Question about Computers & Internet

1 Answer

C++ program a program to find the binomial coefficient using simle method

Posted by on

1 Answer

  • Level 1:

    An expert who has achieved level 1.

  • Contributor
  • 1 Answer

*
**
***
****
******
*****
****
***
**
*
***
****
*****
******
*******
******
*****
****
***
**
*

Posted on Aug 13, 2008

1 Suggested Answer

6ya6ya
  • 2 Answers

SOURCE: I have freestanding Series 8 dishwasher. Lately during the filling cycle water hammer is occurring. How can this be resolved

Hi,
a 6ya expert can help you resolve that issue over the phone in a minute or two.
best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).
click here to download the app (for users in the US for now) and get all the help you need.
goodluck!

Posted on Jan 02, 2017

Add Your Answer

Uploading: 0%

my-video-file.mp4

Complete. Click "Add" to insert your video. Add

×

Loading...
Loading...

Related Questions:

1 Answer

How to do binomial coefficients


In run scree, press the OPTN key, Press F6>. In the next page press F3Prob. The combination tab is above the F3 key

6ba3e316-0d7c-43e2-b626-3a664cbedd06.png

Jul 18, 2014 | Casio Office Equipment & Supplies

1 Answer

Umax astra 1600u driver


try install program Simple Scan I use linux mint 17 lxde and my epson perfection 1650 work automaticly with Simle Scan Linux is unix program as Mac OSX i hope it will work too.

Jul 17, 2014 | Office Equipment & Supplies

1 Answer

Demonstrate how to multiply two binomials


Try to seek these: By using the suggested format:
Suggested su
  1. Adding and Subtracting Binomials
    • 1

      Arrange each term in each binomial in order of degree from greatest to least. The degree of a binomial is the exponent attached to the term. For example, 4x^2 is a second degree term.

    • 2

      Multiply each term in the binomial that is being subtracted by -1 to turn it into an addition problem. For example, the problem (8x^2 + 8) - (x^2 - 2) becomes (8x^2 + 8) + (-x^2 + 2).

    • 3

      Combine like terms. In the example problem, the x^2 terms are combined and the constant terms are combined, yielding (8x^2 + 8) + (-x^2 + 2) = 7x^2 + 10.

    Multiplying Binomials
    • 4

      Understand the F.O.I.L. method. F.O.I.L. is an acronym standing for first, outside, inside and last. It means that you multiply the first number of the first binomial by the first number of the second, then the numbers on the outside (the first term of the first binomial by the second term of the second binomial) and so on. This ensures that both numbers in the first binomial are multiplied by both numbers in the second.

    • 5

      Use the F.O.I.L. method to multiply the two binomials together. For example, (3x + 4)(3x - 4) = 9x^2 +12x - 12x - 16. Notice that -12x is the product of the outside terms and -16 is the product of the last terms, 4 and -4.

    • 6

      Simplify. There will almost always be like terms to combine. In the example, 12x and -12x cancel out, yielding the answer 9x^2 - 16.

    Dividing Binomials
    • 7

      Use the distributive property to divide both terms in the binomial by the monomial divisor. For example, (18x^3 + 9x^2) / 3x = (18x^3 / 3x) + (9x^2 / 3x).

    • 8

      Understand how to divide by a term. If you are dividing a higher order term by a lower order term, you subtract the exponent. For example, y^3/y = y^2. The number part of each term is handled like any other division problem. For example, 20z / 4 = 5z.

    • 9

      Divide each term in the binomial by the divisor; (18x^3 / 3x) + (9x^2 / 3x) = 6x^2 + 3x.

May 10, 2014 | Computers & Internet

1 Answer

Texas 30XIIB binomial cdf


The only known equation for the cumulative binomial distribution is the sum of the individual binomial probabilities. Some more sophisticated (and more expensive) calculators have that equation built in, but the 30xii does not.

If n>30 and n*p>5 and n*(1-p)>5 then you can approximate the cumulative binomial with the normal probability function, but again the 30xii does not have that built in.

Apr 14, 2014 | Texas Instruments TI-30 XIIS Calculator

1 Answer

(3n+2)(n+3)


To multiply binomials use the mnemonic FOIL
  1. Multiply the FIRST members of the two binomials: 3n*n=3n^2
  2. Multiply the OUTER members of expression when read from left (3n) to right (3) =9n
  3. Multiply the INNER members 2 *n=2n
  4. Multiply the LAST members of the binomials 2*3=6
  5. Add all the products 3n^2+ 9n+2n+6,
then combine the two like-terms 9n+2n=11n
Result is 3n^2+11n+6
Seriously now: what does this have to do with Printers and Copiers?

