Inter physics A motor vechicle travelled the first third of a distance s at speed of v1=10kmph,the second third at a speed of v2=20kmph and the last third at a speed of v3=60kmph.Determine the mean speed of the vechicle over the centire distance s.

Hi there, a lightyear is a measure of distance- how far does light travel in a year. Light travels at about 300,000 km/sec.

Journey time 2hrs = 2 x 60 mins = 2 x 60 x 60 seconds
Distance 180 km = 180,000 m
Average speed = 3 x 6 x 10000 / 2 x 6 x 6 x 100 m/s
= 6 x 6 x 100 x 100 / [2 x (2 x 6 x6 x100)] m/s
= 100 / 4 m/s
= 25 m/s

5.May.2014

Dear Sir:_

I will try to help you.

Please check this:

It is simple to change your treadmill so it reads MPH.

Treadmills are an easy and relatively inexpensive way of maintaining physical fitness. Most modern treadmills have a readout on their console that will track your speed over time in kilometers per hour or miles per hour. If your treadmill came with the wrong setting, it is possible to toggle between these two settings.

Instructions
Things You'll Need

• Pencil

At time 'ZERO', the hat was at distance 'ZERO' from the starting-point.
At time 'T', the hat was at distance 'ONE MILE' from the starting point.
The speed of the boat was the MAXIMUM speed of the boat, MINUS the speed of the current.
At time 'T+5', the hat was being carried by the stream-current toward distance 'ZERO'.
At time 'T+10', the hat was at distance 'ZERO', and the boat was at distance 'ZERO'.
The speed of the boat for the most-recent '10' minutes was the MAXIMUM speed, PLUS the speed of the current.

So, calculate the distance travelled at the 'T+5' time:
DISTANCE = VELOCITY1 multiplied by TIME1.
DISTANCE = VELOCITY2 multiplied by TIME2.

where 'VELOCITY1' is the speed travelling AGAINST the current,
and 'VELOCITY2' is the speed travelling WITH the current.

Finish this "homework" assignment on your own.

You should be able to travel a couple of miles and return on a full charge. Of course the slower speed you select to use when you travel will increase the distance some. Hope this helps

There are five trip computer displays which may be stepped through by pushing the MODE button. The information will appear in the following order:

D AVG ECON (Average Fuel Economy): This shows the average fuel economy since the last reset.

D INST ECON (Instantaneous Fuel Economy): This shows fuel economy for the most recent second of driving.

D RANGE (Trip Range): This shows the estimated distance that can be traveled with the remaining fuel. The fuel economy used to calculate range is based on the last few hours of driving. When in a low fuel condition, LO is displayed.

D FUEL USED (Trip Fuel Used): This shows the accumulated fuel used since the last reset.

D AVG SPEED (Average Speed): This shows the average speed since the last reset.

You can download a replacement Owner's Manual here: 2002 Chevrolet Impala Owner's Manual (PDF file from www.gmownercenter.com)

The stopping distance is proportional to square of speed.

that is 90ft proportional to 40^2 mph.

We can write as 90 = X * 40^2. ( X is a constant of proportionality) .

Which implies X = 90 / 1600 = .05625.

Assume S be the distance at which car stops when the speed is 90 mph.

S = X * 90^2. ( since X does not vary as same car is used)

=> S =.05625 * 8100 = 455.625 ft.

Thank you.

Sorry you may need to repost this question, perhaps you mean chain?

A power band is an area on a graph of power v rpm where the engine produces its best power for the engine speed. it is not a physical object.

There is nothing you can do about that I am afraid.

1.2 Km is only 72 seconds of travel at 100Kph

For most domestic GPS the faster you travel the more there may be a small time delay beween between where the gps thinks you are in relationship to where you really are.