16, 2011

    Vm=Vp, Vrms=Vm_/_ square of (2) or Vp*.707=Vrms. So, 5 Vp*.707=3.535 Vrms. See the amplitude is the 5 before the sin(and rest of the equation). We can forget about the rest of the equation because, it will be always changing. I took it as frequency=2000 and the plus 60 degrees is an offset. But, if you want to look at it at a different level. At about t=102 micro seconds the wave should be at it's Vrms value. This is really where most of the power is at too. I'll be glad to post more detail if needed. Remember, there is a lot of unknowns that are not given in this questions to what and, how it is applied too. Such as Vm. I don't know what level you are looking at this problem to a sure me, I'm giving you a correct solution. Vm might have a different solution.

  • Anonymous Jan 17, 2011

    Ater increasing the resolution on the graph. I found that Vrms is approx=104 micro seconds and, 102 micro seconds is good for general resolution. For Vp-p will =10 Vp-p. The rms value is still 3.53 Vrms because, it is a matter of effective voltages and the application. The values for DC briges and, Line to line voltages need to be handled differently. But, since you have only mentioned, " Vp-p and RMS values" that is how the voltage are calculated. Do you need this problem applied in a more advanced application than the one, I'm applying it now? If so, just make a comment and, I'm sure we can look this problen in a different application.

  • Anonymous Jan 17, 2011

    If you used the graph please have in radian mode and, don't use the degree sign behind the 60. Used pi/3 instead. y=5 sin(2*(pi)*2000*x (plus sign) (pi/3)), xMin=1e-4 and, xMax=1.07721518987e-4. yMin=3.33552631579 and, yMax=3.91447368421. Your scale for xscl=1 and yscl=1

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  • Posted on Jan 15, 2011
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5sin is not a correct calculator function the number before the sin, cos, tan is the exponent of the number after it so this would be sin(insert numbers here)^5 not to mention there are a couple unexplainable things wrong with the inside of the parentheses and there should be no spaces

  • 3 more comments 
  • Anonymous Jan 15, 2011

    Thanks for the help, Although when i put this in the calculator i get (sin(60))^2 for a answer . I dont believe im doing it right . So this is how im inputting it "" sin(2pi2000t 60) Im i suppose to enter degrees behind the 60 of the problem ? Cause i dont know to put that in. sorry to bother , i have 6 of these questions and if i figure out this one and how to do it , i can do the rest.

  • cole man Jan 15, 2011

    you won't have use a calculator if there is a 't' in your problem (also assuming you are not spelling out pi)

  • Anonymous Jan 16, 2011

    You can enter the degree sign after 60 for degrees in the equation, instead of converting 60*pi/180 like I did. You'll get the same answer. Just make sure your in radian angle mode.

  • Anonymous Jan 16, 2011

    He's got the brackets right. What he is actually doing is Vrms=sqr(V (L1)rms^2 V (L2) rms^2 V (n) rms^2) so, V(t)=5*sin(w (t) 60 deg), where w=2*pi*f. Vm/2=5. Looks like Power inverter??? pf-power factor. It's single wave.

  • Anonymous Jan 16, 2011

    Vrms=square root(V (L1)rms^2 (plus) V (L2) rms^2 (plus) V (n) rms^2) so, V(t)=5*sin(w (t) (plus) 60 degrees), where w=2*pi*f. Vm/2=5. Also Vm could =5 depending on what part of the wave your looking at.

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