X^2+13x+22=7 How do I solve this by completing the square??

I set it up in a ratio to solve this.

500 113
----- = -----
x 13

I am assuming 13% tax.

Multiplying both sides by 13x:

(500)(13) = 113x

6500 = 113x

6500 = x
------
113

57.52 = x

Good luck,

Paul

to work out area of a circle you must use area = pi x R^2
Area = pi x Radius squared
Area = 22/7 x 2^2
Area = 88/7
Area = 12.571 metres squared (M with a little 2 next to right corner of M)
pi is 22/7= 3.1428571429 (rounded up) just use 22/7

You can't convert a volume to an area. For example. if everything is stacked 7 feet high then the area would be 484 square feet. If stacked 14 feet high the the area would be 242 square feet.

In SI, about 95.94 cubic meters.

x=-2

If you're asking how to do this on a particular calculator, please specify the make and mode. If this is homework, be sure to show your work.

Just complete the square
x^2-22x-10=x^2-2(x)*11+11^2-11^2-10=(x-11)^2-121-10=(x-11)^2- 131.
Use the identity a^2-b^2=(a-b)(a+b) with a=(x-11) and b= square root (131)
Solutions are x1= 11 + square root (131) and x2=11-square root (131).
By the way, the calculator you are refer to cannot perform symbolic algebra calculations.

Use the quadratic formula or completing the square.
Completing the square:
x^2 -13x=-36
x^2-2*(13/2) +(13/2)^2=-36+(13/2)^2
The left side can be factored as (x-13/2)^2.
The right side is (13^2-36*4)/4=(169-144)/4=25/4
Assembling the two sides
(x-13/2)^2=25/4
Taking the square roots x-13/2=+ or - 5/2
Case 1 : x-13/2=+ 5/2.
Solving for x you get the first root as x=(5+13)/2=18/2=9

Case 2 : x-13/2=-5/2.
Solving for x, you get the other root as x=(13-5)/2=8/2=4.
The roots are x1=9, and x2=4

If we assume the width of the frame is X. Then the one dimension of the framed picture will be 2X + 20 and the other dimension of the picture will be 2X + 34. We know the total area of the framed picture should be 640 in^2. Therefore:
(2X + 10) * (2X + 34) = 640
If you multiply this out you get:
4X^2 + 88X + 340 = 640
Subtract 640 from both sides:
4X^2 + 88X - 300 = 0
Divide both sides by 4:
X^2 + 22X - 75 = 0
Use the quadratic equation to solve for X, with A=1, B=22, C=75
X = [-22 +/- sqr(22^2-4*(-75)] /2
This reduces to:
(-22 +/- 48) / 2
The negative solution doesn't make sense in this case. Therefore: X = (-22 + 28) /2 = 6/3 = 3

Therefore the width of the frame should be 3 inches.

I'm assumeing the problem is 2x^2 - 19x+22 = 0, solve for x.

I don't see any easy to factor this so I'll either need to complete the square or use the quadratic equation.
Using the quadratic equation, where A = 2, B = -19, and C = 22

x = [-(-19) +/- squareroot( 19^2 - 4*2*22)] / (2*2) =
(19 +/- squareroot(185))/4 =
8.150367 or 1.349632

There are 28 PINS. Count each PIN starting from left to right on each line. (1 to 28 )

Square 1-- Join together PIN No's ( 1 -- 2 -- 6 -- 7 )

Square 2 -- Join " " " " ( 4 -- 12 -- 21 -- 27 )

Square 3 -- Join " " " " ( 5 -- 9 -- 11 -- 15 )

Square 4 -- Join " " " " (3 -- 10 -- 13 -- 19 )

Square 5 -- Join " " " " (8 -- 16 -- 23 -- 28 )

Square 6 -- Join " " " " (14 --18 - 20 -- 25 )

Square 7 -- Join " " " " (17 -- 22 - 24 - 26 )


Hope you can complete this Puzzle now ----------- GOOD LUCK

Not my brilliance I'm afraid, but found the answer on another website, have copied in below - it does work!

It is very complicated to explain but i'll try as best as I can. 1- First make a small square in the top left corner.(This is the only one that isn't at 45 degrees)

2- Next go to the far bottom left corner and make a small 45 degree (lop sided) square leaving only one peg in the middle.

3- Copy the same thing as you did for the 2nd square but this time in the far top right corner.

4- Use the peg that is in the centre of the square in the bottom left corner(2) and draw a line to the peg on the far right at the very bottom. Then draw a line to the middle peg on the far right. Then draw a line to the peg that is on the 2nd row from the top and 3 columns in from the left. Then complete the square connecting up the other side.

5- Start from the peg that is on the very far right that is free and connect it to the peg that is free at the very bottom. Then connect that to the peg that is free on the far left. Then connect it to the peg at the very top (out of the 2 that are free) on the right. Then complete the square.

6- At the very top start at the free peg and connect it to the free peg on the right that is in the centre of the small 45 degree square. Then connect this to the free peg in the centre of 4 other free pegs. Then connect that to the free peg that is furthest to the left and then complete that square.

7- As there are only 4 pegs left this should be easy to see a small 45 degree square. Hope this helps and didn't confuse you too much.