TRIANGLES FROM A WINDOW 30 feet above the ground,a building 100 feet high, and at a distance of 200 feet, is observed.find the angle of elevation of the top of the building and the angle of depression
...AB = 5 Yards BC = ? Now Tan C= AB/BC BC = AB/ Tan C BC = 5 / Tan 28 Yards BC = 5/.531709 Yards BC = 9.403632 Yards Try checking this site for information on Angles of Depression and
angle of alevation suppose a tree 50 ft in height cast a shadow of length 60 ft. What is the angle of elevation from the end of the shadow to the top of the tree with respect to the ground? height =50
Angle of elevation The angle of elevation to the top of a tree from a distance of 33m is 19 degrees. Work out the height of the tree. 11.3628 M what the ****!!!!
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A flag pole is at the top of a building. 250 ft from the base of the building, the angle of elevation of the top of the pole is 50 degrees and the angle of elevation of the bottom of the pole is 48 ...
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