Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

goodluck!

Posted on Jan 02, 2017

This is not the kind of material for this site, we are a self help repair and use site for manufactured products.

Mar 01, 2017 | Office Equipment & Supplies

This calculator is unable to factor a polynomial expression.

In general there are a few factoring methods

In general there are a few factoring methods

**Factor by grouping terms****Factor by completing the square**(quadratic polynomial)**Factor by finding two integers such their sum is equal to the coefficient of the middle term, and their product is equal to the third (constant term)**. This is valid for a quadratic polynomial where the leading coefficient (of the x^2 term) is equal to 1.**X^2+SX+P**

Jul 31, 2012 | Casio FX-115ES Scientific Calculator

1. Combine like terms on the left side of =

4x-2x =2x

New left side is 2x + 1

2. Combine like terms on right side of =

5 - 7 = -2

New right side is x - 2

3. New problem is 2x + 1 = x - 2

4. Now get all x terms on left side of =

and all constants on right side of = by adding the opposites of the corresponding terms as you move them across the =

2x - x = -2 - 1

5. Combine the like terms on each side of the =

Left side: 2x - x = x and Right side: -2 -1 = -3

So x = -3

6. Now check your solution by substituting your answer back in to the original problem.

4(-3) - 2(-3) + 1 = 5 + (-3) -7

7. Now do the arithmatic and hopefully the left and right sides are equal.

-12 + 6 +1 = 5 -3 -7

-5 = -5

Since this is a true statement I know my answer of x = -3 is the correct solution to this problem.

4x-2x =2x

New left side is 2x + 1

2. Combine like terms on right side of =

5 - 7 = -2

New right side is x - 2

3. New problem is 2x + 1 = x - 2

4. Now get all x terms on left side of =

and all constants on right side of = by adding the opposites of the corresponding terms as you move them across the =

2x - x = -2 - 1

5. Combine the like terms on each side of the =

Left side: 2x - x = x and Right side: -2 -1 = -3

So x = -3

6. Now check your solution by substituting your answer back in to the original problem.

4(-3) - 2(-3) + 1 = 5 + (-3) -7

7. Now do the arithmatic and hopefully the left and right sides are equal.

-12 + 6 +1 = 5 -3 -7

-5 = -5

Since this is a true statement I know my answer of x = -3 is the correct solution to this problem.

May 17, 2012 | SoftMath Algebrator - Algebra Homework...

One possible cause is a mismatched speaker system. Most stereo equipment specifies 8 ohm speakers to match the 8 ohm amplifier output resistance. A well known electronic formula states maximum power transfer occurs when the resistance in and the resistance out are equal. When there is a mismatch, more power is required to obtain the same sound pressure levels. By turning the volume up higher to do this, the electrical requirements to drive the speakers at that level may be exceeding that which the amp can provide. When this happens, the amp shuts down due to overload. Continued operation in this condition can cause permanent failure.

Another possible cause is the power requirements of the speakers to be driven properly. Larger speakers require more power to move the speaker coil and and cone. Connecting a speaker that requires 10 watts to be driven to an amplifier that provides up to 8 or even 10 watts will require that the amp be operating at 100% of capacity. An amplifier run like this will have a short life.

Connect speakers that match the amplifier's impedance requirements (8 ohm types are pretty standard / common) and will operate with the amount of power (in watts) that the amp can supply. Make sure you're comparing watt ratings in similar units. "P-P" (Peak to Peak), "Peak" (or Max") and "RMS" are typical terms. RMS is the is the most common standard used, but as you'll see below, some manufacturers like to use different units to make their products seem to have more power than they actually do. You can convert easily between the terms like this:

200W P-P equals 100W peak, and also equals 71W RMS

"Peak" is 1/2 the value of "Peak to Peak" (P-P) and "RMS" which stands for Root Mean Squared, is 70.7% of Peak. 200W P-P sure sounds like it's more than 70W RMS - doesn't it? It's all pretty simple once you know. Lastly, the fictional unit "Music Power" can be anything really, but is often either Peak or P-P values. It's just more smoke and mirrors by some manufacturers.

I hope this helps and good luck. Please rate my reply. Thanks!

Another possible cause is the power requirements of the speakers to be driven properly. Larger speakers require more power to move the speaker coil and and cone. Connecting a speaker that requires 10 watts to be driven to an amplifier that provides up to 8 or even 10 watts will require that the amp be operating at 100% of capacity. An amplifier run like this will have a short life.

Connect speakers that match the amplifier's impedance requirements (8 ohm types are pretty standard / common) and will operate with the amount of power (in watts) that the amp can supply. Make sure you're comparing watt ratings in similar units. "P-P" (Peak to Peak), "Peak" (or Max") and "RMS" are typical terms. RMS is the is the most common standard used, but as you'll see below, some manufacturers like to use different units to make their products seem to have more power than they actually do. You can convert easily between the terms like this:

200W P-P equals 100W peak, and also equals 71W RMS

"Peak" is 1/2 the value of "Peak to Peak" (P-P) and "RMS" which stands for Root Mean Squared, is 70.7% of Peak. 200W P-P sure sounds like it's more than 70W RMS - doesn't it? It's all pretty simple once you know. Lastly, the fictional unit "Music Power" can be anything really, but is often either Peak or P-P values. It's just more smoke and mirrors by some manufacturers.

I hope this helps and good luck. Please rate my reply. Thanks!

May 12, 2011 | Sony CDX-C5005 CD Player

Assuming your two point coordinates are of the form (x1, y1) and (x2, y2).

