We are given the following data:
length = 5/2 * width
length = 10 inWe know through the transitive
property of equality that the following must be true:
5/2 * width = 10 in
We then solve this equation algebraically for width:
width = (10 in) * 2/5
width = 4 in
The perimeter of the rectangle is given by substituting our known values of length and width into the following general equation:
Perimeter = 2 * length + 2 * width
Perimeter = 2(10 in) + 2(4 in) = 28 in
In a similar fashion, we substitute these known values into the general equation for the area of the rectangle to solve for the same:
Area = length * width
Area = (10 in)(4 in)=40 in^2
SOURCE: the perimeter of a rectangular
a rectangular window is 57.7 cm by 68.5 cm.what is the perimeter of the window?
SOURCE: a rectan Dear Madam Please look at the math
1. Well this one is pretty simple. Since you are not supposed to trim the length trim the width instead.
to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.
2. let the length of rectangle be x cm
and breadth = 20 cm
now original perimeter = 2(x+20) cm
new length = x-30 cm
breadth remains same = 20 cm
new perimeter = 2(x-30+20) cm = 2(x-10) cm
According to question
new perimeter = old perimeter /2
2(x-10) = 2(x+20) /2
2x -20 = x + 20
x = 40 cm
hence length of longer side 40 cm.
If you want to directly comm [email protected]
SOURCE: surface area of a rectangular prism whose length
Since the 'base' and 'top' of any prism have the same shape, the surface area can be found by
So for the rectangular prism in your example..
Hope this helps
Area =Length*width =L*W=660
Length=L=-14 +2*W
(2W-14)*W=660
2W^2-14W=660 Quadratic equation
Simplify by 2
W^2-7W-330=0
Factor the left hand side or use the quadratic formula
Factoring
W^2-7W-330=(W+15)(W-22)=0
A product is =0 if any of its factors is = 0
Thus you can have
W+15 =0 -------> W=-15 Discard it : a length cannot be negative
W-22=0 ---------> W= 22
Length L= -14 +2*22=44-14=30 yd
Check: area = 30*22 = 660 yd^2
Checks OK
L=22 yds
10 inches. This assumes the enlargement magnified equally in both directions.
If this is homework, be sure to show your work.
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