Question about Curtis-Mathis CM25011 25" TV

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9x=5y+25

Posted on Feb 22, 2009

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X = one number

x + 5 = other number

2x + x + 5 = 26

3x = 21

x = 7

x + 5 = 12

Posted on May 27, 2008

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-3x+7y=-1 and -2x+5y=0

Posted on May 06, 2008

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Posted on Jan 02, 2017

With algebra you are learning problem solving-that is the process of problem solving using rules and equations. The best way to learn it is to shut out all distraction and work at it. If there is something you don't understand you may have to go back to the beginning and learn all the principals and rules that you don't understand- Algebra can be a very hard subject but it can be concord with persistence.

Sep 28, 2013 | Office Equipment & Supplies

if ur using pcl driver try with ps driver other wise make it pdf and try to print

Dec 09, 2012 | HP LaserJet 1200 Printer

Assume this:

A is the greater number

B is the lesser

You have 2 equations

A + B = 20

A = 3xB - 4

Substitute the solution for the second eqation into the first

(3xB - 4 ) + B = 20

solve for B

3xB + B = 20 + 4

4xB = 24

B = 6

solve for A with solution for B

go back to equation 2

A = 3xB - 4

A = 3x6 - 4

A = 14

So A = 14

and B = 6

Otherwise use trial and error.

Hope that helps.

A is the greater number

B is the lesser

You have 2 equations

A + B = 20

A = 3xB - 4

Substitute the solution for the second eqation into the first

(3xB - 4 ) + B = 20

solve for B

3xB + B = 20 + 4

4xB = 24

B = 6

solve for A with solution for B

go back to equation 2

A = 3xB - 4

A = 3x6 - 4

A = 14

So A = 14

and B = 6

Otherwise use trial and error.

Hope that helps.

Jun 29, 2011 | HP 12c Calculator

The hardest part of a word problem is translating it into the equation or equations you need. This one needs just one equation.

Let N = the smallest number. Since they are consecutive, the next ones will be N+2 and N+4. (It doesn't matter that they are odd, just that each one is 2 greater than the one before.)

So, N = the smallest number and N+4 = the largest. Translate the problem (3 times the smallest, N, decreased by 7, equals twice the largest, N+4) into numbers:

3N - 7 = 2 (N+4)

Then it's simple to find N:

3N - 7 = 2N +8

3N - 2N = 8 + 7

N = 15

The three numbers then are 15, 17, 19. Check the answer by seeing if they fit the original problem. 3 X 15 = 45, 45 - 7 = 38, 2 X 19 = 38, so we got the right values.

Let N = the smallest number. Since they are consecutive, the next ones will be N+2 and N+4. (It doesn't matter that they are odd, just that each one is 2 greater than the one before.)

So, N = the smallest number and N+4 = the largest. Translate the problem (3 times the smallest, N, decreased by 7, equals twice the largest, N+4) into numbers:

3N - 7 = 2 (N+4)

Then it's simple to find N:

3N - 7 = 2N +8

3N - 2N = 8 + 7

N = 15

The three numbers then are 15, 17, 19. Check the answer by seeing if they fit the original problem. 3 X 15 = 45, 45 - 7 = 38, 2 X 19 = 38, so we got the right values.

Mar 06, 2011 | Office Equipment & Supplies

This calculator cannot handle matrices that have anyone dimension larger than 3.

How to solve your problem?

use a computer program devoted to solving linear equations

OR buy another calculator that can handle larger systems of equations (a graphing calculator, maybe).

How to solve your problem?

- Set up the problem by hand (pencil paper): use Cramer's rules. Make use of the calculator to perform the various calculation.

- Sacrifice one equation which you will use to eliminate one variable of the 4 by expressing it in terms of the other three. Do the algebra to obtain a system of 3 equations in three unknowns.
- Use the calculator to find the solutions ( the three variables that are left).
- Use the 4th equation (the one you scacrificed) to obtain the value of the 4th unknown.

use a computer program devoted to solving linear equations

OR buy another calculator that can handle larger systems of equations (a graphing calculator, maybe).