There are two possible methods:

You can use the slope formula which is commonly known as "rise over run." To do this: slope = (y2 - y1) / (x2 - x1) This means that the vertical distance covered by the two points divided by the horizontal distance covered by the two points is equal to the slope.

You can use your calculator's linear regression capabilities:

First step: Press the STAT button (next to the arrow keys toward the top right of your calculator).

Second: Select the first option, Edit...

Third: Under L1, enter your first x value, press enter, enter your second x value, press enter again.

Fourth: Under L2, enter your first y value, press enter, enter your second y value, press enter again.

Fifth: Press the STAT button again. Press the right arrow button to highlight CALC.

Sixth: Select the fourth option LinReg(ax+b).

Seventh: Press 2ND then 1 (L1 should show up on your screen). Then press the comma button (right above the number 7). Press 2ND then 2 (L2 should show up on your screen). Press ENTER.

Eighth: Once you press ENTER, several values will appear. The a value is the slope of the two coordinates.

There are two possible methods:

You can use the slope formula which is commonly known as "rise over run." To do this: slope = (y2 - y1) / (x2 - x1) This means that the vertical distance covered by the two points divided by the horizontal distance covered by the two points is equal to the slope.

You can use your calculator's linear regression capabilities:

First step: Press the STAT button (next to the arrow keys toward the top right of your calculator).

Second: Select the first option, Edit...

Third: Under L1, enter your first x value, press enter, enter your second x value, press enter again.

Fourth: Under L2, enter your first y value, press enter, enter your second y value, press enter again.

Fifth: Press the STAT button again. Press the right arrow button to highlight CALC.

Sixth: Select the fourth option LinReg(ax+b).

Seventh: Press 2ND then 1 (L1 should show up on your screen). Then press the comma button (right above the number 7). Press 2ND then 2 (L2 should show up on your screen). Press ENTER.

Eighth: Once you press ENTER, several values will appear. The a value is the slope of the two coordinates.

Feb 03, 2011 | Texas Instruments TI-84 Plus Silver...

Using elementary algebria in the **binomial theorem, **I expanded the power **(***x* + *y*)^n into a sum involving terms in the form a x^b y^c. The coefficient of each term is a positive integer, and the sum of the exponents of *x* and *y* in each term is **n**. This is known as binomial coefficients and are none other than combinatorial numbers.

**Combinatorial interpretation:**

Using** binomial coefficient (n over k)** allowed me to choose** ***k* elements from an **n**-element set. This you will see in my calculations on my Ti 89. This also allowed me to use **(x+y)^n** to rewrite as a product. Then I was able to combine like terms to solve for the solution as shown below.

(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

**This also follows Newton's generalized binomial theorem:**

**Now to solve using the Ti 89.**

Using

(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

**Using sigma notation, and factorials for the combinatorial numbers, here is the binomial theorem:**

**The summation sign is the general term. Each term in the sum will look like that as you will see on my calculator display. Tthe first term having k = 0; then k = 1, k = 2, and so on, up to k = n. **

Jan 04, 2011 | Texas Instruments TI-89 Calculator

You'll want to use the IF formula, its syntax goes like this: =IF(condition to be met,value if true,value if false)

If you want to use text for the true/false values, you'll need to put the term in quotes.

Example, lets say you want to know if 260+G$2+F60+$X$99+$A25 is equal to 1024, then the formula would be: =IF(260+G$2+F60+$X$99+$A25=1024,"True","False")

If you want to use text for the true/false values, you'll need to put the term in quotes.

Example, lets say you want to know if 260+G$2+F60+$X$99+$A25 is equal to 1024, then the formula would be: =IF(260+G$2+F60+$X$99+$A25=1024,"True","False")

Dec 29, 2008 | Microsoft Office 2003 Basic Edition...

Goal Seek Solver and Sceanerios are a Part of What if Data Analysis Tools.

Goal Seek find the Expected Change in terms of value to a calculated Items.

For Example if you have a sales data for the year 2007 where Profit is 350000 and you want to make it 500000 for the year 2008 so what changes you will do in Product cost or Product Price this you will find with Goal Seek. It is also known as Back calculation. It has some restrictions which is overcome by Solver. But before doing this type of calculation use Sceanerios to store different Calculated values using Goal Seek and Solver. You dont have to add these values in different sheets all the values stored as a sceanerios. so You can show different Predections to the customers without moving around the Sheets.

Goal Seek find the Expected Change in terms of value to a calculated Items.

For Example if you have a sales data for the year 2007 where Profit is 350000 and you want to make it 500000 for the year 2008 so what changes you will do in Product cost or Product Price this you will find with Goal Seek. It is also known as Back calculation. It has some restrictions which is overcome by Solver. But before doing this type of calculation use Sceanerios to store different Calculated values using Goal Seek and Solver. You dont have to add these values in different sheets all the values stored as a sceanerios. so You can show different Predections to the customers without moving around the Sheets.

Nov 17, 2008 | Microsoft Computers & Internet

the 6th term of an A.P is equal to 2.the value of common difference of the A.P which makes the product a1a4a5 least is given by

Aug 06, 2008 | SoftMath Algebrator - Algebra Homework...

96 people viewed this question

Usually answered in minutes!

where do i put the parenthesis to make this problem true: 6x4-3=8

There is no solution to this question unless you change the math rules.

(6x4)+3=21

6x(4-3)=6

(6x4-3)=21

×