# I have the sharp EL-733A, calculate the learning curve formula of y=ax(-b) on this type calculator

I have the sharp EL-733A, pls advise on how you calculate the learning curve formula of y=ax(-b) on this type calculator assuming the learning curve is 80% - how do you get the 'b' calculated then how do you complete the formula with the power of 'b'

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### Anonymous

you could try http://www.sharpusa.com/files/cal_man_EL531_509.pdf
this basically replaced the d model

or you could order one from:
http://www.andrewselectronics.com/

hope that helps.

Posted on Jan 26, 2008

### Jerry

You can access the .pdf manual for your particular calculator here:

http://www.sharpusa.com/files/cal_man_EL1750PIII.pdf

Page 1 for how to set date/time:

“RATE SET”: To set the date, time, and tax rate, set this switch at the “RATE SET” position.
Date:
• Enter in the order of month, day and year, then press to complete the entry.
• Use to separate month, day, and year.
• When is pressed, the number entered is evaluated and displayed as “date” if the
value is within the following range; “Error” is displayed otherwise, and the previously set
date is restored.
Month: 1 - 12; day: 1 - 31; Year: 2000 - 2099 (in 4 digits) or 00 - 99 (in 2 digits)
Time:
• Enter in the order of hour, minutes, then press to complete the entry.
(There is no entry available for the seconds value. The clock starts at zero second.)
• If the hour/minute digit is less than 10, it is not necessary to enter the first digit “0”.
• Use to separate hour and minute values.
• When is pressed, the number entered is evaluated and displayed as “time” if the
value is within the following range; “Error” is displayed otherwise, and the previously set
time is restored.
Hour: 0 - 23 (24-hour system for the hour entry), Minute: 0 - 59

Posted on Apr 27, 2009

### Anonymous

SOURCE: how to calculate

It's very simple: the calculators have a default base 10 so that log x it's log x base 10 so here is some logs:
log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y
Hope it's helped

Posted on Jul 06, 2009

### Anonymous

http://www.sharpusa.com/products/support/view_all_models/0,2326,32,00.html
I don't see that model listed...are you positive on exact model number?

Posted on Sep 05, 2009

### Anonymous

SOURCE: Sharp EL-1801V Calculator

Change the switch to Rate Set, then input the mm.dd.yyyy then the clock/time button then hrs (military time).minutes then clock/time button.

Posted on Feb 11, 2010

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P.S. I posted an image, got a post error if typed on plain text, fixya won't accept.

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GOTO http://support.sharp.net.au/

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Hello,
This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.
Let the equation be ax^2 +bx+c=0
You compute the discriminant Call it disc.
disc= (b^2-4*a*c)
1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.
Then x1=(-b+square root of disc)/(2*a)
and x2= (-b-square root of disc)/(2*a)

2. If disc=0 , square root of disc =0 and x1=x2=-b/(2*a)
3. If disc is negative, there are no real solutions.

To find the solutions you replace a, b, and c by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

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Hello,
This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.
Let the equation be ax^2 +bx+c=0
You compute the discriminant Callit disc.
disc= (b^2-4*a*c)
1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.
Then x1=(-b+square root of disc)/(2*a)
and x2= (-b-square root of disc)/(2*a)

2. If disc=0 , square root of disc =0 and x1=x2=-b/(2*a)
3. If disc is negative, there are no real solutions.

To find the solutions you replace a, b, and c by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

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Hello,
This calculator does not have a program to which you give the equation, and which returns the solutions. Sorry. You have to use the formulas you learned.
Let the equation be ax^2 +bx+c=0
You compute the discriminant Call it disc.
disc= (b^2-4*a*c)
1. If discriminant is larger than zero you have two solutions. Let us call them x1 and x2.
Then x1=(-b+square root of disc)/(2*a)
and x2= (-b-square root of disc)/(2*a)

2. If disc=0 , square root of disc =0 and x1=x2=-b/(2*a)
3. If disc is negative, there are no real solutions.

To find the solutions you replace a, b, and c by their numerical values, to calculate disc, its square root, and calculate X1 and X2.

Hope it helps.

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