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rudy jordaan Posted on Mar 21, 2012
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I have a auto pro 800 watt inverter that gives 220volt ac **** wont run my kellerman freezer it runs in the house on ac can you help

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  • Master 32,281 Answers
  • Posted on Mar 22, 2012
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If your freezer need more than 800 watts to run then your 800 watt inverter will be overloaded and it will shutdown.

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nitrospawn

Ibe Chukwudi

  • 290 Answers
  • Posted on Feb 27, 2010

SOURCE: Vector vec 051D 3000 watt fan won't run anymore, unit overheats

your inverter needs to cool at all times , if the fan does not work,try buying a small standing fan to blow cool air to you machine, it is possible that your heater is making the inverter to over heat please avoid using the heater on the inverter

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How do I make the inverter work on a 2017 holiday rambler vacationer 35k

An inverter changes 12vdc to ac. If it is 35 k it may be 35000watts. Therefore it needs that many watts or more to run it efficiently. Check with a manual for information on how many watts it needs. Most average homes need 10000watts or 10kilo-watts. If you are making DC Volts you need to hook up an AC LINE INTO YOUR VACATIONER and this will give you standard a.c. for refrigerator and overhead lighting. With that 35k watts if that is so you may need a 240 VOLT AC HOOK UP.. Some trailers use AC and some DC . Mine has an inverter but I think it uses120 volt AC . Some VACATION Homes have DC possibly 4 -12volt batteries or more but those batteries are each possibly 300 AMPS at. around 14.5 volts DC. Watts =VOLTS x AMPS . 14.5 X 300 = 4350 X 4 =17400 Watts or 17.4 k watts . 120 VAC input times 15 AMPS = 1800 watts standard a.c. But with 240VAC x 25AMPS = 6000 watts. Along with those 4 batteries it would have plenty of power to run it. If the Dc was hooked to an inverter it would produce a.c. Instead of DC. Inverters are all different so check the wattage being output and input.
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I'm trying to run a 750 watt whirlpool compact microwave with a 2500 watt Cobra inverter. The microwave runs normally, but it won't heat. If I plug it in at my house it heats fine. I'm stumped. I load...

I assume your not using a pure sine wave inverter. A lot of electronic devices won't work on a lower cost inverter (modified sine wave) that has a square sine wave, either invest in a true sine wave inverter or don't run sensitive electronic equipment, I'm somewhat surprised you didn't damage the circuit board in the microwave...Below is a link of a inverter that would work if you want to spend the money for one.
2500W 5000 Watt Power Inverter Pure Sine Wave 12V dc 110V 120V ac LCD...
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I have a coleman powermate pmp400-t inverter 400w/800w will it power a sump pump? I tried it and it beeped and the fault light came on

Hello, the answer is no. This inverter will work with a pump that below or about 400 watts power for operation. I notice it says that the inverter 400w/800w. The 800 watts is the surge required to get an electric motor to run. On a single phase motor (120 AC) and it take 4 amperes to operator this motor. But to start the it will 12 amperes to start it. This is one reason why on a lot of electrical motors there will be a big tube or can, this is the starting capacitor, it stores energy in form of current (amperes) to drop across the windings of the motor when it starts. If some electric motors didn't have this capacitor. The most likely scenario would be tripping a breaker because it drawing to much current.


Now, for you problem. Example of Power and the unit of the formula is V (volt), R (resistance) I (current) P (power) Ohm's states that :

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Now Power would be stated: P = V times(x) I. Therefore in your case, if the pump at normal operation is drawing 4 amps of current for operation pumping water. The power factor would be 120 V AC (house voltage) times (X) I (current) which 4 amps. So here is what you have: P = 120 X 4 equal= 480 watts.

Therefore, your inverter will not work because it operating at 80 watts more than the power inverter can deliver which is 400 Watts.



