Here are a few ways to calculate your BTU's.
Get ready to use that algebra you thought you'd never use.
1 Ton = 12000 BTU's
400cubic feet per minute (CFM) = 1 Ton on standard ac units (300 is an absolute minnimum)
BTU's air heat = difference in temp. ( ∆T ) x 1.08 x CFM ∆T = BTU's / (1.08 x CFM) i.e. 65◦F entering your unit and 93◦F air leaving on a 12000BTU unit. ∆T = 28 CFM = 400 28 x 1.08 x 400 = 12096BTU's Another way... Electric heat calculations. BTU's = KW (killowatts) x 3413 Watts = Volts x Amps (single Phase) Most Homes)) Watts = Volts x Amps x Phase (this is for three phase units.)three wires and a ground)) 120 volts 30 amps single phase (common) 120 x 30.0 x 1 = 3600 or 3.6KW 3.6 x 3413 = 12286BTU's
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hundreds of variables such as building age, insulation, size and quality if windows, etc. Also how many people will be in the building at one time? VERY rough guess without knowing the answer to those questions is 40 tons, but do a heat loss and gain calculation to know for sure.
The Old Rule of Thumb is 400 square feet per ton, but you really need to do a heat load calculation to be safe. A lot of windows on the west or south side of the house will really increase your load and you may need a lot larger unit. Insulation also changes your load so you may be able to cool a larger area. You may be able to get the Heat Load Calculation Form either online or from Johnstone supply. They are on the internet.
It is a two ton system. and without doing a heat load Calculation and not knowing the heat load It would not be anything but a guess. But if everything is working properly and the system is clean and with good duct work, than it should be big enough for the size of your house.
It's not fixed formula, but as per basic rule, easy method tocalculate for motor capacitor.
(2650 X full load amps) divided by supply voltage(mentionedin capacitor)= MFD. (Plus or minus 10% to 15%)
Ex: 1 Tr which gives full load amps of 6 amps (2650 X 6)=15900 divided by 240(VAC)volts=66.25MFD
(10% to 15% plus or minus) You can fix 56.32 mfd or 76.18mfd
So, you can go in between 56.32 mfd and 76.18 mfd.
If you calculate of 440VAC capacitor, it will be 36 mfd.
Hope, it will be helpful . Thanks.
Could be several factors. Let me start by saying the unit you have should cool a room that totals around 450 square feet (Approx.).
If you do not know your rooms square footage just multiply the width of the room x the length of the room.
(e.g. 20' x 10' = 200 SF)
The above 450 SF is for a room with typical 8' ceilings. This is also a "Rule-Of-Thumb" measurement, as windows, doors, insulation, and air leakages (heat gain) also play a role in calculation of heat loads. But this will get you close....
If the room is larger than 450 S.F. in size then the unit is too small for this size room.
A rule of tumb for sizing is: every 600 square feet requires a ton (or 12,000 BTU) of cooling. Again, without doing a proper load calculation on the room or area being cooled, it is hard to be exact.
The other possibility is the unit is not operating as it should due to mechanical or other issues. This is hard to specify. COuld be refrigerant levels are low, coils dirty, or filter dirty.
Wow, You will need to get with a mechanical engineer, take a set of plans to him, he will need the cubic feet of the building, lighting load, ect.
This something that you don't want to wing it.
Constant 1.08 is a percentage of outside air being brought into a building or space you want to cool.
Most public or commercial building hvac use a outside air damper to allow fresh air to come in,allowing this air in will cause a constant load or heat.say its 92.f outside this 92.air will constantly be coming in and will need to be cooled.
There's a thumb rule in A/C air distribution. At 1 TR load, the air supply is about 400 CFM and the ideal diffuser size is 16" x 16" with an effective flow area of about 70%. Branch duct size for this outlet should be around 12" x 12".