Question about Casio FX-300MS Calculator

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You can go to https://www.omnicalculator.com/math/circumference and calculate.

Anyway:

The diameter is the length of the line through the center that touches two points on the edge of the circle.

Anyway:

The diameter is the length of the line through the center that touches two points on the edge of the circle.

Aug 27, 2017 | The Computers & Internet

Circumference Calculator

If the circumference is 2, then the diameter is 0.63662 of whatever unit of measure of length is applied.

If the circumference is 2, then the diameter is 0.63662 of whatever unit of measure of length is applied.

Aug 22, 2017 | The Computers & Internet

circumference is pye times twice the radius or by the diameter

3.1417 X 6 ( diameter or 2 times the radius )= 18.8496

90 degrees is 1/4 of the circumference

18.8496 divided by 4 = 4.7124 cms

arc of 90 degrees =4.74124 cms

3.1417 X 6 ( diameter or 2 times the radius )= 18.8496

90 degrees is 1/4 of the circumference

18.8496 divided by 4 = 4.7124 cms

arc of 90 degrees =4.74124 cms

May 02, 2017 | The Computers & Internet

If you would like to know the circumference of a 15" diameter circle this is the formula:

circumference = radius x 2 x pi

circumference = diameter x pi

in our case:

circumference = 15" x 3,14

circumference = 47 ,1" (that's 119,634 cm)

circumference = radius x 2 x pi

circumference = diameter x pi

in our case:

circumference = 15" x 3,14

circumference = 47 ,1" (that's 119,634 cm)

May 06, 2014 | Cars & Trucks

In which language? This is really more a mathematical problem than a programming/compilation one. Try walking the circumference of the circle, testing for a point along each of the triangle's segments. If only one such point can be found, or a series of consecutive points (since software "circles" are never true circles, they're made up of short straight segments), then you have a tangent.

You can save a lot of time and math by making coarse estimates first - for example, don't bother testing for tangentiality for any circumferential segment that's fully above, to the left or right of, or below, all three points of the triangle - you CANNOT have a tangent in those areas.

An alternate approach is... walk the triangle instead of walking the circle. Test for a single circle crossing point. Again, you can save time by checking each segment first, and walking only segments that actually cross the circle's circumference. If no part of the circle can be found mathematically between any pair of vertices, then discard that segment outright.

You can save a lot of time and math by making coarse estimates first - for example, don't bother testing for tangentiality for any circumferential segment that's fully above, to the left or right of, or below, all three points of the triangle - you CANNOT have a tangent in those areas.

An alternate approach is... walk the triangle instead of walking the circle. Test for a single circle crossing point. Again, you can save time by checking each segment first, and walking only segments that actually cross the circle's circumference. If no part of the circle can be found mathematically between any pair of vertices, then discard that segment outright.

Mar 10, 2014 | Computers & Internet

About 146 and a half degrees.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Oct 22, 2013 | Office Equipment & Supplies

You can not do it unless you know the measure of the central angle sustending (supporting) the arc. If the angle is known, you use the proportionality relation that follows:

If angle is in degrees

(length of arc) / circumference=(measure of central angle sustending arc)/360.

Here the circumference is 2*PI*radius.

If angle is in radians , the relation is somewhat simpler,

**arc length= (radius length)* (angle measure in radians)**

It is clear that in the last relation, the unit for the arc length is the same as the unit for the radius.

If angle is in degrees

(length of arc) / circumference=(measure of central angle sustending arc)/360.

Here the circumference is 2*PI*radius.

If angle is in radians , the relation is somewhat simpler,

It is clear that in the last relation, the unit for the arc length is the same as the unit for the radius.

Jul 15, 2011 | Casio FX-300MS Calculator

If an arc is 4╥, it is 12.56.

You can use 12.56 as a starting point and figure out what circumference that is 40° of.

Circumference = 2 • π • radius = π • diameter

Reverse this and you will have your answer.

You can use 12.56 as a starting point and figure out what circumference that is 40° of.

Circumference = 2 • π • radius = π • diameter

Reverse this and you will have your answer.

Oct 12, 2009 | Computers & Internet

Hi,

The arc length can be obtained by:

(pi x r x Angle) / 180

or

(3.1415 x 5 x 30) / 180 = 2.618 in.

Hope this helps...

The arc length can be obtained by:

(pi x r x Angle) / 180

or

(3.1415 x 5 x 30) / 180 = 2.618 in.

Hope this helps...

Sep 15, 2009 | Vivendi Math Blaster Geometry for PC, Mac

A classic. This is one of Zeno's Paradoxes.

Sep 13, 2008 | Casio FX-115ES Scientific Calculator

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