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Lesley Ferguson Posted on Jan 28, 2013
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How do i graph three equations on my calculator

My equations I want to graph are x + y + z = 6, 2x + y -4z = -15, 5x - 3y + z = -10. I want them to be on one graph

1 Answer

k24674

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  • Texas Instru... Master 8,093 Answers
  • Posted on Jan 28, 2013
k24674
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Your calculator cannot, natively, perform 3D graphing.

5 Related Answers

Anonymous

  • 1 Answer
  • Posted on Jan 29, 2008

SOURCE: graphing

The first solution will allow you to watch your calculator graph two equations simultaneously rather than finishing one before graphing the next; it won't solve the problem of having the calculator unselect one equation when you select a second. To fix that problem, try the following:


In order to select additional graphs, the Transformation Graphing App will need to be uninstalled from the TI-83 Plus Family and TI-84 Plus Family. Uninstalling the App does not erase it from the calculator, it disables it from interfering with the normal graphing modes. Below are the steps to successfully uninstall the App.

  • Press [APPS] key
  • Select Transfrm from the menu
  • Press 1:Uninstall
The illustration and solution are courtesy of Jesse Phillips, who cites this page from the Texas Instruments support site

- doug garfinkel, Children's Day School

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Anonymous

  • 3 Answers
  • Posted on Jul 23, 2008

SOURCE: how to graph linear equation in two variables

I am not quite sure what you are asking...

(1) if asking for graphing y= -2/3x+2, then press [diamond] [F1: Y=] type in .2/3x +2, see graph by [diamond][graph]

(2) if asking for graphing y= -2/3x+a, where a=3x, then first archive a=3x in Home screen by [home], type 3x [sto] a, then go back to y= menu, and type -2/3x+a in Y1

(3) if asking for graphing an equation that is dependent on 2 variables at the same time, use x-y-z axis (aka, change mode to graphing 3-D by [mode]graph [5:3D]) then enter desired equation in y= menu using Z function in terms of x and y aka z(x,y)= ...)

Anonymous

  • 4 Answers
  • Posted on Oct 09, 2008

SOURCE: My calculator will only graph one graph at a time.

This is simple... Back up all RAM, (press second+, then 2, then 1, press enter to back up something if backed up it will have a star by it) Then clear your RAM (pull out your batteries while the calc is still on or press second+, then 7, then 1)
Hope this helps!

Anonymous

  • 1 Answer
  • Posted on Oct 29, 2009

SOURCE: how to graph an equation on a t1-83?

how to fix window to graph Pythagorean property

k24674

  • 8093 Answers
  • Posted on May 09, 2010

SOURCE: TI-83 Plus Calculator: I am trying to graph an equation and I get the "ER...

If the message appears when you try to graph functions deactivate the statistical plots. To do so:

Press [2nd][Y=] to access (STAT PLOTs)
Select [4:PlotsOff] then [ENTER]

That should solve your problem. Post a comment to this thread if you still have trouble graphing.

If the message appears in another context, it sure would help knowing the context of the error.

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Related Questions:

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1answer

Find the equations of circles passing through (1,-1),touching the lines 4x+3y+5=0 and 3x-4y-10=0

First, I graphed the lines and the point using Desmos.com.

I noticed that the two lines are perpendicular to each other and the point (1,-1) appears to be on the right side of the circle, on a line parallel to 3x -4y-10=0. The equation of this line is y= 3/4x - 1.75. The y-intercept is -1.75. Now we have two points on the opposite sides of the circle, (1, -1) and (0,-1.75). The midpoint formula will give you the centre of the circle and the distance formula will provide the radius.

Let me know if you have any questions.

Good luck.

