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Anonymous Posted on Feb 06, 2014

Inverse sine function - Texas Instruments TI 30XIIS Scientific Calculator

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kakima

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  • Texas Instru... Master 102,366 Answers
  • Posted on Jun 13, 2014
kakima
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Press 2nd SIN

For example, to calculate the inverse sine of 0.5, press 2nd SIN . 5 =

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0helpful
1answer

"Undefined" as answer to an inverse sine calculation

I suspect that you are confusing things a bit.
The inverse sine, called the arcsine is a function defined in the closed interval [-1,1]. And so is the inverse cosine. Any value outside this interval will give you a non-real result (meaning a complex one).
There are no limitations on the domain of definition of the inverse hyperbolic sine or sinh^-1
If your input value is allowed to be complex, the arcsine function gives a complex value. See the screen capture

ced983c4-63c8-431d-8104-3d4d5a3200e1.png
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Find inverse sin

The inverse of a function usually shares the same physical key as the direct function.

7b93b129-4193-458b-8c24-18857b33b495.jpg
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My TI-30XB WONT CALCULATE INVERSE COS OR INVERSE SIN

Does it refuse to do so or does it give an error message?
Three common errors:
  1. Not having the correct angle unit. Wrong result, No error message
  2. Confusing reciprocal of sine (1/sin(x) with arc sine (x) ,sin^-1(x). Confusing the reciprocal of cosine, 1/cos(x) with arc cosine (cos^-1(x)). Wrong result, No error message
  3. Taking the argument of the inverse sine and/or inverse cosine functions outside the interval [-1,1]. This gives a domain error.
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1answer

Inverse sine function

The sine and cosine function have a range between [-1, 1]. The domain of their inverse functions is [-1,1]. So 20/1 which is 20 is out of the domain of definition of the functions. No limitations for tangent and cotangent.
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1answer

Hi I am experiencing problem with my Casio 991 MS

The range of the cosine and sine functions is limited to the interval [-1, 1]. As a result the calculator will send an error message if the functions are called with arguments outside the interval [-1, 1]. Aside from this, I do not see any reason why the functions would give an error.
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I'm using the original TI-30 SOL calculator. Is there any way to do inverse sine or cosine?

Of course. Just press the INV key before pressing the appropriate trig function key. For example, to calculate the inverse sine, press INV then sin.
1helpful
1answer

I'm trying to do inverse sine and cosine equations but I'm receiving a message that there is a domain error. Is there anything I can do or press like a reset button?

The inverse sine and cosine equations mean "angle who's sine/cosine is:" The bounds of the arguments for these functions must be between 1 and -1, the maximum and minimum values of the sine and cosine functions, because no angle can have a sine or cosine that is greater than 1 or smaller than -1. Also it should be noted that the inverse sine/cosine function is not the same as 1/sine or 1/cosine, although the symbol makes it look like that.
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I'm trying to do sin-1 7/2 but it keeps saying math error.

That is correct: there is an error in your request. The range of the sine function spans the closed interval [-1, 1]. Thus the domain of the inverse sine function (the arc-sine) is the interval [-1,1]. However you are asking the calculator to calculate outside of the domain (7/2=3.5). If you are using the hyperbolic sine sinh, that is another matter.
12helpful
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How do I find inverse sine, cosine and tangent in degrees

First, make sure the calculator is set to degrees (2nd [FORMAT] down-arrow).

Put in the value, press INV, the appropriate function key, and =.

For example, to find the inverse sine of .3, press
. 3 INV [SIN] =
1helpful
1answer

Ive been doing inverse sine, inverse cosine, and inverse tangent problems for a few hours now but all of a sudden when i put in this one problem it gives me: ERR:DOMAIN. im not sure what is wrong... I've...

Since you are familiar with sines, cosines, you know that their ranges (interval of values) varies from -1 to 1. The inverse functions of sine and cosine tkae their values in that very domain, [-1,1].
However you fed the arc sine function (sin^-1) a vlaue of (25/20.48) and that value is obviously larger outside the [-1,1] domain, hence the DOMAIN error message.

No such domain limitations exist for arc tangent (tan^-1) because the range of the tangent function spans the open interval ]negative infinity to positive infinity[.
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