The sides of a triangle are in the ratio 3 4 5 of the longest side of the triangle measures 40 cm what is the perimeter of the triangle?

you need at least 2 measurement or 2 angles

Find the scaling ratio
Perimeter of first pentagon is 12*5=60 cm
Scale factor (2nd/first)=140/60 =7/3
Ratio of areas varies as the square of the scale factor for the lengths
Area of second / area of first =(7/3)^2 =49/9
Area of second pentagon =248 *(49/9) cm^2
Finish the calculation.

Using the Pythagorean Theorem in one of the corner triangles you get
y^2=2*(x/2)^2
Thus, y=(SQRT( 2))*(x/2)
The ratio of the perimeters is equal to the ratio of the sides
P2/P1=y/x=SQRT(2)/2=1/SQRT(2)

The two pentagons are similar. If k is the scale factor for the lengths, the ratio of the areas is k^2.
Pent 1 side =12 cm
Pent 2 side =140/5 =28 cm
Scale factor (larger over smaller) is k=28/12=7/3
Area of Pent_2= (49/9)*Area of Pent_1
Your answer should be C.

About 3420 square centimeters.

If this is homework, be sure to show your work.

1. Well this one is pretty simple. Since you are not supposed to trim the length trim the width instead.
to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.



2. let the length of rectangle be x cm
and breadth = 20 cm
now original perimeter = 2(x+20) cm


new length = x-30 cm
breadth remains same = 20 cm
new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2
2(x-10) = 2(x+20) /2
2x -20 = x + 20
x = 40 cm


hence length of longer side 40 cm.

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1. the ratio of there height is 3:2
2. the ratio of areas of the triangle is: 125:6561
3. the perimeter of smaller parallelogram is: 40 cm2
4. THe real length of the object is 7 cm

9 cm

If the distance is 2 cm longer than the short side of a right triangle then the lengths could then be assumed as:
Right triangle A/B = 3 cm
A/C = 1 cm
B/C = 3 cm