sinx+cosx=5, tanx+secx=3 then sinx=? sinx+cosx=5,tanx+secx=3 sinx=? tanx= sinx/cosx, secx=1/cosx 1+sinx/cosx=3 1+sinx=3cosx---------->1 cosx=5-sinx------------->2 sub 2 in 1 1+sinx=3(5-sinx) 1+sinx=15
wat is the solution for sinx-cosx=2 ? whats the appropriate unit of measure for -5 1/4in - 2 2/3 in (sinx+cosx)^2 + (sinx-cosx)^2
sinX-cosX=4 how can this be solved? I gues this problem has no solution because both SinX and cosX should be between -1 and +1 so it's not possible that value of SinX - cosX should be 4
(sin-cos)(sin+cos) help!! (sinX-cosX)(sinX+cosX) =(sin^2 - Cos^2X) =Sin^2X - (1-Sin^2X) =Sin^2X -1 + Sin^2X =2Sin^2X -1 Zulfikar Ali [email protected] 9899780221
cscx = 2 and cscx = -2 cscx = 2 and cscx = -2 0 ≤ x ≥ 360 cscx=2 which can also be written as 1/sinx = 2/1 do the recipricol (flip it) and sinx = 1/2 which is pie/6 or 30 degrees.
does (sinx)^6 + (cosx)^6 = 1 ? like sinx^2 + cosx^2 = 1? no the answer is not equal to 1
Question about SoftMath Computers & Internet
use the identity tan(x/2)=sinx/1+cosx to solve for the value of tan45 degrees solve for tan45 degrees using the identity tan(x/2)=sinx/1+cosx tan(x/2)=sin(x)/(1+cos(x)) Setting x/2=45, means that x=90
its all about the trigonometric ratios sinx+sinpower2x=1 then cospower8x+2cospower6x +cospower4x is how much
Question about Super Tutor Computers & Internet
If asinx =bsin(x+2*180/3)= csin(x+4*180/3); prove that ab+bc+ac=0 * = multiply asinx = a*sinx asinx=bsin(2x*60)=120x
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