The simple answer is not many. I don't think your pump is that hungry to use kilowattS per hour... lets see "Kilo" is one thousand. At this
site you will find the several formula for getting to your answer. Ohm's Law applies ... http://www.powerstream.com/Amps-Watts.htm
I am presuming your pump is 115 Volts and it probably plugs into a 15 amp circuit. IF IT USES 15 amps (I doubt it uses the entire value) Volts X Amps = Watts or 1725 watts or about 1.7 kilowatt. I couldn't find the amp rating for your particular model pump. I think it probably operates near 6 to 8 amps @ 115 Volts AC. If your pump runs at 6 amps that is 690 watts, 8 is 920 and 10 would be 1150. There are other factors that determine the actual amount of power consumed - load will increase the use - partially clogged filter would be an example of increased load, age of the pump could be another factor.
Here is another nifty place to convert: http://www.supercircuits.com/resources/tools/Volts-Watts-Amps-Converter
Here is a rule of thumb: If a device can run on two different voltages, the higher the voltage, the lower the amps. For example 115 volt @ 12 amps would use 1380 watts. The same device running at 230 volts would run at 6 amps and use 1380. This is the correct math answer. However, in actual use, the device would run slightly more efficient (use fewer watts). Electricians and science teachers and math teachers will all tell you different stories depending
on their discipline. Heavy
use devices do run more efficiently at the higher voltage (stove, dryer, furnace, hot water heater, well water pumps, swimming pool pumps)(Do not go looking for a 220 Volt pump for your above ground pool in an effort to save money. The higher voltage device will cost more and there are other practical and safety related issues in this kind of installation.)
If you lived in my area, (please don't say where you live) you would pay about 12 cents (US dollars) per kilowatt hour. If your pump runs at 10 amps 115 volts - that
would be just over 12 cents per hour to run the pump.
I trust this answers your question? Thank you for your interest in FixYa