Integration, too few arguments

There are several ways of doing this.

Since you're using a graphing calculator, you can always graph it as a function of 'a' and use the graphical tools.

Another way is to use the solve() function. For example, to find the value of a where the integral of sin(x) from 0 to a equals one, enter
solve(fnInt(sin(X),X,0,A)-1),A,1.5)

solve( and fnInt( are accessible through the CATALOG. The 1.5 is an initial guess.

Unfortunately this calculator does not display results in radical form. If you enter SQRT(147) you get 12.12435565...
What you are asking for is called rationalizing an irrational expression. Usually one tries to get rid of radicals that appear in the denominators. Here is an example.
Suppose you have 1/(c+SQRT(d)), and you want to get rid of the radical in the denominator. How to do it?
Recall the identity (a-b)*(a+b)= a^2-b^2. It is true for any a and b

Rationalizing a denominator (usual case)
Now consider (c+SQRT(d)). Multiply it by (c-SQRT(d))
[c+SQRT(d)]*[c-SQRT(d)]=c^2 -[SQRT(d)]^2=c^2-d
You see that there is no radical.
Now take 1/(c+SQRT(d)). To get rid of the radical from the denominator multiply it by (c-SQRT(d)). But to leave the value of your expression 1/(c+SQRT(d)) unchanged, you must multiply both numerator and denominator by (c-SQRT(d)).
The numerator becomes 1*(c-SQRT(d))=c-SQRT(d), and the denominator (c^2-d).
Finally, the rationalized form of the expression 1/(c+SQRT(d)) is
[c-SQRT(d)]/[c^2-d].

Rationalizing a numerator
Sometimes, people have a radical in the numerator that they want to get rid of and have it in the denominator. The procedure is the same
Example:(c+SQRT(d)), the denominator here is 1
(c+SQRT(d))=(c+SQRT(d))*[c-SQRT(d)]/[c-SQRT(d)]. This gives
[c^2-d]/[c-SQRT(d)]
You have no radical in the numerator but there is one in the denominator. This is called rationalizing the numerator.
Your case is a lot simpler
SQRT(147)=7*SQRT(3)
Multiply it by SQRT(3)/SQRT(3) which is 1. This gives
SQRT(147)=7*3/SQRT(3)=21/SQRT(3)

SQRT(147)= 21/SQRT(3)

The calculation may be taking too long and you got impatient. To reduce the time it takes to calculate some expression or find a root you can make better guesses (initial values), or choose better limits to an integral, or divide the integral in two if integrand symmetrical. If you can select the tolerance (error you are willing to accept), increase it: Instead of taking epsilon =1E-9, take epsilon=1.E-5. But that depends on the context of the calculations. You be the judge.

If you're in the MATHPRINT mode, press
2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 right-arrow ) / 2 5 ENTER

If you're in the CLASSIC mode, press
2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 ) ) / 2 5 ENTER

In either case you should get an answer of about 103.

The error data type means that the program is expecting a specific type of data ( number, list, matrix, real, complex, string, etc.) while you are feeding it some other type of data. The point in the program where you are taken when the error occurs is where the exception was launched.

A common source of error stems from the use of variables that are global and defined in some other program. You can use the same name inside your program as long as you declare the variable local.
If your program is in fact a function, then all its argument must be passed in the call to the function: You cannot ask a function to read your input.

I will not pretend to know why you get the error, but the few comments I made above may help you debug the program.

By the way, if you are interested a Cobebrook online calculator, here is a link

You can perform coordinate conversions in the COMP, STAT, MATRIX and VECTOR Modes.
Angle unit may be in either degree or radian.

To convert from rectangular to polar, (SQRT(2)/2,SQRT(2)/2)

Press [SHIFT] [+] (Pol)
Screen displays Pol(
Type in SQRT2
Use right arrow to move cursor out of radical
Type in /2 [SHIFT] [,]
Type in SQRT2
Use right arrow to move cursor out of radical
Type in /2
Close the right parenthesis
Screen displays Pol (SQRT2 /2, SQRT2 / 2)
Press [=]. Display echoes the command on top line and result in bottom line as r=1, theta =45, (if unit is in degree) or theta = 0.7853981634 if unit is radian.

To convert from polar to rectangular coordinates
Note: You cannot use the answer memory to convert back to rectangular because the calculator will use the r-value only. So you will have to enter the radius AND the angle.

ex: Rec(1,45)
Angle must be in degree
Press [SHIFT][-] (Rec)
Screen display Rec(
Type in 1 [SHIFT] (,) 45 [)] [=]
Calculator displays X=0.7071067812, Y=0.7071067812
If you press the SD key hoping to convert the decimals to radicals, the calculator will not do it.

As to the "confusion", I have found none.
After you finish entering the argument of a square root, use the right arrow to move cursor out of under the root symbol to signify that the argument is complete. If you use a left parenthesis inside the root, you must insert the matching right parenthesis inside the root, then move cursor outside the root.

This is how the calculator behaves, and I am not expressing an opinion on how simple or complicated that is. I assume that to make full use of the calculator capabilities, one has to converse with it, using the syntax it understands.

Hello,
The default variable for the integral is x. If you have a product between two litteral symbols the * must be inserted. Arguments of functions must be enclosed between parentheses. To avoid errors clear the variables before the integration: [2nd][F6:Clean Up] [2:NewProb][ENTER]ENTER]



Hope it helps.

Hello,
Here is a screen capture of the integral.


The dummy variable x may contain some previously defined value. Clear old values . In Home folder [2nd][F6: Clean Up][ 1:Clear a-z] [ENTER][ENTER] or [2:NewProb][ENTER][ENTER]
Make sure you insert the multiplication sign. And do not forget to put the argument x of the function inside parentheses.
Hope it helps.

Hello,
You should enter it as follows [SQRT]36 ) [ENTER/=].
If you define some function f of a variable x you write that f(x), where the parentheses enclose the so-called argument (objet on wich the function acts). It seems that on this calculator the opening parenthesis is implicit: the calculator supplies it when you press [SQRT] but does not display it (a design flaw?). However the closing parenthesis must be entered by you to signifie to the function [SQRT] that you have finished entering the argument. Weird but one can live with it.
Hope it helps.