Paul
Desmos Beautiful Free Math
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Argument error ti nspire

What are you trying to do?
Could it be that you entered a + sign followed by a - (minus) sign instead of a change sign (-). +-10
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I want to know how to graph equations on the TI-84 calculator

You must cast the functions in the so-called functional form y=ax+b. Isolate y for both functions, then open the Y= function editor and type in the second member (right member) of y=ax+b.
You can enter both functions and have them graphed on the same screen. In that case one will be on the Y1= line, the other on the second line.
Make sure that both = signs in the Y= editor are highlighted if you want both functions on the same graph.
0helpful
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How do I graph two equations on the calculator

You must cast the functions in the so-called functional form y=ax+b. Isolate y for both functions, then open the Y= function editor and type in the second member (right member) of y=ax+b.
You can enter both functions and have them graphed on the same screen. In that case one will be on the Y1= line, the other on the second line.
Make sure that both = signs in the Y= editor are highlighted if you want both functions on the same graph.
0helpful
1answer

How to use ti 84 plus calculator to graph linear equations

You have to use Y Editor to define functions on the both sides of the equation and then graph it. Finally option is F5: Intersection.
See captured images for equation 5x+10=-2x-7, y1=5x+10, y2=-2x-7 and x=-17/7












2_26_2012_7_15_54_am.jpg

2_26_2012_7_16_12_am.jpg
0helpful
1answer

What ia the sulution of 3y-6x=-3

To find the solution, first find the value of y for each equation.
Then substitue one equation into the other so that you only the x variable left.
Then just solve for x.
Once you have a value for x, then you can easily solve for y.


So for the first equation:

3y - 6x = -3
3y = 6x - 3

y = 2x - 1


Now for the second equation:

2y + 8x = 10
2y = -8x + 10

y = -4x + 5

Since both equations equal y, they also equal each other, therefore:

2x - 1 = -4x + 5

Now just solve for x:

2x + 4x = 5 + 1
6x = 6

x=1

Now substitute x=1 into either original equation:

y = 2x - 1
y = 2 (1) - 1
y = 2 - 1

y = 1


Therefore the solution is x=1 and y=1



Good luck, I hope that helps.


Joe.
0helpful
1answer

Michael buys two bags of chips and three boxes of pretzels for 413. He then buys another bag of chips and two boxes of pretzels for 239. Find the cost of each bag of chips and each box of pretzels.

Price of bag of chips s X and price of box of pretzels is Y.
Now you can write following equations:

2X+3Y=413
X+2Y=239

From second equation you know that X is 239-2Y, and you put that in first equation:

2*(239-2Y)+3Y=413

or

-4Y+3Y=413-2*239

Finally we have for Y: Y=65 and X=239-2Y=109.
0helpful
1answer

I am trying to graph function x^2+y^2+4z=10

  1. In Home, Press the MODE button.
  2. On line Graph, use right arrow to unfold the graph menu and select 3D.
  3. Press [2nd][QUIT] to go back to HOME screen.
  4. Enter the [Y=] editor.
  5. On line z1= type in the expression (10-x^2-y^2)/4
  6. Press the appropriate key sequence to [GRAPH] (on my Voyage 200PLT, I press [diamond R]
  7. While graph is displayed you can press the F2 key to access the ZOOM functions.
1helpful
1answer

Algebra equations

This is very basic scientific calculator and you cannot use it with variables.
As to your equation (if you want to solve it) it is much simpler to do so with pen and paper.

Write it as
3y-6=-7y +4
Take the 6 from the left to the right where it becomes +6, Thus
3y=-7y+4+6
3y=-7y+10

Take the -7y term from the right to the left side, where it becomes +7y
3y+7y=10 or 10y=10.
The solution is clearly y=1.
11helpful
4answers

How to graph linear equation in two variables

I am not quite sure what you are asking...

(1) if asking for graphing y= -2/3x+2, then press [diamond] [F1: Y=] type in .2/3x +2, see graph by [diamond][graph]

(2) if asking for graphing y= -2/3x+a, where a=3x, then first archive a=3x in Home screen by [home], type 3x [sto] a, then go back to y= menu, and type -2/3x+a in Y1

(3) if asking for graphing an equation that is dependent on 2 variables at the same time, use x-y-z axis (aka, change mode to graphing 3-D by [mode]graph [5:3D]) then enter desired equation in y= menu using Z function in terms of x and y aka z(x,y)= ...)
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