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My ti-89 titanium won't graph logarithms (y1=22log(10)x)

It shows a straight line going through the point (0,0) terminus at (1,10), (-1,-10) instead of a curved line as it should show...What am I doing wrong?

Posted by hbom7641 on


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The graph of y=22log(10) is a straight line, though it should go through (0,0) and (1,22). Log(10) is a constant 1, so the function is simply y=22x .

If you want "twenty-two times log-base-ten of x", write it as 22*log(x) .

Posted on Aug 12, 2012


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See capture image below

My ti-89 titanium won't graph logarithms (y1=2 - ti-89-titanium-won-39-t-graph-roir20cykniyl1pyryxceik0-1-0.jpg

Posted on Feb 29, 2016


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  • 37 Answers

SOURCE: Won't Graph Exponential Function

Ok, try these two things and you should be just fine.
1.) Check your range for your graph. It is possible that the range you are using isnt large enough to show the curve. Also try using Z-fit vs Z-st. These are options that your calculator will give you once the equation is graphed.
2.) Place a parenthesis around the 2x, make sure that you and the calculator are both using the same order of operations. This move mill ensure that the calculator will multiply the variable, x, by two and then do the exponential.
This should do it!
Happy Graphing!

Posted on Jul 25, 2010


  • 8092 Answers

SOURCE: I graphed Y=tan(x) on two

Check the angle unit. If Angle unit is set to degree and window is about (-10,10) for X and (-10,10) for Y, you get a straight line. See screen capture.

Use radians. Or if you use degrees, set Xmin about -180 and XMax about180

With radian units the graph looks as follows.
Check the calculator configuration.

Posted on Jun 10, 2011


  • 11 Answers

SOURCE: I have an TI-84 and

when you do your regression (stat --> calc --> linReg/QuadReg/whichever regression you're doing)) make sure you put the equation into Y1 before going to the table.

Posted on Sep 17, 2011

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Related Questions:


How to restore memory on TI-89

Hard Reset means reset. Everything gone and no way to recover it.

Sine graph is straight

If the angle unit is set to degrees and you use the standard window dimensions (Xmin=-10, Xmax=10) then all you will see is a straight line: Between 0 and 10 degrees, the sine is approximately equal to 0 and the cosine is about 1.

To see the features of the trigonometric functions you must do one of the following
  1. Set angle to degree but set window dimensions to span the domain -180 to 180 or larger.
  2. Set windows dimensions to the standard -10, 10 range but set angle degree to radians

Can you find stationary points of this equation ((x-1)^1/3)*((x+2)^2/3))

There is only one stationary point for the function y(x)=((x-1)^(1/3))*((x+2)^(2/3)) and it is pointwith coordinates x=0 and y=-1.5859

At first, first derivation is y'(x)=x/((x-1)^(2/3))*((x+2)^(1/3)) and we obtained that y'(0)=0. Then we can find second derivation of the function and for value x=0 we could concluded that y''(0)>0. In this stationary point it is minimum value of the function.
Finally, at the points x=-2 and x=1 we have so called critical values for this function.
See captured images below

1. Second derivation for y(x)

2. Graph y(x)

3. Enlarged detail of the graph y(x)

Using appropriate properties of logarithms, rewrite f(x)=2+3ln(1/x)

At first, y=2+3(ln1-lnx), logA/B=logA-logB

You have to know that ln1=0 because by the definition e^(0)=1

And finally y=2-3ln(x)

See the graph of this function on the image below


I have a TI-89 Titanium. How do I graph a function containing a cubed root?

For example y=x^(1/3)-x+1. Type this function and then graphing it!
See captured images



Where can I find the log values in TI 89

For natural logarithms, you can use the ln function (2ND shift of the X key). For example, the natural logarithm of 3 is 2ND [LN] 3 ) ENTER.

For logarithms to other bases, use the log function (diamond shift of the 7 key). For example, the base-2 logarithm of 16 is diamond 7 1 6 , 2 ) ENTER. If the base is 10 (common logarithms), you can omit the comma and the second argument.

All trig-based graphs give me weird results on my TI-89 Titanium. Taking y=sin(x) for instance, I get a clean diagonal line through the point (0,0), almost resembling the graph y=x with window xmin = -10...

You have your angular mode set to degrees. Ten degrees is about 0.17 radians, and for small x: sin(x) is nearly equal to x. Thus, sin(x) from -10 to 10 is indeed nearly a straight diagonal line.

Press MODE, then scroll down to "Angle" to change the angular mode.

X and Y axis disappeared

You hit 2nd Zoom then turn go down to Axes On and hit enter to turn it on.
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