Feb 16, 2011 | Casio FX-115ES Scientific Calculator

1st equation:

11=6+a

Everything the you do to one side of the equals sign in an equation, you have to do to the other. So let's subtract 6:

5=a

------

The second equation:

a+7=10+b

Now we know from the first equation that a= 5, so let's put that in:

5+7=10+b

Or, simplifying:

12=10+b

Let's take away 10 from both sides:

2=b

So your answer is: b=2

11=6+a

Everything the you do to one side of the equals sign in an equation, you have to do to the other. So let's subtract 6:

5=a

------

The second equation:

a+7=10+b

Now we know from the first equation that a= 5, so let's put that in:

5+7=10+b

Or, simplifying:

12=10+b

Let's take away 10 from both sides:

2=b

So your answer is: b=2

Apr 04, 2010 | Vivendi ADI English and Maths Year 5 Full...

The best way to solve this is to develop one or more equations and then solve for the unknown numbers.

I solved this problem twice using different sets of equations to make sure I was right, and here is what I found:

1) I used the equations x + y = 623, and x = (2/3)y. In these equations, x is the number of girls and y is the number of boys.

Substituting the second equation into the first, I get (2/3)y + y = 623.

Adding the left side together I get : (5/3)y = 623.

Dividing both sides by (5/3) I get 373.8.

This means that x (the number of girls) is 249.2.

2) For the second attempt, I developed the equation: 2x+3x=623. Here 2x is the number of girls, and 3x is the number of boys.

Adding the left side I get: 5x = 623.

Dividing both sides by 5 I get: x = 124.6.

This means that the number of girls (2x) is 249.2. Just like in the first method.

But since you can't have a 1/5 of a girl, the answer must be 249 girls.

I solved this problem twice using different sets of equations to make sure I was right, and here is what I found:

1) I used the equations x + y = 623, and x = (2/3)y. In these equations, x is the number of girls and y is the number of boys.

Substituting the second equation into the first, I get (2/3)y + y = 623.

Adding the left side together I get : (5/3)y = 623.

Dividing both sides by (5/3) I get 373.8.

This means that x (the number of girls) is 249.2.

2) For the second attempt, I developed the equation: 2x+3x=623. Here 2x is the number of girls, and 3x is the number of boys.

Adding the left side I get: 5x = 623.

Dividing both sides by 5 I get: x = 124.6.

This means that the number of girls (2x) is 249.2. Just like in the first method.

But since you can't have a 1/5 of a girl, the answer must be 249 girls.

Nov 19, 2009 | Office Equipment & Supplies

Hello,

I do not understand what you mean by solve complex equations, but if you want to manipulate complex numbers here are the tools you need to enter your complex numbers. Operations and function evaluations do not need special symbols.

Hope it helps.

I do not understand what you mean by solve complex equations, but if you want to manipulate complex numbers here are the tools you need to enter your complex numbers. Operations and function evaluations do not need special symbols.

Hope it helps.

Oct 31, 2008 | Casio FX-9860G Graphic Calculator

This question is strangely worded and does not pertain to floppy drives. However, taking all information here as given and sufficient enough to form the equations, you arrive at the following:

X=Y+60

60(3.25) = 195 One tenant must pay $195 more for his extra 60square ft.

(975-195)/2=390 The remaining rent (assuming the given info is all that is needed to solve)

390/3.25=120 is divided between the two and represents the rent of the smaller bedroom.

y=120 sq ft The rent of the smaller room holder is divided by $3.25 to reach the sq ft.

so,

x=180 sq ft

X=Y+60

60(3.25) = 195 One tenant must pay $195 more for his extra 60square ft.

(975-195)/2=390 The remaining rent (assuming the given info is all that is needed to solve)

390/3.25=120 is divided between the two and represents the rent of the smaller bedroom.

y=120 sq ft The rent of the smaller room holder is divided by $3.25 to reach the sq ft.

so,

x=180 sq ft

Sep 17, 2008 | Computers & Internet

x=7 Therefore, first is 7, second is 35

I like numbers but as I get older, they get harder!

I like numbers but as I get older, they get harder!

Jun 30, 2008 | Computers & Internet

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