Question about Casio FX-115ES Scientific Calculator

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Surely you are joking, Mr Feynman? (This is itself a reference to a famous book.)

Anyway, your question has nothing to do with this puny Scientific calculator. You cannot even do it on the back of an envelop. It requires a lot of elbow grease, pencil and paper.

Here is a link to a Course Wiki from the Florida State University where you can have all the details. You will have to supply the form of your time-dependent perturbation and be ready to iterate.

Good luck.

Posted on May 23, 2011

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Posted on Jan 02, 2017

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Take this equation y = 3x + 4

As written x can be any value, and y depends on what that is. So y is the dependent variable here.

Of course you can write it the other way round, x = (y-4)/3 and then it appear that x is the dependent variable.

So in modelling a real situation it is important to arrange things so that the truly independent variable is modelled by "x", on the RHS

Say you were modelling fuel consumption as a function of speed. It becomes obvious that fuel consumption depends quite a bit on speed, so it should be the "y" variable.

As written x can be any value, and y depends on what that is. So y is the dependent variable here.

Of course you can write it the other way round, x = (y-4)/3 and then it appear that x is the dependent variable.

So in modelling a real situation it is important to arrange things so that the truly independent variable is modelled by "x", on the RHS

Say you were modelling fuel consumption as a function of speed. It becomes obvious that fuel consumption depends quite a bit on speed, so it should be the "y" variable.

Aug 21, 2014 | Computers & Internet

First of all you equation is not one : it has nothing on the right side of the = sign. But to answer the general question let us write the equation as **50+25x-5y=0**

**X-intercept (also know as roots) There may be several**

Definition: X-intercepts are those values of the independent variable x**for which y=0**. For a straight line there con be at most 1 x-intercept.

To find the intercept, set y=0 in the equation of the line and solve for x

50+25x-5(0)=0 or 50+25x=0. The solution is** x=-(50/25)=-2**

**Y-intercept (also know as the initial value.** There can only be 1 y-intercept, otherwise the expression does not represent a function.

Definition: It is the value of the dependent variable y when x=0 (where the function crosses the y-axis

To find it, set the x-value to 0 in the equation of the line.

**50+25x-5y=0**

50+25(0)-5y=0, or 50-5y=0. The solution is**y=50/5=10**

The straight line cuts the x-axis at the point (-2, 0) and the y-axis at the point (0,10)

Definition: X-intercepts are those values of the independent variable x

To find the intercept, set y=0 in the equation of the line and solve for x

50+25x-5(0)=0 or 50+25x=0. The solution is

Definition: It is the value of the dependent variable y when x=0 (where the function crosses the y-axis

To find it, set the x-value to 0 in the equation of the line.

50+25(0)-5y=0, or 50-5y=0. The solution is

The straight line cuts the x-axis at the point (-2, 0) and the y-axis at the point (0,10)

Jan 28, 2014 | Computers & Internet

See if you have an

Sep 30, 2013 | Office Equipment & Supplies

Your scientific calculator is unable to solve complex equation with complex coefficients. You should try to solve by hand directly using the quadratic formula or by factoring the polynomial in z

failing that, another way would be to set z=x+iy, substitute this for z, carry out the algebra and try to separate real and imaginary parts. But your two equations will constitute a system of two quadratic equations. I am not aware of any general method to solve coupled nonlinear equations.

Good luck.

failing that, another way would be to set z=x+iy, substitute this for z, carry out the algebra and try to separate real and imaginary parts. But your two equations will constitute a system of two quadratic equations. I am not aware of any general method to solve coupled nonlinear equations.

Good luck.

Dec 20, 2012 | Casio FX-115ES Scientific Calculator

This calculator is unable to factor a polynomial expression.

In general there are a few factoring methods

In general there are a few factoring methods

**Factor by grouping terms****Factor by completing the square**(quadratic polynomial)**Factor by finding two integers such their sum is equal to the coefficient of the middle term, and their product is equal to the third (constant term)**. This is valid for a quadratic polynomial where the leading coefficient (of the x^2 term) is equal to 1.**X^2+SX+P**

Jul 31, 2012 | Casio FX-115ES Scientific Calculator

deSolve( ) solves differential equations. The general syntax is deSolve(1stOR2ndOrderODE, Var, depVar). The first argument must be a first order or second order differential equation, the second argument is the independent variable, and the third is the dependent variable (the name of the function you are trying to obtain.)

Your command does not have a differential equation, and it does not have the dependent variable.

Your command does not have a differential equation, and it does not have the dependent variable.

