Question about Texas Instruments TI-84 Plus Calculator

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Press [math] [0] to put the calculator into equation solver. Then you input your equation in 0 = format. So, the equation x/3 - 1/5 = 4/3 would be input as 0 = x/3 - 1/5 - 4/3 . Then press [enter] .

Posted on Apr 05, 2011

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Posted on Jan 02, 2017

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Do you really need a calculator to solve a linear equation?

Let us see how to solve it without a calculator.

Remove the parentheses fronm the second term on the left : y-3

Use the distributive property on the last term on the right side -2y-6

Take the term -3 to the right side, changing its sign in the process (becomes +3)

Take the -2y term to the left making it +2y.

3y +2y=18+3-6 or 5y=15 and the answer is straightforward .

As to your Casio FX300ES, it cannot solve equations because it does not have an EQUATION calculation mode. The Casios FX-115ES and FX-991ES have an Equation Mode. If you use any of the two to solve an equation in one variable (linear, quadratic or other) the unknown is taken to be x by default. You would have to change the name of the variable from y to x.

Let us see how to solve it without a calculator.

Remove the parentheses fronm the second term on the left : y-3

Use the distributive property on the last term on the right side -2y-6

Take the term -3 to the right side, changing its sign in the process (becomes +3)

Take the -2y term to the left making it +2y.

3y +2y=18+3-6 or 5y=15 and the answer is straightforward .

As to your Casio FX300ES, it cannot solve equations because it does not have an EQUATION calculation mode. The Casios FX-115ES and FX-991ES have an Equation Mode. If you use any of the two to solve an equation in one variable (linear, quadratic or other) the unknown is taken to be x by default. You would have to change the name of the variable from y to x.

Sep 08, 2011 | Casio fx-300ES Calculator

On most calculators with a solver function, you can specify a starting value for the variable (in this case x) after pressing [Solve] but before pressing the = key.

To get the three solutions, try entering the function, pressing [Solve] then an estimated starting point (say 0.5 or 0.7) then [=]. This should show the +root2/2 result (ie 0.7071067812).

You should not need to enter the function again.

Follow this by pressing [Solve] again, then another estimated starting point (say -0.5 or -0.7) then [=] to get the -root2/2 result.

Similarly, then press [Solve] again, and enter another estimated starting point (say -2) then [=] to get the final solution of -3.

On Casio calculators, the [Solve] function is usually found by pressing [Shift][Calc]. Note that the solver function generally won't return numbers in surd form, only as a decimal value.

To get the three solutions, try entering the function, pressing [Solve] then an estimated starting point (say 0.5 or 0.7) then [=]. This should show the +root2/2 result (ie 0.7071067812).

You should not need to enter the function again.

Follow this by pressing [Solve] again, then another estimated starting point (say -0.5 or -0.7) then [=] to get the -root2/2 result.

Similarly, then press [Solve] again, and enter another estimated starting point (say -2) then [=] to get the final solution of -3.

On Casio calculators, the [Solve] function is usually found by pressing [Shift][Calc]. Note that the solver function generally won't return numbers in surd form, only as a decimal value.

Jul 07, 2011 | Office Equipment & Supplies

y = x -3

This is a linear problem- so the usual way to solve the graph would be to solve where x = 0 and y= 0

if you use the format y = slope (m) * x + y intercept (b)- you would set y = 0

at that point it would be 0 = x -3 x = 3 Therefore where y = 0, x = 3. In a graph, that would point to the coordinate (3,0) for the x-intercept. To find the y-intercept, you'd set x = 0 at that point, you'd have the y-intercept being (0,-3)

so if y = 1, x would be 4; if y = 2, x = 5, and so on

This is a linear problem- so the usual way to solve the graph would be to solve where x = 0 and y= 0

if you use the format y = slope (m) * x + y intercept (b)- you would set y = 0

at that point it would be 0 = x -3 x = 3 Therefore where y = 0, x = 3. In a graph, that would point to the coordinate (3,0) for the x-intercept. To find the y-intercept, you'd set x = 0 at that point, you'd have the y-intercept being (0,-3)

so if y = 1, x would be 4; if y = 2, x = 5, and so on

Jun 22, 2011 | Computers & Internet

There are a lot of ways to do it. One is to write a program using the cubic formula. If you just want the roots, use the solve() or zeros() functions.

For example, to find the zeros of x^2-6x^2+11x-6, enter

solve(x^3-6*x^2+11*x-6=0,x)

or

zeros(x^3-6*x^2+11*x-6,x)

Note that solve() has "=0" in it while zeros() does not.

solve() will give you an answer of

x=1 or x=2 or x=3

while zeros will give you an answer of

{1 2 3}

which plainly are the same thing, just expressed differently.

