CAN I USE THE AMP FOR TWO 12" KICKER CVT SUBS SINGLE COIL

Are the subs single voice coil? 4 ohm? I'm guessing the amp is 2 channel?

disconnect the amp and do a "pop" test with a 9v battery, it should be clear and no rattle... if it rattles sub is blown

im guessing both speakers are 4 ohms ..mtx 4ohms and kicker dual 4ohms..now if your amp can go down to 1 ohm wiring the kicker dual coils in parallel (2ohms) and the mtx connected together (4ohms) should leave you with a final impedance between 1 and 2 ohms ...i suggest you use one or get another

I have Ref-1000s with two Pioneer TS-W1200C 4-ohm subs bridged in series. So it is 8-ohm mono load, easy for an amplifier, long durability, less heating, low current consumption. I have heard that this amp might break if used with low impedance loads.

how should i wire my s12 L7 2 ohm dual voice coil to my JL 500/1 amp

You have a 2 ohm stable amp, and dual voice coil subs.. The L7's come in both Dual 4 ohm, and Dual 2 ohm, so you have to know what impedance your coils are prior to wiring. HERE is a nifty little guide that will show you how to wire your subs. DO NOT WIRE THE SUBS LOWER THAN 2 OHMS ON YOUR AMPLIFIER!

Hello brysonford00,

The wiring configuration depends on what final impedance you want the amp to see. If the subs are 4ohm DVC's, you can wire them to present a 2ohm impedance or an 8ohm impedance. The diagrams are here. If your subs are 2ohm DVC's, the wiring is the same. The impedances will be 1ohm and 4ohms.

Hope this helps.

Hello solo7908,

With a single 4ohm DVC sub there are only two possible wiring solutions, parallel the voice coils for a final 2ohm load or series the voice coils for an 8ohm load. In your case, you want to wire them in parallel, both positives and both negatives connected to the amp terminals.

Here are the diagrams: (-) to (-) and then to the amp - (+) to (+) and then to the amp. Impedance = 2ohms.

Hope this helps.

that is 2 12 hitting 150 db you got to know what you are doing

Ok.. Bridge the two sub into 4ohm than bridge to amp.


So. this how it goes.

sub1 + -
to      | |
sub2 - +
=      4ohm
       

           From Sub
                Two
            -          +  
            |           |
amp (L) - + (R)- +


This will use the full potiental of RF 800a2 amp. I believe it like 1153 watts max out.