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yusuf Posted on Feb 14, 2012
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Sketching curves on a calculator - Casio FX83ES Scientific Calculator

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k24674

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  • Casio Master 8,093 Answers
  • Posted on Feb 15, 2012
k24674
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Curves drawn with the help of a graphing calculator are no mere sketches, they are a lot more accurate than a human hand will be able to draw.
Unfortunately for you, the calculator you are using is no graphing calculator and thus cannot draw. However, it is able to generate a table of values which you might use to sketch curve on a sheet of graph paper.

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0helpful
1answer

Right Triangle ABC has vertices A (-4 2)B(-4 6) C (9 6)

The area of a triangle is 1/2 times base times height. A sketch of the triangle in the coordinate plane will determine how easy or hard this will be to be. From the sketch, you will see that this is a right-angled triangle with B being the right-angle. This makes it easier because we can easily determine the base and the height to use in the formula.

We can chose AB or BC to be the base, while the other will be the height. If we choose the base of AB, its length is 4, the 6 - 2. The height is 9-(-4) or 13.

We can now put the length and height into the formula to calculate the area of the triangle.

Good luck.

Paul
0helpful
1answer

When I try to find Intercept on my graph I : [2nd]Trace [Enter] (for first curve) [Enter] (for second curve) but nothing happens. It still asks me for second curve. I move the point to diffrent...

There seems to be a confusion between two terms: intersection of two curves and y-intercept, or x-intercept.
When you press [2nd][TRACE] you are accessing the CALCulations menu for the graphics. The [1:calculate ] sub-menu gives the value of y for a given value of x. The first curve taken is the one in Y1=. If you want to find the value of y on a second curve for the same value of x, you use the Up Arrow or Down Arrow. (Use Up Arrow or Down Arrow to cycle through the curves.)
The sub-menu [5:Intersect] allows you to find a point where two curves intersect (cut one another). The calculator starts on the first curve (Y1=) and asks you to select the second curve. At this point you use the Up or Down arrow to jump tho the next curve. Then you will be asked for a guess.
First, know what you want and do not confuse interCEPT with interSECT
1helpful
1answer

Ind the area of the region bounded by the two circles y=x^3-6x^2+

The first step here is to draw a rough sketch of the two curves, and find the two points they meet. If you set x^3-6x^2+8x = x^3-4x, then you can rearrange this into the quadratic equation 6x^2-12x = 0. Solving this tells you x=0 or 2 : these are the two x values where the curves meet, and they give the bounds on your integral.

When you sketch the curves, you'll see that x^3-4x is below x^3-6x^2+8x, so the thing you need to integrate is (x^3-6x^2+8x)-(x^3-4x), that is, 12x-6x^2. If you integrate this from 0 to 2, you'll have the answer you need!
8helpful
1answer

How do I use the intersect function on the TI-84 plus calculator

  1. You draw two or more graphs.
  2. After the graphs are displayed, press [2nd][TRACE] to access the (CALC)ulate menu.
  3. Select [5:Interesct]
  4. You will be prompted for a first curve: the equation of the curve will be displayed at the top left corner of the screen. If it is one the intersecting curves, press [ENTER]
  5. You will be prompted for the second curve. (You can move from one curve to another by pressing the UpArrow or DownArrow).
  6. After two curves are selected, you will be prompted for a guess for the X-value of an intersection point: you can use the keypad to enter a guess or use the left or right arrow to move the cursor towards a point of your choosing (if there are more than one point).
  7. After a short while the calculator gives you a solution.
  8. If it fails, you must make a better guess.
0helpful
1answer

How do i sketch a graph using a polar equation? i.e. r=a(1+cos "theta") this is for a casio 7400g plus btw

Apparently you cannot. Here are all the possible graph types available and there is no polar graph among them.

33137f5.jpg
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1answer

I can't calculate the intersection

Use the UpArrow and downArrow keys to switch from one curve to another. Use the left and right arrow keys to move cursor along a curve.
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1answer

The calculator wont recognise the blue funtion buttons (1-6)

Clear the ram:
1. Press [MENU]2. Press [tan] (MEM)3. Select RESET4. [F1] (yes)
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1answer

I need to find out how to graph fuctions and the derivatives using a cfx 9850gc plus ASAP

Hello,
Let us start wih the derivatives. To obtain the values of derivatives at points on a graph, you must set Derivative to ON
Press [AC/On] to trun calculator on. If you do not see the icons press [MENU], with arrows select [RUN] and press[EXE] . The screen clears.
Press [SHIFT][SETUP ] . The first few options must be set as follows
Mode : : Comp
Function Type : Y=
Draw Type : PLot
Derivative : ON This is the one to make derivatives visible
Angle : Rad unles you have to use degrees.
Coord : on if you want the x,y coordinates to be displayed
Grid : Off
Axes : ON to display x and y axes
Press [EXE] to save options. You are taken to [Run] screen.
Press [Menu] Play with arrows to select [GRAPH] and press [EXE]

You see a list Y1=, Y2= and so on
On the line Y1=, enter [SIN] [X,Theta, T] .
If function is complicated you may have to enter parentheses sin(X). When you finish to enter the functions you want to draw, hit [F6:Draw]
The graphs are displayed.
Press [F1:Trace] The trace function allows you to move cursor along the curve, while it displays the coordinates of the cursor. And since you set Derivative to ON, the trace displays also the value of the derivative of the curve at the position of the cursor.

There are other intersting tools, under [Sketch] and [G-solve ] such as minimum, maximum, tangente, inverse of the function drawn, integral under the curve, intercepts with the coordinates axes, etc. I will not spoil your fun by giving you the plot of the movie.

Hope it helps.

0helpful
1answer

Inst manual

The length of a rectangle is twice its width w. a second rectangle, which is 8 cm longer and 3 cm narrower than the first rectangle, has perimeter 154 cm. Make a sketch of the rectangles expressing all dimensions of w. Then find the dimensions of each rectangle.
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