The specifications listed for the transformer are 18 v , 80 va .What is the ampere rating ?

SOURCE: WHISTLE STOPPED WORKING on CW-80

replace the button with a new one just remember which wire goes to which terminal. you will need a soldering iron and electronic solder to do this trick , also make sure you un plug the transformer. by any chance you got any n-scale trains you want to get rid of . If you do send me the info @ [email protected] I'am a disabled veteran with little funds.

Posted on Dec 01, 2008

SOURCE: lionel CW - 80 transformer

Check out this link, I think it will help.

http://www.lionel.com/media/servicedocuments/71-4198-251.pdf

Posted on Jan 20, 2009

SOURCE: Why does my new CW 80 transformer show constant

It sounds like the variable resistor control is faulty or shorted, and supplying voltage all the time. If the unit's new, enforce your warranty or exchange priviledge. This problem shouldn't be happening for a few years.

If, for some reason, your warranty doesn't apply, you'll have to take it apart to figure out what's broken or shorted.

I would contact Lionel, if worse comes to worse- maybe they would send you an exchange.

Here's their support site:

http://www.lionel.com/

Good luck, and hope this helps.

Posted on Nov 18, 2010

SOURCE: Can I use the cw-80 transformer on any Lionel

You should be able to. The Lionel transformers all put out AC power, not DC and many Marx and American Flyer transformers will work too. The real question is total amount of power being drawn and whether or not you have the wattage to match your engine and accessories. With the CW-80 though, it should put out plenty. I run my pre-war 1666E engine pulling a full compliment of metal cars with no problems using a CW-80.

Posted on Feb 10, 2011

SOURCE: how many feet can 1

If you are talking about how many feet of track than your answer is 50. You can get the manual on the link below.

http://www.lionel.com/media/servicedocuments/71-4198-251.pdf

Posted on Feb 19, 2011

0helpful

1answer

You need the total amperes of the refrigerator and multiply by the refrigerator volts to get voltamps, then choose a transformer that is rated at least 120% of the voltamps of the refrigerator. e.g. refrigerator runs at 120 volts and 7.5 amperes, 120 x 7.5 is 900, then 120% of 900 is 1080. A transformer of at least 1080 VA (volt amps) that is 220-240 volts primary and 120 volts secondary. 1080 volt amps is same as 1.08kva (kilo volt amps).

Mar 15, 2015 •
Refrigerators

1helpful

1answer

On the base of the transformer you will find 4 tamper proof screws that you will need to remove to open the case. A triangular blade screwdriver will be need to do this. Once removed the tamper proof screws can be replaced with self tapping screws.

Silverhill Tools ASDTR1 Triangle Screwdriver

Silverhill Tools ASDTR1 Triangle Screwdriver

Jul 16, 2014 •
Lionel Cw 80 Transformer

0helpful

1answer

Hi - I'm an electrician and can help you with your question.

A BR2100 circuit breaker is a 2 Pole 100 Amp (for the part number "BR2100", the "2" indicates the number of poles and the "100" indicates the amperage) circuit breaker. It can be installed in a single phase or three phase 120/240 VAC system panel*that specifically lists the BR series breakers as acceptable for use.*

A BR260 A BR2100 circuit breaker is a 2 Pole 60 Amp (the part number BR260, the "2" indicates the number of poles and the "60" indicates the amperage) circuit breaker. It can be installed in a single phase or three phase 120/240 VAC system panel*that specifically lists the BR series breakers as acceptable for use.*

It is not possible to have a BR2100 rated for 60 amps, 1 or 3 poles, or a BR260 rated for 100 amps, 1 or 3 poles.

*It is not permissible to install any circuit breaker brand or type in any panel that does not specifically include it on a list of acceptable circuit breakers.*

Circuit breakers are designed to carry 80% of the amperage rating.

To**determine the load **a circuit breaker** **can carry, multiply the circuit breaker amp rating by 80%. This means that if you need to supply more than 80 amps, you cannot use a 100 amp circuit breaker. A higher rating is required. A BR2110 would be acceptable for loads greater than 80 amps, but less than 88 amps because the formula above says: 110 amp x 80% = 88 amps.

