Question about Office Equipment & Supplies

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Posted on Mar 27, 2011

Hi,

You need to calculate speed? . Speed=Distance/Time. In your case distance 6km and time 6 mins.

So you are travelling in 1km/min. In standard format, you are travelling in 60km/hr. Your speed is 60km/hr or 16.66667m/s.

Hope this helps.

Shane

Posted on Mar 26, 2011

Hi,

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Posted on Jan 02, 2017

First translate the various statements of the problem into equations. then try to solve the equations. It won't do much good if I just gave you the answers.

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To travel 6km in half an hour, you need to travel 12kph.

Sep 10, 2014 | Cars & Trucks

It doesn't matter! Because the US star wars project blew them both up in the air. ^^

Jul 12, 2014 | Video Game Consoles & Games

Journey time 2hrs = 2 x 60 mins = 2 x 60 x 60 seconds

Distance 180 km = 180,000 m

Average speed = 3 x 6 x 10000 / 2 x 6 x 6 x 100 m/s

= 6 x 6 x 100 x 100 / [2 x (2 x 6 x6 x100)] m/s

= 100 / 4 m/s

= 25 m/s

5.May.2014

Distance 180 km = 180,000 m

Average speed = 3 x 6 x 10000 / 2 x 6 x 6 x 100 m/s

= 6 x 6 x 100 x 100 / [2 x (2 x 6 x6 x100)] m/s

= 100 / 4 m/s

= 25 m/s

5.May.2014

May 05, 2014 | Office Equipment & Supplies

you have to get there by foot/vehicule once before fast travel work

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Recurve bow arrows can travel up to 150 mph. compound bow arrow can travel up to 200 mph and in longbow arrows the velocity is slower because the weight of the arrows.

Aug 26, 2012 | Betsey Johnson Archery

18 km/hour

The bike is traveling at the speed of 12/40 = 6/20 =**18/60**

18 km/60 minutes

The bike is traveling at the speed of 12/40 = 6/20 =

18 km/60 minutes

Jun 21, 2011 | Computers & Internet

To start out, you need to figure out what the equation for the problem is. You know a few things that should help you along the way:

The 6 at the front is how many hours the first train traveled. the 4 is the hours the second train traveled. the 60 is (4*15) which is how much faster the second train was going. the 580 is the total distance between them.

Solve for x

10x=520

x=52

So the westbound train was going 52 km/h and the east bound train was going 67km/h.

- The trains are 580 km apart
- one train traveled for 6 hours
- the other train traveled for 4 hours
- one train is going 15km/h faster than the other.

The 6 at the front is how many hours the first train traveled. the 4 is the hours the second train traveled. the 60 is (4*15) which is how much faster the second train was going. the 580 is the total distance between them.

Solve for x

10x=520

x=52

So the westbound train was going 52 km/h and the east bound train was going 67km/h.

May 03, 2011 | Texas Instruments TI-30 XIIS Calculator

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Nov 12, 2009 | Video Game Consoles & Games

Sep 23, 2017 | Office Equipment & Supplies

23 people viewed this question

Usually answered in minutes!

Thank you Shane,

This is for a speeding fine , from point A to point B a distance of 6 klm's with a time frame of 6min.

At [point A ] I was doing 81 KPH in a 70 KPH zone @ 05:52pm at[point B ] I was doing 74 KPH in a 60 KPH zone @ 05:58pm.....

ALLEDGEDDoes this further information make a difference to your original answer.

If your in Australia this was in NSW A = Blandford and B = Murrurundi all on the New England Hwy.

Outside the speed zones the speed limit is 100 KPH on the open Hwy.

I was not speeding is the information supplied by the NSW government consistant with the facts I have given you, so , does the times match up with time speed and distance ?

Cheers Harry Bryce

041540500

I have put in my mobile number if you wish to call me [I don't know if thats allowed]

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