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Posted on May 02, 2011

How solve sin square theta=0.0454 - Computers & Internet

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  • Posted on May 02, 2011
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Shift sin 0.0454, and square you answer

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0helpful
1answer

How to type sin theta and cosine theta in casio fx-85MS

Since this calculator cannot perform symbolic manipulations (algebra) you never need to type in sin(theta) or cos(theta). To calculate the sine of an angle (whatever the name of the angle may be) just press the sin key followed by an angle value and the function will be calculated. same thing with any other trigonometric function.
Make sure that the angle units is set to the unit required by your calculation: degree, radian, or grad.
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Complex polar angle scientific

{r, theta} is equivalent to r*exp(i*theta)=r*cos(theta) +i*sin(theta)
That is all you need.
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1answer

X= disappeared from the Y=

You have several types of graphs
Function graphs
Y_1=f(x), Y1=3X^2-4, [X, T, Theta, n] key types X
Polar graphs r=F(theta), r=r_o*ln(theta). [X, T, Theta, n] types Theta
Parametric graphs X_1=f(T) and Y_1=g(T). [X.T, Theta, n] types T
Examples: X_1= cos(T). Y_1= 2(1--sin(T))
Sequence graphs u_n+1= f(u_n), [X,T,Theta,n] types n
0helpful
1answer

X= disappeared

You have several types of graphs
Function graphs
Y_1=f(x), Y1=3X^2-4, [X, T, Theta, n] key types X
Polar graphs r=F(theta), r=r_o*ln(theta). [X, T, Theta, n] types Theta
Parametric graphs X_1=f(T) and Y_1=g(T). [X.T, Theta, n] types T
Examples: X_1= cos(T). Y_1= 2(1--sin(T))
Sequence graphs u_n+1= f(u_n), [X,T,Theta,n] types n
1helpful
2answers

How do you input arccos

Press 2nd SIN 3 2 / 1 4 5 ) =

Make sure you have the desired angular mode set before you do this.
0helpful
1answer

When i am graphing and I enter- Y1=Sin(theta) it does not graph it and says syntax error

When drawing function graphs of type Y1=, the name of the independent variable should be X
For polar graphs r=.., the independent variable is theta, while for parametric graphs it is T
To enter the default independent variable, press the key marked [X,Theta, T] . It will type in the correct name.
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1answer

Please help me change: 5 sin X - 3 Cos X to C sin (X - @) @ = theta

we can represent 5 sin X --3 cos X as

5.83 sin ( X - 30.96)

if you want steps please leave a comment and don't forget to vote for me thank you
0helpful
1answer

Can't transform from polar to rectangular

Hello,
The e is the same, it is the exponential. According to Euler's relation
e^(i theta) = cos(theta) + i sin(theta), where i is the imaginary unit.
When represented on the complex plane (x,iy) the point (cos(theta), sin(theta)) is at the extremity of a vector of length 1 and making an angle theta with the real axis.

In (plane) polar coordinates, a point is defined by the radius r, and the angle, theta, it makes with the x axis, measured in the trigonometric (counterclockwise) direction. It is structurally equaivalent to representing it in the complex plane as r*e^(i*theta). Since r is the measure ot is radius, and the theta is it argument (angle). The complex notation is used for its convenience when adding vectors (as is AC circuits)
That is the theory.
I am inserting a clipping from the book to show you how to convert between polar and rectangular coordinates.

d2af7da.jpg
0helpful
3answers

Trignometric problem

The answer is Square root of 2. ( ef5590434a387b3c4427e09d5b08baaf.png )
They way it works is :
sec theta at 45 degre is 1 over cosine of theta or
cosine of theta is square root of 2 over 2.
Therefore you have 1 over square root of 2 over 2.
After rationalization and simplification you should have ef5590434a387b3c4427e09d5b08baaf.png .
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