If you need to purchase a new power inverter, remember always take into account the Amperes required for operation. Just by the simple Ohm's Formula. Best of Luck. GB....stewbison
son
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No,
You will need a much larger power inverter than that to run that vac...

heatman101
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We need to know how much power the 3.6 cu-ft danby freezer uses as we have solar power. Would like to run off the batteries if possible

Hi, well its 120 volts a/c, 60hz, and you would have to look on the data plate to see what the total amperage it draws. If you are wanting to run it off of batteries, it can be done, You would need to figure out how many dc batteries it would take to do this and I have seen mobile homes have 240 volts a/c to there home running on batteries alone. You would need a rectifier to change dc to ac voltage. I would recommend making some calls on how to figure this out as far as what all you need to do this as I could not walk you through this, only if I were there. Call an electrical wholesale parts house and tell them what you want. They will be able to supply the dc rectifier to change dc to ac and they would be able to tell you where to go to get the right batteries and how to run them together to produce 120 volts ac voltage. Please keep me posted on your progress and if you need further help. Good Luck,
Shastalaker7
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Went u turn it on the red lite comes on and wont turn green and wont work its a road pro rppi-1500w

Sadly replacement is the best option. It is just not cost effective to get the inverter repaired.

The cost starts out about 150.00.

Best option is to take it back to where you purchased it and hope you can get a new one.

Hope this tip helps.

Am a seven each power inverters owner.

Recommendations: Purchase a Pure sine inverter 1500 watt. We have had one of these running 24 seven for almost a year now.
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2000 watt cobra inverter keeps saing olp, overload

2000w means is out off rang load 2000w plus then alarm beep have running.
1helpful
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Conecting to 120 volts AC

If you want to get more precise, figure out everything in terms of power (watts).

Basic electrical rule 1, 2 and 3:

voltage x current = power

or re-arranged:

current = power divided by voltage

or re-arranged:

voltage = power divided by current


For example, 12V X 2 amps = 24 watts.

or another example, 400 watts divided by 120 Volts = 3.33 amps

A 55W headlight that uses 12V would draw 55 /12 = 4.6 amps @ 12V

A 55 watt light bulb in a lamp at home would draw 55 / 120 = 0.46 amps @ 120V


As the previous post mentioned, inverters are not perfect when convertering 12V into 120V. If the converter consumes 1000W from the 12V battery, then a 90% effecient converter would generate 900W of 120V AC power best case. The other 100W is lost primarily as heat.

The other thing that gets tricky is that these ratings and the formula above are used for resistive loads, like light bulbs or hair dryers. Anything with a motor or transformer is considered an inductive load and can get much more tricky to calculate.

Consequently you need to give your self a safety margin when figuring out how big an inverter you need.

How does work in a practical sense?

Lets say you want an inverter for TV, DVD and Sat. Receiver. Look at the back of TV or in the manual. It should say how many watts it consumes. Lets say it is 400W. The DVD might be 100W and the Sat. receiver 50W - just as an example.

400 + 100 + 50 = 550 Watts. (just as an example)

You might think, well no problem, I'll use a 600 Watt inverter and have 50 watts left over. Depending on your inverter, that 600W might really be 600 x 90% effecient = 540 Watts of AC, less a 20% margin of error for the inductive transformers in the electronic of the TV, DVD and Sat. receiver 540 - 20% = 432 Watts.

Now you can see your 600 Watt inverter isn't big enough to do the job.

If we really need 550 watts of AC, add 10% to make up the effiency loss, then add a safety margin for inductive loads.

550 + 10% = 605 + 20% = 726 Watts.

Sounds more like an 800W inverter fits the job.

What does that mean in terms of wiring the 12V batteries to the inverter?

from the formula above:

current = power divided by voltage

In our example, we have an 800W inverter that runs on 12V

The current would thererfore be:

current = power divided by voltage
current = 800 watts divided by 12V
current = 66 amps.

That is important info because you can not use light gauge wire to carry 66 amps worth of 12V to the inverter nor could you use a 20A fuse to protect your inverter.

Now that's a lot of science for a guy who just wants to run a toaster on an inverter right?

800W / 120V = 6.66 amps

Using garryp's ratio 11:1, 6.66 x 11 = 73 amps.

That is a good ratio with a good safety margin.

This is all just MHO and should not taken as solid technical advise. In other words, don't blame me if you blow yourself up.
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