Well, the equation is Ax=b and we want so solve for x
There are several ways of entering the data, but this is one way
Code:
A=[15+35i 29+1i; 46+13i 62+3i]
b=[0;0]
x=A\b
which has the trivial solution x=[0;0] (the ";" means "next row", a space next column.)
To input a matrix use APPs then Data/Matrix Editor then New. Then change Data to Matrix. Put in the name such as "AA" in the variable field. Then enter row and column dimensions. Then edit as a spread sheet. Use F6(util) to delete a column or row. To manipulate matrices, exit the matrix application, then go to MATH then Matrix. Notice that J(RowOpps) is available.
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Thanks for your reply. What I need to know is if the ti- 89 calculator can solve the following systmem of equations..
(1 2i)x (2 4i)y = 1
(4 4i)x (2 3i)y = 4
Do we have to use the solve fucntion as we do for other linear equations or use rref matrix and does the calculator allows entries of complex numbers in the matrix or just real numbers
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