Question about Exercise & Fitness

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Hi there, a lightyear is a measure of distance- how far does light travel in a year. Light travels at about 300,000 km/sec.

Jan 22, 2018 | Cars & Trucks

You travel the distance between the friend's house and your home which is stated to be 3 miles.

Nov 05, 2015 | Cars & Trucks

Since the Earth and Jupiter are both revolving around the sun, the distance between them is always changing. The average distance between the Earth and Jupiter is 483 million miles. If you could travel at the speed of light, it would only take you 43 minutes to get to Jupiter. Since people cant travel at the speed of light, you would probably have to take a rocket ship to Jupiter instead- which would take you about 2.2 years if it was going at top speed the whole way. If the California interstate went all the way to Jupiter and you could drive there going 65 mph, it would take you almost 850 years!

Feb 23, 2015 | Computers & Internet

Anti freeze changing is usually based on distance traveled and depends on the quality of the product used some could be every 10,000 Km,s roughly 6500 miles roughly or 60,000 kms around 40,000 miles roughly . Good Luck John

Oct 12, 2012 | 2000 Toyota Avalon

Dear Sir:_

I will try to help you.

Please check this:

I will try to help you.

Please check this:

It is simple to change your treadmill so it reads MPH.

Treadmills are an easy and relatively inexpensive way of maintaining physical fitness. Most modern treadmills have a readout on their console that will track your speed over time in kilometers per hour or miles per hour. If your treadmill came with the wrong setting, it is possible to toggle between these two settings.

Instructions

Things You'll Need

- Pencil

Oct 19, 2011 | Weslo Cadence 55 Treadmill

In two hours the first car will have traveled 110 miles. The second car closes the distance by 20 miles every hour, so it will need 5.5 hours to close the 110 miles.

Jun 26, 2011 | Texas Instruments TI-89 Calculator

At time 'ZERO', the hat was at distance 'ZERO' from the starting-point.

At time 'T', the hat was at distance 'ONE MILE' from the starting point.

The speed of the boat was the MAXIMUM speed of the boat, MINUS the speed of the current.

At time 'T+5', the hat was being carried by the stream-current toward distance 'ZERO'.

At time 'T+10', the hat was at distance 'ZERO', and the boat was at distance 'ZERO'.

The speed of the boat for the most-recent '10' minutes was the MAXIMUM speed, PLUS the speed of the current.

So, calculate the distance travelled at the 'T+5' time:

DISTANCE = VELOCITY1 multiplied by TIME1.

DISTANCE = VELOCITY2 multiplied by TIME2.

where 'VELOCITY1' is the speed travelling AGAINST the current,

and 'VELOCITY2' is the speed travelling WITH the current.

Finish this "homework" assignment on your own.

At time 'T', the hat was at distance 'ONE MILE' from the starting point.

The speed of the boat was the MAXIMUM speed of the boat, MINUS the speed of the current.

At time 'T+5', the hat was being carried by the stream-current toward distance 'ZERO'.

At time 'T+10', the hat was at distance 'ZERO', and the boat was at distance 'ZERO'.

The speed of the boat for the most-recent '10' minutes was the MAXIMUM speed, PLUS the speed of the current.

So, calculate the distance travelled at the 'T+5' time:

DISTANCE = VELOCITY1 multiplied by TIME1.

DISTANCE = VELOCITY2 multiplied by TIME2.

where 'VELOCITY1' is the speed travelling AGAINST the current,

and 'VELOCITY2' is the speed travelling WITH the current.

Finish this "homework" assignment on your own.

Jan 27, 2011 | Computers & Internet

The stopping distance is proportional to square of speed.

that is 90ft proportional to 40^2 mph.

We can write as 90 = X * 40^2. ( X is a constant of proportionality) .

Which implies X = 90 / 1600 = .05625.

Assume S be the distance at which car stops when the speed is 90 mph.

S = X * 90^2. ( since X does not vary as same car is used)

=> S =.05625 * 8100 = 455.625 ft.

Thank you.

that is 90ft proportional to 40^2 mph.

We can write as 90 = X * 40^2. ( X is a constant of proportionality) .

Which implies X = 90 / 1600 = .05625.

Assume S be the distance at which car stops when the speed is 90 mph.

S = X * 90^2. ( since X does not vary as same car is used)

=> S =.05625 * 8100 = 455.625 ft.

Thank you.

Jun 12, 2010 | Bagatrix College Algebra Solved Full...

If the gears have been INCREASED the speed etc will be less.

Say it's increased by 18%.In theory,at 100mph real speed, the speedo will read 18%less.i.e. 82mph.

If the speedo is driven off the g/box,all this has to be taken into account.

If the speedo is driven off the wheels(and the wheels have not changed at all)All that will happen is the engine revs will have decreased by 18%.

So,To work out the difference.Divide the distance travelled by 100 and then multiply the answer by 82.(82 is the remaining % of the original)

So if 150 miles is divided by 100=1.5

1.5 is multiplied by 82=123 miles.

Hope this helps

Say it's increased by 18%.In theory,at 100mph real speed, the speedo will read 18%less.i.e. 82mph.

If the speedo is driven off the g/box,all this has to be taken into account.

If the speedo is driven off the wheels(and the wheels have not changed at all)All that will happen is the engine revs will have decreased by 18%.

So,To work out the difference.Divide the distance travelled by 100 and then multiply the answer by 82.(82 is the remaining % of the original)

So if 150 miles is divided by 100=1.5

1.5 is multiplied by 82=123 miles.

Hope this helps

May 11, 2010 | 2003 Jeep Wrangler

12x60=720 meters in one minute the distance traved is 720 meters in one minute so in four minutes the vechilce has travled 720x4 minutes =2880 meters in four minutes.

Aug 26, 2009 | 1998 Dodge Ram 1500 4WD

Oct 31, 2019 | Life Fitness 95ti Treadmill

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