Question about HP PSC 1210 All-In-One InkJet Printer

# Carriage slams from side to side every time the printers is turned on

Any solutions?

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The encodder strip is loose or broken/damaged.check out.

Posted on Aug 15, 2008

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Posted on Jan 02, 2017

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## Related Questions:

### What volume of a 2.50m solution of hydrochrolic acid is required to prepare 2.0 litres of a 0.30m solution?

I need to be sure what you meant by the m symbol: M or m. The first is used for molarity and the latter for molality. If it is molality we do need to know the masses per unit volume for the solutions (the so-called densities)

However if you meant 2.5 M and 0.3 M, then the problem is readily solved. I 'll take a step by step method.
2.50 M means that the original solution contains 2.5 mol of solute per 1 L of solution. Let x be the volume of the solution.
The amount of solute ( expressed as a number of moles) isAmount of solute in original solution (in mol)=2.5 (mol/L)*x (L)
Now consider the final solution.
The amount of solute in the final solution is given by:Amount of solute (in mol) =0.3 mol/L*2 L=0.6 mol
However, this last value is exactly the amount of solute the original solution, because you are just putting it in a bigger volume (dilution)
Equating the two amounts of solute we get
2.5 x=0.6 (in mol) and
x=0.6/2,5=0.24 L=240 mL
When concentrations are given in molar units, the foregoing reasoning can be summarized as
initial concentration (c_i) * initial volume (V_i)=final concentration (c_f)*final volume (V_f) or more simply
c_i*V_i=c_f*V_f
Using the formula to find the initial volume
V_i=(c_f*V_f)/c_i=(0.3 *2)/2.5=0.24
The starting volume is 0.24 L or 240 mL

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