Sep 21, 2013 | Office Equipment & Supplies

1 Answer

Definition of special product in algebra types and example of special product in algebra


Product means the result you get after multiplying.
In Algebra xy means x multiplied by y
Likewise when you see (a+b)(a-b) it means (a+b) multiplied by (a-b), which we will be using a lot here!
Special Binomial Products So when you multiply binomials you get ... Binomial Products
And we are going to look at three special cases of multiplying binomials ... so they are Special Binomial Products.
1. Multiplying a Binomial by Itself What happens when you square a binomial (in other words, multiply it by itself) .. ?

(a+b)2 = (a+b)(a+b) = ... ?

The result:

(a+b)2 = a2 + 2ab + b2
You can easily see why it works, in this diagram:

x-y-2-diagram.gif
2. Subtract Times Subtract And what happens if you square a binomial with a minus inside?

(a-b)2 = (a-b)(a-b) = ... ?

The result:

(a-b)2 = a2 - 2ab + b2
3. Add Times Subtract And then there is one more special case... what if you multiply (a+b) by (a-b) ?

(a+b)(a-b) = ... ?

The result:

(a+b)(a-b) = a2 - b2
That was interesting! It ended up very simple.
And it is called the "difference of two squares" (the two squares are a2 and b2).
This illustration may help you see why it works:
apb-amb-why.gif a2 - b2 is equal to (a+b)(a-b) Note: it does not matter if (a-b) comes first:

(a-b)(a+b) = a2 - b2
The Three Cases Here are the three results we just got:
(a+b)2 = a2 + 2ab + b2 } (the "perfect square trinomials") (a-b)2 = a2 - 2ab + b2 (a+b)(a-b) = a2 - b2 (the "difference of squares") Remember those patterns, they will save you time and help you solve many algebra puzzles.
Using Them So far we have just used "a" and "b", but they could be anything.
Example: (y+1)2
We can use the (a+b)2 case where "a" is y, and "b" is 1:

(y+1)2 = (y)2 + 2(y)(1) + (1)2 = y2 + 2y + 1

Example: (3x-4)2
We can use the (a-b)2 case where "a" is 3x, and "b" is 4:

(3x-4)2 = (3x)2 - 2(3x)(4) + (4)2 = 9x2 - 24x + 16

Example: (4y+2)(4y-2)
We know that the result will be the difference of two squares, because:

(a+b)(a-b) = a2 - b2
so:

(4y+2)(4y-2) = (4y)2 - (2)2 = 16y2 - 4
Sometimes you can recognize the pattern of the answer:
Example: can you work out which binomials to multiply to get 4x2 - 9
Hmmm... is that the difference of two squares?
Yes! 4x2 is (2x)2, and 9 is (3)2, so we have:

4x2 - 9 = (2x)2 - (3)2
And that can be produced by the difference of squares formula:

(a+b)(a-b) = a2 - b2
Like this ("a" is 2x, and "b" is 3):

(2x+3)(2x-3) = (2x)2 - (3)2 = 4x2 - 9
So the answer is that you can multiply (2x+3) and (2x-3) to get 4x2 - 9

Jul 26, 2011 | Computers & Internet

2 Answers

How to solve foil method


The FOIL Method is a process used in algebra to multiply two binomials. The lesson on the Distributive Property, explained how to multiply a monomial or a single term such as 7 by a binomial such as (4 + 9x).
1.gif But, what if there was a binomial instead of a single term outside of the parentheses? That is, what if a binomial was being multiplied by another binomial? An example of this is given below.
2.gif
FOIL stands for:
First - Multiply the first term in each set of parentheses Outer - Multiply the outer term in each set of parentheses Inner - Multiply the inner term in each set of parentheses Last - Multiply the last term in each set of parentheses Now let's give it a try in our problem. We'll start by multiplying the first term in each set of parentheses and then marking down the answer below the problem.
3.gif Now we will multiply the outer terms and again mark down the answer below the problem.
4.gif And the Inners.
5.gif And finally the last terms.
6.gif

Jun 12, 2011 | Computers & Internet

2 Answers

TI-89 Titanium: I want to solve a Binomial Theorem problem (x+y)^6 how would i go about solving this in the calculator?