*To ***determine the breaker size**, *determine the load (by measuring with a meter or obtaining amp rating of the load from the data plate) and multiply it by 125%*. Using the same numbers in the example above; assume an 88 amp load. 88 amps x 125% = 110 amp circuit breaker. The 60 amp breaker is acceptable for up to 48 amps because 60amps x 80% = 48 amps. A 48 amp load needs a 60 amp breaker because 48 amps x 125% = 60 amps.

I hope this helps and good luck!

A BR2100 circuit breaker is a 2 Pole 100 Amp (for the part number "BR2100", the "2" indicates the number of poles and the "100" indicates the amperage) circuit breaker. It can be installed in a single phase or three phase 120/240 VAC system panel

A BR260 A BR2100 circuit breaker is a 2 Pole 60 Amp (the part number BR260, the "2" indicates the number of poles and the "60" indicates the amperage) circuit breaker. It can be installed in a single phase or three phase 120/240 VAC system panel

It is not possible to have a BR2100 rated for 60 amps, 1 or 3 poles, or a BR260 rated for 100 amps, 1 or 3 poles.

Circuit breakers are designed to carry 80% of the amperage rating.

To

I hope this helps and good luck!

Jan 15, 2013 •
Eaton Corporation BR2100 Circuit Breaker

0helpful

1answer

Hi John, I'm an electrician and I think I can help you with this problem.

First and foremost, this switch's 2000VA / 1600W electrical rating is based on a*incandescent* load.

Let's do do the math on this one.. 18 x 50 = 900 watts. So, you're under the 1600 watt capacity, but I think this is a bit more involved than this.

I'd be willing to bet that you're not dimming a 12 volt circuit - but rather a 120 volt circuit that supplies one or more transformers that step the power down from 120 volts to the the 12 volt bulb voltage. A transformer is an*inductive* load. A transformer's inductive load is completely different than the incandescent load the dimmer is designed to control. The transformers are rated for 120 volts and will have issues including heat problems if provided less than the rated input voltage to provide a reduced output voltage you want so that you can dim these lights.

This switch will not work on the output of the transformer in this situation either because the significant amperage being switched here. Each of these lamps draws a bit over 4 amps as determined by ohm's law: 50W / 12V = 4.16A. The total load at 12 volts is (again, Ohm's law) 18 x 4.16A = 74.88A ! That means the wire would need to be a #4 or #2. This is about the size of the cable on your car's battery (only amperage determines conductor size - voltage determines insulation).

A dimmer on this circuit will not work unless the fixtures are changed so that no transformers are used to supply the lamps. This includes fluorescent lamps (compact or otherwise) unless the packaging specifically states that they can be used on a dimmer.

You may wish to contact Lutron Hotline at 800-523-9466 for additional help and suggestions. I hope this helps & good luck!

First and foremost, this switch's 2000VA / 1600W electrical rating is based on a

Let's do do the math on this one.. 18 x 50 = 900 watts. So, you're under the 1600 watt capacity, but I think this is a bit more involved than this.

I'd be willing to bet that you're not dimming a 12 volt circuit - but rather a 120 volt circuit that supplies one or more transformers that step the power down from 120 volts to the the 12 volt bulb voltage. A transformer is an

This switch will not work on the output of the transformer in this situation either because the significant amperage being switched here. Each of these lamps draws a bit over 4 amps as determined by ohm's law: 50W / 12V = 4.16A. The total load at 12 volts is (again, Ohm's law) 18 x 4.16A = 74.88A ! That means the wire would need to be a #4 or #2. This is about the size of the cable on your car's battery (only amperage determines conductor size - voltage determines insulation).

A dimmer on this circuit will not work unless the fixtures are changed so that no transformers are used to supply the lamps. This includes fluorescent lamps (compact or otherwise) unless the packaging specifically states that they can be used on a dimmer.

You may wish to contact Lutron Hotline at 800-523-9466 for additional help and suggestions. I hope this helps & good luck!

