Texas Instruments TI-30XA Calculator "log 2" Questions

...log(2) from log(4) I get .301029957, the answer should be 2, what is wrong? The answer for the problem log(4) - log(2) is actually 0.301, so the good news is that your calculator is working properly! ...

...log base 2 To calculate the log base 2 of a value, calculate its log and then divide by the log of 2. You can use either the log or the ln keys, but be consistent. For example, to calculate the log ...

log^2 24 - log^2 3 = log^5 x Here something that would help you: log x base y = log x / log y log (x*y) = log x + log y log (x/y) = log x - log y so log 24 base 2 it's log 24 / log 2 etc. and if i get

...log (base 2) 8? The answer should be 3....that is it is the inverse calculation of 2 cubed =8. Can any one help with the log calculation? Yes look you can't enter the base in calculators it's default ...

...log base 2 You can't. However, you can calculate the log base 2 of any number by calculating log2(x) = log(x)/log(2) = ln(x)/ln(2) That is, the log base 2 of any number is the log of that number ...

log(x) / log(b) = ln(x) / ln(b) You can use either the common log (log) or the natural log (ln), as long as you're consistent. So, to calculate log2(2.5), press 2 . 5 log / 2 log = or 2 . 5 ln / 2 ln

How can i perform Log 9 base 2 log(9)/log(2) (both base 10) is equal to log(9)base 2. This works for anything, try it backwards and you'll find that 2^(log(9)/log(2)) is equal to 9.

...log(x-2)= log[(x+1)*(x-2)]=1 Use the fact that log4=log in base 4 and rewrite the equation with the appropriate symbols. log4[(x+1)*(x-2)] =1 However 1=log4(4) and log4[(x+1)*(x-2)]=log4(4) The ...

2*(log[0.160]/[0.002]) please do explain each step in detail . Look the calculators has a default base 10 and you can't change it but you may learn this: log x base y = log x / log y log (x*y) = log x