Using elementary algebria in the binomial theorem, I expanded the power (x + y)^n into a sum involving terms in the form a x^b y^c. The coefficient of each term is a positive integer, and the sum of the exponents of x and y in each term is n. This is known as binomial coefficients and are none other than combinatorial numbers.

Combinatorial interpretation:

Using binomial coefficient (n over k) allowed me to choose k elements from an n-element set. This you will see in my calculations on my Ti 89. This also allowed me to use (x+y)^n to rewrite as a product. Then I was able to combine like terms to solve for the solution as shown below.
(x+y)^6= (x+y)(x+y)(x+y)(x+y)(x+y)(x+y) = x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6

This also follows Newton's generalized binomial theorem:


oneplusgh_15.jpg
Now to solve using the Ti 89.


Using sigma notation, and factorials for the combinatorial numbers, here is the binomial theorem:

oneplusgh.gif

The summation sign is the general term. Each term in the sum will look like that as you will see on my calculator display. Tthe first term having k = 0; then k = 1, k = 2, and so on, up to k = n.
Notice that the sum of the exponents (n ? k) + k, always equals n.



oneplusgh_26.jpg


The summation being preformed on the Ti 89. The actual summation was preformed earlier. I just wanted to show the symbolic value of (n) in both calculations. All I need to do is drop the summation sign to the actual calculation and, fill in the term value (k), for each binomial coefficient.



oneplusgh_18.jpg

This is the zero th term. x^6, when k=0. Notice how easy the calculations will be. All I'm doing is adding 1 to the value of k.


oneplusgh_19.jpg

This is the first term or, first coefficient 6*x^5*y, when k=1.
Solution so far = x^6+6*x^5*y



oneplusgh_20.jpg


This is the 2nd term or, 2nd coefficient 15*x^4*y^2, when k=2.
Solution so far = x^6+6*x^5*y+15*x^4*y^2



oneplusgh_27.jpg



This is the 3rd term or, 3rd coefficient 20*x^3*y^3, when k=3.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3



oneplusgh_28.jpg



This is the 4th term or, 4th coefficient 15*x^2*y^4, when k=4.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4



oneplusgh_21.jpg


This is the 5th term or, 5th coefficient 6*x*y^5, when k=5.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5



oneplusgh_22.jpg

This is the 6th term or, 6th coefficient y^6, when k=6.
Solution so far = x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6



oneplusgh_23.jpg

Putting the coefficients together was equal or, the same as for when I used the expand command on the Ti 89.

binomial coefficient (n over k) for (x+y)^6
x^6+6*x^5*y+15*x^4*y^2+20*x^3*y^3+15*x^2*y^4+6*x*y^5+y^6












Jan 04, 2011 | Texas Instruments TI-89 Calculator

1 Answer

NCr + nCr-1 = n+1Cr prove it?


The identity (n+1)Cr=nCr+nC(r-1), valid if n>=1 and 1=0. These facts embody the construction of Pascal's triangle and let you prove by induction (on n) that nCr is always an integer since it's either 1 or it's the sum of two integers.

You can also think of the combinatorial definition of nCr, the number of r-subsets of an n-set. This is definitely an integer. Of course then you'd have to prove that the factorial expression for nCr is correct...


The nCr are binomial coefficients with the property that n+1Cr = nCr-1 + nCr (think of Pascal's Triangle) with nCn = 1 = nC0. Since 0C0 = 1 it follows that all nCr are integers

Dec 06, 2010 | Dell Computers & Internet

1 Answer

I was told that, to do binomial distributions on a ti-86, I would need to hit 2nd Math, then More, and I should see something that says STAT and go from there to get to DIST and Binomi. I see nothing...


Hello,

Sorry, but you information is wrong, to find the binomial distribution use the PROB menu not the STAT menu. Its name is randBi
[2nd][MATH][F2:PROB] scroll right.
Hope it helps.

Oct 10, 2009 | Texas Instruments TI-86 Calculator

Not finding what you are looking for?
Computers & Internet Logo

Related Topics:

30 people viewed this question

Ask a Question

Usually answered in minutes!

Top Computers & Internet Experts

Brian Sullivan
Brian Sullivan

Level 3 Expert

27725 Answers

kakima

Level 3 Expert

101580 Answers

David Payne
David Payne

Level 3 Expert

14160 Answers

Are you a Computer and Internet Expert? Answer questions, earn points and help others

Answer questions

Manuals & User Guides

Loading...