Sep 18, 2011 | Texas Instruments TI-89 Calculator

This expression 5x^2+15x+3 is not an equation, therefore it can have any value depending on the value of x. You have to make it an equation before looking for the particular value of x that satisfy your equation **5x^2+15x+3 =0**

This calculator cannot solve equations because it does not have an equation solver.

This calculator cannot solve equations because it does not have an equation solver.

Dec 15, 2010 | Sharp ELW535 Calculator

I assume that if you want to input the equation it is with the intent to solve it. If that be the case then what follows will help you input and solve any equation (linear, quadratic, trig, etc.)

Make sure the calculator angle unit is the same as your problem requires (degree, radian, grad). Here are some screen capture to help you. Change the equation to yours.

To enter the equation in screen above, use the right arrow.

You have to enter an initial guess on line X=, a default value may be supplied by calculator: It depends on last value stored in X. Once a value is entered press the F6 key to SOLV

Press F1: Rept if you want to solve another equation.

Make sure the calculator angle unit is the same as your problem requires (degree, radian, grad). Here are some screen capture to help you. Change the equation to yours.

To enter the equation in screen above, use the right arrow.

You have to enter an initial guess on line X=, a default value may be supplied by calculator: It depends on last value stored in X. Once a value is entered press the F6 key to SOLV

Press F1: Rept if you want to solve another equation.

Nov 13, 2010 | Casio FX-9860G Graphic Calculator

Hello,

First of all, you have to set the mode to EQUATION by pressing [MODE][5:Equation]. When you do that, you are offered 4 choices of equation types to solve.

PART 1 a_n*X+b_n*Y=C_n.

In this type, you have only 2 unknows, X, Y, the others are coefficients. When this mode is selected, you are given access to a what looks like a matrix.

The top row, inaccessible to you, displays headings a, b, c.

The first column, also inaccessible to you numbers the lines as (1 and 2)

First line

Enter the coefficient of X in the first equation, a_1, and press [=] Cursor moves to the dark rectangle under the b heading.

Enter the coefficient of Y, (b_1) in the first equation and press [=] Cursor moves to the dark rectangle under heading c.

Enter the constant term in the first equation, C_1, and press [=]

At this stage you have finished entering the coefficients and constant term of the first linear equation of your system, namely

a_1*X+b_1*Y= C_1

After you enter C_1 and press [ENTER] the cursor moves to the

Second Line

On this line, just as in the previous one, you enter a_2, b_2 and c_2 Once you finish entering all coefficients and constant terms you press [ENTER].

Calculator does its thing and returns with a solution and displays at the top left of the screen

X=

and on the bottom right the value for X ( a fraction or a decimal number)

Press [=] again and the screen displays the value of the second unknown Y.

If you press [=] a third time the claculator takes you back to the entry screen to modifiy coefficients and constant terms.

Exemple a_1=6 b_1=3 c_1=7 a_2=5 b_2=8.3 c_2=1

X= 19/12 To convert it to decimal press [S<->D] to get 1.58333 Y=-5/6 To convert it to decimal press [S<->D] to get -0.8333333

PART B a_n*X+b_n*Y+c_n*Z =D_n This is a linear system in 3 unknowns X, Y, X.

It requires

a_1, b_1, c_1, and d_1

a_2, b_2, c_2, and d_2

a_3, b_3, c_3 and d_3.

Procedure to enter the coefficients and constant terms is the same as above, but due to the limited screen, you have to use right arrow to access the places where you enter d_1, d_2. d_3.

When finished you have to press [=] 1 time to get X, a second time to get Y, and a third time to get Z.

PART C aX^2 + bX +c=0 (quadratic equation)

You enter a, b, and c in the template.

When finished press[ENTER] once to get X1, and a second time to get X2.

PART D aX^3 +bX^2+cX+d =0 (cubic equation)

Same procedure as Part C, except that you have to enter a, b, c, and d in template and press [=] 1 time to get X1, a second time to get X2, and a third time to get X3.

Hope it helps.

PS to the power that be of this site, if you are listening: We ought to have prompts to confirm the post before validating it. We ought to be able to correct typos, errors; to amend what we entered.

First of all, you have to set the mode to EQUATION by pressing [MODE][5:Equation]. When you do that, you are offered 4 choices of equation types to solve.

PART 1 a_n*X+b_n*Y=C_n.

In this type, you have only 2 unknows, X, Y, the others are coefficients. When this mode is selected, you are given access to a what looks like a matrix.

