Question about Canon PIXMA MP150 All-In-One InkJet Printer

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Please be advised that if the MP 150 is displaying the letter E followed by number 3, this would indicate a paper jam.However, if it is flashing E, then 3 and then another digit, an error requiring servicing might have occurred.Turn Off the machine and unplug the power cord of the machine from the power supply. After a few minutes, plug the power cord of the machine back in and turn On the machine. If the same error occurs, contact a Canon service representative

Posted on Mar 26, 2011

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Posted on Jan 02, 2017

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To solve a system of equations, there are two algebraic ways to solve them, one is by substitution, while the other is elimination.

1) 2a + 3b + 5 = 0

2) 2a + 4b + 10 = 0

-----------------------

-b -5 = 0 (subtract 2 from 1)

+b-b-5 = b

-5 = b

Substitute into 1) to solve for a.

2a + 3(-5) + 5 = 0

2a -15 + 5 = 0

2a -10 = 0

2a -10 + 10 = 10

2a = 10

---- ----

2 2

a=5

Substitute into 2) to check if we did it correctly.

2(5) + 4(-5) + 10 = 0

10 -20 + 10 = 0

0=0

Good luck.

Paul

1) 2a + 3b + 5 = 0

2) 2a + 4b + 10 = 0

-----------------------

-b -5 = 0 (subtract 2 from 1)

+b-b-5 = b

-5 = b

Substitute into 1) to solve for a.

2a + 3(-5) + 5 = 0

2a -15 + 5 = 0

2a -10 = 0

2a -10 + 10 = 10

2a = 10

---- ----

2 2

a=5

Substitute into 2) to check if we did it correctly.

2(5) + 4(-5) + 10 = 0

10 -20 + 10 = 0

0=0

Good luck.

Paul

Feb 10, 2015 | Office Equipment & Supplies

There is nothing to solve here.You just have an expression with two letters; you have no equation to solve because you need an = sign.

Sep 07, 2013 | Office Equipment & Supplies

Syntax should be solve(x^2=121,x) ENTER or solve(x^2-121=0,x). Solutions are x=-11 or x=11.

Jan 05, 2012 | Texas Instruments TI-89 Calculator

On most calculators with a solver function, you can specify a starting value for the variable (in this case x) after pressing [Solve] but before pressing the = key.

To get the three solutions, try entering the function, pressing [Solve] then an estimated starting point (say 0.5 or 0.7) then [=]. This should show the +root2/2 result (ie 0.7071067812).

You should not need to enter the function again.

Follow this by pressing [Solve] again, then another estimated starting point (say -0.5 or -0.7) then [=] to get the -root2/2 result.

Similarly, then press [Solve] again, and enter another estimated starting point (say -2) then [=] to get the final solution of -3.

On Casio calculators, the [Solve] function is usually found by pressing [Shift][Calc]. Note that the solver function generally won't return numbers in surd form, only as a decimal value.

To get the three solutions, try entering the function, pressing [Solve] then an estimated starting point (say 0.5 or 0.7) then [=]. This should show the +root2/2 result (ie 0.7071067812).

You should not need to enter the function again.

Follow this by pressing [Solve] again, then another estimated starting point (say -0.5 or -0.7) then [=] to get the -root2/2 result.

Similarly, then press [Solve] again, and enter another estimated starting point (say -2) then [=] to get the final solution of -3.

On Casio calculators, the [Solve] function is usually found by pressing [Shift][Calc]. Note that the solver function generally won't return numbers in surd form, only as a decimal value.

Jul 07, 2011 | Office Equipment & Supplies

There are a lot of ways to do it. One is to write a program using the cubic formula. If you just want the roots, use the solve() or zeros() functions.

For example, to find the zeros of x^2-6x^2+11x-6, enter

solve(x^3-6*x^2+11*x-6=0,x)

or

zeros(x^3-6*x^2+11*x-6,x)

Note that solve() has "=0" in it while zeros() does not.

solve() will give you an answer of

x=1 or x=2 or x=3

while zeros will give you an answer of

{1 2 3}

which plainly are the same thing, just expressed differently.

For example, to find the zeros of x^2-6x^2+11x-6, enter

solve(x^3-6*x^2+11*x-6=0,x)

or

zeros(x^3-6*x^2+11*x-6,x)

Note that solve() has "=0" in it while zeros() does not.

solve() will give you an answer of

x=1 or x=2 or x=3

while zeros will give you an answer of

{1 2 3}

which plainly are the same thing, just expressed differently.

May 09, 2011 | Texas Instruments TI-89 Calculator

Use the quadratic formula or completing the square.

Completing the square:

x^2 -13x=-36

x^2-2*(13/2) +(13/2)^2=-36+(13/2)^2

The left side can be factored as (x-13/2)^2.