Mar 29, 2012 •
Lutron Electrical Supplies

0helpful

1answer

Hello, a 24 volt transformer can handle a tolerance of about 10% or just a little under. The important thing to remember about transformers is to always replace one with the same VA rating ( VOLT-AMPERE)

Feb 18, 2011 •
Heating & Cooling

0helpful

1answer

You should be able to. The Lionel transformers all put out AC power, not DC and many Marx and American Flyer transformers will work too. The real question is total amount of power being drawn and whether or not you have the wattage to match your engine and accessories. With the CW-80 though, it should put out plenty. I run my pre-war 1666E engine pulling a full compliment of metal cars with no problems using a CW-80.

Feb 05, 2011 •
Lionel Cw 80 Transformer

1helpful

1answer

New wire and plugs are available at chuckstrains.com , they can also tell you how to get into it

Jan 12, 2011 •
Lionel Cw 80 Transformer

0helpful

1answer

First of all, are there any other appliances or lights on this circuit? If so, they must be included in the total wattage for the circuit. The fan units are either listed with the Amp rating or wattage rating (Volt Amp) VA. The total amperage allowed on a 15 A circuit is 12A.(80% of the total per NEC). The total wattage would be 1380 watts. ( 115 Volt single phase X 15A = 1725 watts, 1725 x 80% = 1380 watts)

Jan 04, 2011 •
Cutler Hammer Ch115 15a 1 Pole Circuit...

0helpful

1answer

Check out this link, I think it will help.

http://www.lionel.com/media/servicedocuments/71-4198-251.pdf

http://www.lionel.com/media/servicedocuments/71-4198-251.pdf

Dec 14, 2008 •
Lionel Cw 80 Transformer

2helpful

1answer

I'm disappointed that Dewalt does not have the full specs on their website so . . .

Check the specifications on the charger's label; they should read something like 120 VAC or Volts AC and 2.0 (or similar) amperes or just 'A' after a numerical value.

If the label does not give you an amperage value you can use the output value instead and substitute the output voltage at the high end if a range is listed.

To get the adaptor (step-down transformer) wattage, multiply the AC values such as:

120 X 2=240 watts input power.

If these AC values are not available;

Take the high end charge voltage if it is a multirange charger, and multiply those values;

One we own DW9108 (- yours is 7.2 - 18) is spec'd at 9.6 to 18 volts and 2.8 amperes:

2.8 X 18=50.4 watts.

You can see that the values do not correspond but it is a multirange device so the maximum current taken from the AC line can be ~ 2.0 amperes but this is charging a specific pack and the peak input current is only momentary so the maximum output current and voltage are the values one should use as a guide. In other words, the output wattage is closer to the value needed.

Since there are losses in any transformation (mostly heat), the required stepdown transformer must be capable of more than the indicated 50 watts.

A safe factor would be 1.5 X 50 (W) or ~ 75 watts minimum to ensure the charger receives the 120 volts it wants.

Anything that will step down your (?) 220 volts and is rated at 75 watts or more will do the job even if the Dewalt draws a little more current at your line frequency of 50Hz which it may.

Check the specifications on the charger's label; they should read something like 120 VAC or Volts AC and 2.0 (or similar) amperes or just 'A' after a numerical value.

If the label does not give you an amperage value you can use the output value instead and substitute the output voltage at the high end if a range is listed.

To get the adaptor (step-down transformer) wattage, multiply the AC values such as:

120 X 2=240 watts input power.

If these AC values are not available;

Take the high end charge voltage if it is a multirange charger, and multiply those values;

One we own DW9108 (- yours is 7.2 - 18) is spec'd at 9.6 to 18 volts and 2.8 amperes:

2.8 X 18=50.4 watts.

You can see that the values do not correspond but it is a multirange device so the maximum current taken from the AC line can be ~ 2.0 amperes but this is charging a specific pack and the peak input current is only momentary so the maximum output current and voltage are the values one should use as a guide. In other words, the output wattage is closer to the value needed.

Since there are losses in any transformation (mostly heat), the required stepdown transformer must be capable of more than the indicated 50 watts.

A safe factor would be 1.5 X 50 (W) or ~ 75 watts minimum to ensure the charger receives the 120 volts it wants.

Anything that will step down your (?) 220 volts and is rated at 75 watts or more will do the job even if the Dewalt draws a little more current at your line frequency of 50Hz which it may.

Oct 09, 2008 •
Dewalt 7.2-18.0 Volt One Hour Charger

379 views

Usually answered in minutes!

×