The top row, inaccessible to you, displays headings a, b, c.

The first column, also inaccessible to you numbers the lines as (1 and 2)

First line

Enter the coefficient of X in the first equation, a_1, and press [=] Cursor moves to the dark rectangle under the b heading.

Enter the coefficient of Y, (b_1) in the first equation and press [=] Cursor moves to the dark rectangle under heading c.

Enter the constant term in the first equation, C_1, and press [=]

At this stage you have finished entering the coefficients and constant term of the first linear equation of your system, namely

a_1*X+b_1*Y= C_1

After you enter C_1 and press [ENTER] the cursor moves to the

Second Line

On this line, just as in the previous one, you enter a_2, b_2 and c_2 Once you finish entering all coefficients and constant terms you press [ENTER].

Calculator does its thing and returns with a solution and displays at the top left of the screen

X=

and on the bottom right the value for X ( a fraction or a decimal number)

Press [=] again and the screen displays the value of the second unknown Y.

If you press [=] a third time the claculator takes you back to the entry screen to modifiy coefficients and constant terms.

Exemple a_1=6 b_1=3 c_1=7 a_2=5 b_2=8.3 c_2=1

X= 19/12 To convert it to decimal press [S<->D] to get 1.58333 Y=-5/6 To convert it to decimal press [S<->D] to get -0.8333333

PART B a_n*X+b_n*Y+c_n*Z =D_n This is a linear system in 3 unknowns X, Y, X.

It requires

a_1, b_1, c_1, and d_1

a_2, b_2, c_2, and d_2

a_3, b_3, c_3 and d_3.

Procedure to enter the coefficients and constant terms is the same as above, but due to the limited screen, you have to use right arrow to access the places where you enter d_1, d_2. d_3.

When finished you have to press [=] 1 time to get X, a second time to get Y, and a third time to get Z.

PART C aX^2 + bX +c=0 (quadratic equation)

You enter a, b, and c in the template.

When finished press[ENTER] once to get X1, and a second time to get X2.

PART D aX^3 +bX^2+cX+d =0 (cubic equation)

Same procedure as Part C, except that you have to enter a, b, c, and d in template and press [=] 1 time to get X1, a second time to get X2, and a third time to get X3.

Hope it helps.

PS to the power that be of this site, if you are listening: We ought to have prompts to confirm the post before validating it. We ought to be able to correct typos, errors; to amend what we entered.

Oct 11, 2009 | Casio FX-115ES Scientific Calculator

I assume you are speaking of solving a system of equations with a number of unknowns. If not, please correct me. Here's an example in practice:

If you have a system of 3 equations with 3 unknowns, you would set up your matrix so that the coefficients of each variable for a particular equation are on one row. So, given equations x + y + z = 0, 2x + 3y - 4z = 1, x + -z = -1 you would type the following into your calculator: [[1,1,1,0][2,3,-4,1][1,0,-1,-1]] and press enter to make sure you typed it correctly. notice that in the third row there is a zero, since we have zero time y for the third equation. Then row-reduce the matrix (2nd > 5 > 4 > 4 or in the CATALOG as rref). You should get out the matrix [[1,0,0,-1][0,1,0,1][0,0,1,0]]. This says that x=-1 y = 1 z=0 since my first column contained the coefficients for the x variable, the second for the y variable, and the third for the z variable. The last column contains the solution, the part on the other side of the equals sign.

Hope this helps! For more reading (from someone else; I just made this one up), check out the Wikipedia articles on Gaussian elimination and Systems of linear equations

If you have a system of 3 equations with 3 unknowns, you would set up your matrix so that the coefficients of each variable for a particular equation are on one row. So, given equations x + y + z = 0, 2x + 3y - 4z = 1, x + -z = -1 you would type the following into your calculator: [[1,1,1,0][2,3,-4,1][1,0,-1,-1]] and press enter to make sure you typed it correctly. notice that in the third row there is a zero, since we have zero time y for the third equation. Then row-reduce the matrix (2nd > 5 > 4 > 4 or in the CATALOG as rref). You should get out the matrix [[1,0,0,-1][0,1,0,1][0,0,1,0]]. This says that x=-1 y = 1 z=0 since my first column contained the coefficients for the x variable, the second for the y variable, and the third for the z variable. The last column contains the solution, the part on the other side of the equals sign.

Hope this helps! For more reading (from someone else; I just made this one up), check out the Wikipedia articles on Gaussian elimination and Systems of linear equations

May 03, 2009 | Texas Instruments TI-84 Plus Calculator

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