The right side is (13^2-36*4)/4=(169-144)/4=25/4

Assembling the two sides

(x-13/2)^2=25/4

Taking the square roots x-13/2=+ or - 5/2

Case 1 : x-13/2=+ 5/2.

Solving for x you get the first root as x=(5+13)/2=18/2=9

Case 2 : x-13/2=-5/2.

Solving for x, you get the other root as x=(13-5)/2=8/2=4.

The roots are x1=9, and x2=4

Completing the square:

x^2 -13x=-36

x^2-2*(13/2) +(13/2)^2=-36+(13/2)^2

The left side can be factored as (x-13/2)^2.

The right side is (13^2-36*4)/4=(169-144)/4=25/4

Assembling the two sides

(x-13/2)^2=25/4

Taking the square roots x-13/2=+ or - 5/2

Case 1 : x-13/2=+ 5/2.

Solving for x you get the first root as x=(5+13)/2=18/2=9

Case 2 : x-13/2=-5/2.

Solving for x, you get the other root as x=(13-5)/2=8/2=4.

The roots are x1=9, and x2=4

Apr 20, 2011 | Casio FX-115ES Scientific Calculator

You can solve it with following method.

5x+3y=6 2x-4y=5

So 5x=6-3y so 2[(6-3y)/5]-4y=5

So x=(6-3y)/5 so 12-6y-20y=25

so -26y=25-12

so -26y=13

so y= -(1/2)

2x-4y=5

so 2x=5+4y

so 2x=5+4(-1/2)

so 2x=(10-4)/2

so 2x=6/4

so x =3/2

The value of x=3/2 and value of y= -1/2

Let me know if you need further assistance.

Thanks for using FixYa.

5x+3y=6 2x-4y=5

So 5x=6-3y so 2[(6-3y)/5]-4y=5

So x=(6-3y)/5 so 12-6y-20y=25

so -26y=25-12

so -26y=13

so y= -(1/2)

2x-4y=5

so 2x=5+4y

so 2x=5+4(-1/2)

so 2x=(10-4)/2

so 2x=6/4

so x =3/2

The value of x=3/2 and value of y= -1/2

Let me know if you need further assistance.

Thanks for using FixYa.

Mar 03, 2010 | Office Equipment & Supplies

Hi,

**You can use algebra to solve it.**

Use the fact that 4 =2^2 and 8=2^3 and substitute in the equation

(2^3)^x =2^(3*x)

Then** 2^(3*x)=2^2**

By equating the exponents

3x=2 and**x=2/3**

**Using the solve( function**

With the calculator physical keys between square brackets, and the SHIFTed or ALPHA keys between parentheses, type in the following

8 [^ ] [ALPHA] [ ) ] (X) [ALPHA][CALC] ( =) 4 [SHIFT][CALC] (SOLVE)

Once the foregoing command entered press [=]

Display shows**Solve for X** on top line and probably **0.000** on bottom line.

Press [.] 5 to give 0.5 as a guess for the value of x

After a moment the calculator returns with the solution.

The display shows three lines

1st Line: 8[^] X =4

2nd Line: X= 0.66666666

3rd Line : L-R =0.

Your solution is 0.6666666. In fact the exact solution is 2/3.

Hope it helps.

Thank you for using FixYa and for rating this solution.

Use the fact that 4 =2^2 and 8=2^3 and substitute in the equation

(2^3)^x =2^(3*x)

Then

By equating the exponents

3x=2 and

With the calculator physical keys between square brackets, and the SHIFTed or ALPHA keys between parentheses, type in the following

8 [^ ] [ALPHA] [ ) ] (X) [ALPHA][CALC] ( =) 4 [SHIFT][CALC] (SOLVE)

Once the foregoing command entered press [=]

Display shows

Press [.] 5 to give 0.5 as a guess for the value of x

After a moment the calculator returns with the solution.

The display shows three lines

1st Line: 8[^] X =4

2nd Line: X= 0.66666666

3rd Line : L-R =0.

Your solution is 0.6666666. In fact the exact solution is 2/3.

Hope it helps.

Thank you for using FixYa and for rating this solution.

Dec 03, 2009 | Casio FX-115ES Scientific Calculator

Just plug in one side of the equation and find the answer. Then plug in the other side and compare answers.

Feb 19, 2008 | Texas Instruments TI-89 Calculator

First to solve a problem, write it like this

solve(3/x-2+21/x^2-4=14/x+2,x)

Second, for inverse, do this (note the "y=" part)

solve(y=3x^2 -2x+1,x)

The calculator will rewrite the formula as x = ...

solve(3/x-2+21/x^2-4=14/x+2,x)

Second, for inverse, do this (note the "y=" part)

solve(y=3x^2 -2x+1,x)

The calculator will rewrite the formula as x = ...

Oct 23, 2007 | Texas Instruments TI-89 Calculator

Jul 16, 2014 | Canon PIXMA MP150 All-In-One InkJet...

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