Question about Casio FX-115ES Scientific Calculator

You can calculate the logarithm to any base by using the relationship

logb(x) = log(x)/log(b) = ln(x)/ln(b).

To calculate the log base 2 of 16, either divide the log of 16 by the log of 2 or the ln of 16 by the ln of 2.

Posted on Apr 07, 2011

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Posted on Jan 02, 2017

The inverse of log functions are power functions.

Inv of ln is exponential (e^x)

Inv of log in base 10 is 10^(x)

A function and its inverse usually share the same physical key. One function is accessed directly, the other by using the SHIFT or 2ndF key.

Inv of ln is exponential (e^x)

Inv of log in base 10 is 10^(x)

A function and its inverse usually share the same physical key. One function is accessed directly, the other by using the SHIFT or 2ndF key.

Aug 18, 2014 | Casio Office Equipment & Supplies

The inverse of log functions are power functions.

Inv of ln is exponential (e^x)

Inv of log in base 10 is 10^(x)

A function and its inverse usually share the same physical key. One function is accessed directly, the other by using the SHIFT or 2ndF key.

Inv of ln is exponential (e^x)

Inv of log in base 10 is 10^(x)

A function and its inverse usually share the same physical key. One function is accessed directly, the other by using the SHIFT or 2ndF key.

Aug 18, 2014 | Casio Office Equipment & Supplies

Rephrase the question please. It makes no sense, in particular what are all those TIMES for?

Combine all the logs using the rule log_2(a)+log_2(b)=log_2(a*b)

You get

log_2((x-10)(x-3)/x)=2=log_2(4)

Thus

(x-10)*(x-3)/x=4

Convert it to a quadratic equation (x^2-17x+30=0). the solutions are x=2 and x=15. That should not be too difficult to factor out 5*2=30 -15-2=-17.

Combine all the logs using the rule log_2(a)+log_2(b)=log_2(a*b)

You get

log_2((x-10)(x-3)/x)=2=log_2(4)

Thus

(x-10)*(x-3)/x=4

Convert it to a quadratic equation (x^2-17x+30=0). the solutions are x=2 and x=15. That should not be too difficult to factor out 5*2=30 -15-2=-17.

Jun 22, 2014 | Casio FX-300W Plus Calculator

Are you using the right type of logarithms? The calculator provides for two types: common (base 10) and natural (base e).

Could you post an example or two, with the answers you get and the expected answers?

Could you post an example or two, with the answers you get and the expected answers?

Apr 15, 2013 | Casio FX83ES Scientific Calculator

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Mar 23, 2011 | Casio FX-270W Calculator

4726 seems to already be on base 10

it's 4*10^3 + 7*10^2 + 2*10^1 + 6*10^0

it's 4*10^3 + 7*10^2 + 2*10^1 + 6*10^0

Mar 17, 2011 | Casio FX-115ES Scientific Calculator

Like you maybe know in math (I know!) log x base y = log x / log y

so what you need its just input your number (x for example) and log it, than divide log x by log 2.

just: log x / log 2. (by the way in calculator the meaning of log x is log x base 10 the default base is 10)

so what you need its just input your number (x for example) and log it, than divide log x by log 2.

just: log x / log 2. (by the way in calculator the meaning of log x is log x base 10 the default base is 10)

Jun 05, 2009 | Casio FX-300MS Calculator

Look it's simple in the calculator the default base is 10 so when you input log 3 its log 3 base 10 so:

maybe you know in math log x base y = log x / log y . So if you need log 3 base 3 its => log 3 / log 3 (by the way its 1)

maybe you know in math log x base y = log x / log y . So if you need log 3 base 3 its => log 3 / log 3 (by the way its 1)

Mar 27, 2009 | Casio FX-300MS Calculator

All calculators it's the same:

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

the default base in all the calculators is 10 so instead of writing log 4 base 2 you simply need to write log 4 / log 2

Hope you understand :)

log x base y = log x / log y

log (x*y) = log x + log y

log (x/y) = log x - log y

the default base in all the calculators is 10 so instead of writing log 4 base 2 you simply need to write log 4 / log 2

Hope you understand :)

Dec 16, 2008 | Casio FX-7400G Plus Calculator

In any scientific calculator log2(n) can be calculated with either ln or log function as
follows

Log2(n)= ln(n) / ln(2)

Or

Log2(n)=log(n) / log(2)

both will give nearly the same answers

Log2(n)= ln(n) / ln(2)

Or

Log2(n)=log(n) / log(2)

both will give nearly the same answers

Dec 08, 2007 | Casio FX-300MS Calculator

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