...has a son 9. in how many years will the mother be twice as old as her son? 33 + x = 2 (9+x) 33 + x = 18 + 2x 33 + x - 2x = 18 33 - x = 18 x = 15 In 15 years (The mother will be 48 and the son
33 and 3051. This sum is equal to 40+48+56+64+72+...+3024+3032+3040+3048= 40+(48+3048)+(56+3040)+(64+3032)+(72+3024)... There are (3048-40)/8+1=377 terms in sum. (48+3048)=(56+3040)=(64+3032)=(72+3024
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