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Can not find site to log on for e-learning - Computers & Internet

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Mohammed Jamal

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Posted on Jun 05, 2017


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I'am having problem longing into my facebook

First, I'm not a facebook representative.
* This is from their site;
I can't log in.
shareShare Article If you're having trouble logging into your Facebook account, here are some things you can try.

Try recovering your Facebook account
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If your password isn't working or you don't remember your password:
Try resetting your password.

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Aloha, ukeboy57

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Log4 (x+1) + log4 (x-2) =1

This is not a calculator problem. Use the rules you have learned to simplify your problem.
For a a log in any base. log(a*b) =log(a) +log(b) or log(a)+log(b) =log(a*b).
log(x+1)+log(x-2)= log[(x+1)*(x-2)]=1
Use the fact that log4=log in base 4 and rewrite the equation with the appropriate symbols. log4[(x+1)*(x-2)] =1
However 1=log4(4) and
The equality of the two logs implies the equality of their arguments (contents) and

(x+1)*(x-2) =4

Now you solve this quadratic equation by the methods you must have learned (sorry I have to leave some thing for you to do, to ensure that proper learning is achieved).
Once you find the roots of the quadratic equation, verify that each term in your original expression has meaning-- x+1 positive and x-2 positive.

If one of the roots makes the argument (x+1) or (x-2) negative, reject it. because the argument of a log function cannot be negative.

Dec 14, 2009 | Casio FX-300MS Calculator

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