For example, to find the zeros of x^2-6x^2+11x-6, enter

solve(x^3-6*x^2+11*x-6=0,x)

or

zeros(x^3-6*x^2+11*x-6,x)

Note that solve() has "=0" in it while zeros() does not.

solve() will give you an answer of

x=1 or x=2 or x=3

while zeros will give you an answer of

{1 2 3}

which plainly are the same thing, just expressed differently.

May 09, 2011 | Texas Instruments TI-89 Calculator

pls solve this prblm

Feb 24, 2011 | Computers & Internet

explain to solve if 5+3+2=151022,9+2+4=183652,8+6+3=482466,5+4+5=202541,then what is 7+2+5=?

Nov 12, 2010 | Dual Exercise & Fitness

3(8)+3(5+3)=x(10+2) First add numbers in ()

3(8)+3(8)=x(12) Now multiply the numbers next to ()

24+24=12x Now add the 24 +24

48=12x Now we have to solve for x. 12x is actually 12 times x. in order to solve for x we have to do the opposite and divide by 12

__48__=__12__x

12 12

4=1x is the same as 4=x.

3(8)+3(8)=x(12) Now multiply the numbers next to ()

24+24=12x Now add the 24 +24

48=12x Now we have to solve for x. 12x is actually 12 times x. in order to solve for x we have to do the opposite and divide by 12

12 12

4=1x is the same as 4=x.

Mar 26, 2010 | Mathsoft Solving and Optimization...

Hi,

**You can use algebra to solve it.**

Use the fact that 4 =2^2 and 8=2^3 and substitute in the equation

(2^3)^x =2^(3*x)

Then** 2^(3*x)=2^2**

By equating the exponents

3x=2 and**x=2/3**

**Using the solve( function**

With the calculator physical keys between square brackets, and the SHIFTed or ALPHA keys between parentheses, type in the following

8 [^ ] [ALPHA] [ ) ] (X) [ALPHA][CALC] ( =) 4 [SHIFT][CALC] (SOLVE)

Once the foregoing command entered press [=]

Display shows**Solve for X** on top line and probably **0.000** on bottom line.

Press [.] 5 to give 0.5 as a guess for the value of x

After a moment the calculator returns with the solution.

The display shows three lines

1st Line: 8[^] X =4

2nd Line: X= 0.66666666

3rd Line : L-R =0.

Your solution is 0.6666666. In fact the exact solution is 2/3.

Hope it helps.

Thank you for using FixYa and for rating this solution.

Use the fact that 4 =2^2 and 8=2^3 and substitute in the equation

(2^3)^x =2^(3*x)

Then

By equating the exponents

3x=2 and

With the calculator physical keys between square brackets, and the SHIFTed or ALPHA keys between parentheses, type in the following

8 [^ ] [ALPHA] [ ) ] (X) [ALPHA][CALC] ( =) 4 [SHIFT][CALC] (SOLVE)

Once the foregoing command entered press [=]

Display shows

Press [.] 5 to give 0.5 as a guess for the value of x

After a moment the calculator returns with the solution.

The display shows three lines

1st Line: 8[^] X =4

2nd Line: X= 0.66666666

3rd Line : L-R =0.

Your solution is 0.6666666. In fact the exact solution is 2/3.

Hope it helps.

Thank you for using FixYa and for rating this solution.

Dec 03, 2009 | Casio FX-115ES Scientific Calculator

Hello,

The** solve(** is available through the CATALOG : [2nd][CATALOG], scroll down till you reach the command. Highlight it and press [ENTER]. The command echodes on main screen as **solve(** .

You complete the command by entering the expression (not the equation), the name of the variable you solve for, the initial guess , and { lower limit, upper limit} between curly brackets, and the closing parenthesis.

Exemple:

**solve ( Q^3-100, Q,0 {-50,50} ) [ENTER]**

It is implied that the expression is 0 (Q^3-100 =0), so you should not insert =0, otherwise you get an error. Here the lower limit is -50. You must use the change sign symbol (-) under the 3 key, not the regular MINUS.

Hope it helps.

The

You complete the command by entering the expression (not the equation), the name of the variable you solve for, the initial guess , and { lower limit, upper limit} between curly brackets, and the closing parenthesis.

Exemple:

It is implied that the expression is 0 (Q^3-100 =0), so you should not insert =0, otherwise you get an error. Here the lower limit is -50. You must use the change sign symbol (-) under the 3 key, not the regular MINUS.

Hope it helps.

Oct 14, 2009 | Texas Instruments TI-83 Plus Calculator

First to solve a problem, write it like this

solve(3/x-2+21/x^2-4=14/x+2,x)

Second, for inverse, do this (note the "y=" part)

solve(y=3x^2 -2x+1,x)

The calculator will rewrite the formula as x = ...

solve(3/x-2+21/x^2-4=14/x+2,x)

Second, for inverse, do this (note the "y=" part)

solve(y=3x^2 -2x+1,x)

The calculator will rewrite the formula as x = ...

Oct 23, 2007 | Texas Instruments TI-89 Calculator

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