Question about Bagatrix Algebra Solved! 2005 (105101) for PC

This has to be solved using binomial theorem

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Try this... here we represent 1.01 as 1+.01

and so we have nCr and stuff... it can be noted that a number lesser than .01 when raised to power will result in a number lesser than it and hence the first term which is 1^1000000 will be greatest among the terms... so it can never be greater than 10000

Posted on Jan 31, 2008

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I am sorry to come in like that (5 years after the question was asked) and spoil your fun.

If you try to enter it on a regular calculator you will get an overflow error, memory error or some such thing. On the Windows calculator here is what I get.

2.3647358888701483369966440045217x10^(4321)

Posted on Mar 01, 2013

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Posted on Jan 02, 2017

Use the quadratic formula, or factor the quadratic polynomial. Once factored into a product of two first degree binomials, the roots are obtained by setting (in TURN) each binomial factor equal to zero.

May 02, 2014 | Casio fx-300ES Calculator

I worked out the algebra leaving out a few simple steps (special binomial products, Pythagorean theorem in trigonometry, definition of secant and co-secant functions). I am inserting the answer as a set of png pictures. However I am not sure how it will look.

Sep 21, 2013 | ValuSoft Bible Collection (10281) for PC

You have to type expand((38x-28y)^4,x). See captured images

Jan 04, 2012 | Texas Instruments TI-89 Calculator

In mathematics, **special products** are of the form:

(a+b)(a-b) = a2 - b2 (Product of sum and difference of two terms) which can be used to quickly solve multiplication such as:

301 * 299 = (300 +1)(300-1) = 3002 - 12 = 90000 - 1 = 89999__types__

1. Square of a binomial

(a+b)^2 = a^2 + 2ab + b^2

carry the signs as you solve

2. Square of a Trinomial

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc

carry the sings as you solve

3. Cube of a Binomial

(a+b)^3 = a^3 + 3(a^2)b + 3a(b^2) + b^3

4. Product of sum and difference

(a+b)(a-b) = a^2 - b^2

5. Product of a binomial and a special multinomial

(a+b)(a^2 - ab + b^2) = a^3-b^3

(a-b)(a^2 + ab + b^2) = a^3-b^3

(a+b)(a-b) = a2 - b2 (Product of sum and difference of two terms) which can be used to quickly solve multiplication such as:

301 * 299 = (300 +1)(300-1) = 3002 - 12 = 90000 - 1 = 89999

(a+b)^2 = a^2 + 2ab + b^2

carry the signs as you solve

2. Square of a Trinomial

(a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc

carry the sings as you solve

3. Cube of a Binomial

(a+b)^3 = a^3 + 3(a^2)b + 3a(b^2) + b^3

4. Product of sum and difference

(a+b)(a-b) = a^2 - b^2

5. Product of a binomial and a special multinomial

(a+b)(a^2 - ab + b^2) = a^3-b^3

(a-b)(a^2 + ab + b^2) = a^3-b^3

Jul 28, 2011 | Computers & Internet

But, what if there was a binomial instead of a single term outside of the parentheses? That is, what if a binomial was being multiplied by another binomial? An example of this is given below.

FOIL stands for:

Now we will multiply the outer terms and again mark down the answer below the problem.

And the Inners.

And finally the last terms.

Jun 12, 2011 | Computers & Internet

Pierre de Fermat died in 1665. Today we think of Fermat
as a number theorist, in fact as perhaps the most famous number
theorist who ever lived. It is therefore surprising to find that Fermat
was in fact a lawyer and only an amateur mathematician. Also surprising
is the fact that he published only one mathematical paper in his life,
and that was an anonymous article written as an appendix to a
colleague's book.

Because Fermat refused to publish his work, his friends feared that it would soon be forgotten unless something was done about it. His son, Samuel undertook the task of collecting Fermat's letters and other mathematical papers, comments written in books, etc. with the object of publishing his father's mathematical ideas. In this way the famous 'Last theorem' came to be published. It was found by Samuel written as a marginal note in his father's copy of Diophantus's*Arithmetica*.

Because Fermat refused to publish his work, his friends feared that it would soon be forgotten unless something was done about it. His son, Samuel undertook the task of collecting Fermat's letters and other mathematical papers, comments written in books, etc. with the object of publishing his father's mathematical ideas. In this way the famous 'Last theorem' came to be published. It was found by Samuel written as a marginal note in his father's copy of Diophantus's

Fermat's Last Theorem states that

*x**n* + *y**n* = *z**n*

has no non-zero integer solutions for *x*, *y* and *z* when *n* > 2.

In number theory, **Fermat's Last Theorem** states that no three positive integers *a*, *b*, and *c* can satisfy the equation *a**n* + *b**n* = *c**n* for any integer value of *n* greater than two.

Mar 04, 2011 | MathRescue Word Problems Of Algebra Lite

how to solve the problem for binomial theorem (1.08)8

Feb 24, 2011 | Texas Instruments TI-92 Plus Calculator

Using elementary algebria in the **binomial theorem, **I expanded the power **(***x* + *y*)^n into a sum involving terms in the form a x^b y^c. The coefficient of each term is a positive integer, and the sum of the exponents of *x* and *y* in each term is **n**. This is known as binomial coefficients and are none other than combinatorial numbers.

**Combinatorial interpretation:**

Using** binomial coefficient (n over k)** allowed me to choose** ***k* elements from an **n**-element set. This you will see in my calculations on my Ti 89. This also allowed me to use **(x+y)^n** to rewrite as a product. Then I was able to combine like terms to solve for the solution as shown below.

(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

**This also follows Newton's generalized binomial theorem:**

**Now to solve using the Ti 89.**

Using

(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

**Using sigma notation, and factorials for the combinatorial numbers, here is the binomial theorem:**

**The summation sign is the general term. Each term in the sum will look like that as you will see on my calculator display. Tthe first term having k = 0; then k = 1, k = 2, and so on, up to k = n. **

Jan 04, 2011 | Texas Instruments TI-89 Calculator

This may help:

http://en.wikipedia.org/wiki/Binomial_theorem

Rate me, thanks.

http://en.wikipedia.org/wiki/Binomial_theorem

Rate me, thanks.

Jun 19, 2009 | Texas Instruments TI-89 Calculator

=IF**(**K>50,(IF(K>66,A*300,A*200),10000)**)**

Feb 24, 2009 | Microsoft EXCEL 2004 for Mac

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

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