Question about Super Tutor Trigonometry (ESDTRIG) for PC

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Posted on Mar 23, 2011

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Posted on Jan 02, 2017

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30 and 80.

If this is homework, be sure to show your work.

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Nov 15, 2016 | Office Equipment & Supplies

If I understand your terminology correctly, you have a triangle with a hypotenuse of 6' 3-13/16" and a side opposite the angle you wish to find with a length of 8" (and a side adjacent to the angle you wish to find with a length of 6' 3-3/8") Trigonometry says that the sine of an angle is the length of the opposite side divided by the hypotenuse. (all units must be the same, so convert everything to inches)

So sine (angle) = 8/(6 * 12 + 3 + 13/16)

sine (angle = 8/(75.8125)

sine(angle) = .105523

angle = arc-sine(.105523)

angle = 6.0573 degrees (from tables, calculator, computer etc)

So sine (angle) = 8/(6 * 12 + 3 + 13/16)

sine (angle = 8/(75.8125)

sine(angle) = .105523

angle = arc-sine(.105523)

angle = 6.0573 degrees (from tables, calculator, computer etc)

Jun 07, 2014 | CyberEd Trigonometry Problem Solver

Label of key [deg symbol ' "]. It is between [(-)] and [hyp]

To enter a value in decimal degrees

12.58 [deg ' "] [=] Screen displays 12.58 deg on top line and 12 deg 34' 48" on bottom line.

Pressing the [deg ' "] key while this value is displayed will show 12.58

To enter a DMS value:

Press the [deg ' "] key after each number even if one of the numbers D,M,S is nill (0).

Exemple Enter 25 deg 0 ' 48"

25 [deg ' "] 0 [deg ' "] 48 [deg ' "] [=]

Screen displays 25 deg 0' 48" on bottom line

Pressing the [deg ' "] key converts this result to decimal degrees 25.013

This showed you how to enter angles in DMS or DD. For the rest 'find the angles, etc.' you should refer to your trigonometry manual: You have the definitions of the trigonometric ratios, the sine law, the cosine law to resolve triangles.

To enter a value in decimal degrees

12.58 [deg ' "] [=] Screen displays 12.58 deg on top line and 12 deg 34' 48" on bottom line.

Pressing the [deg ' "] key while this value is displayed will show 12.58

To enter a DMS value:

Press the [deg ' "] key after each number even if one of the numbers D,M,S is nill (0).

Exemple Enter 25 deg 0 ' 48"

25 [deg ' "] 0 [deg ' "] 48 [deg ' "] [=]

Screen displays 25 deg 0' 48" on bottom line

Pressing the [deg ' "] key converts this result to decimal degrees 25.013

This showed you how to enter angles in DMS or DD. For the rest 'find the angles, etc.' you should refer to your trigonometry manual: You have the definitions of the trigonometric ratios, the sine law, the cosine law to resolve triangles.

Feb 24, 2011 | Casio FX-115ES Scientific Calculator

In right triangle we are making 90 degree angle triangle, we can have problem for finding hypotenuse or finding sin or cos values of the side of the triangle.
For ex,Find out the hypotenuse,sin and cos value of the right triangle with base 4 cm and perpendicular 3 cm
Solution:Hypotenuse = SQRT(4^2 + 3^2)
=SQRT(4*4 + 3*3)
=SQRT(16+9)=SQRT(25)=5 cm
For right triangle,
sin(x)=3/5=0.6
cos(x)=4/5 =0.8

Jul 16, 2010 | Super Tutor Trigonometry (ESDTRIG) for PC

From the given data we can get angle A=30 degrees and B = 30 degrees.

There fore

sin ( A+B) = sin ( 30+30) =sin 60 = root ( 3 )/ 2

There fore

sin ( A+B) = sin ( 30+30) =sin 60 = root ( 3 )/ 2

May 19, 2010 | Mathsoft Solving and Optimization...

Tangent is a trigonometry term. It is used to find the Opposite/Adjacent ratio when given an angle measure in a right triangle. The proper syntax is tan(angle measure).

Dec 17, 2009 | Computers & Internet

It is not clear which angle you are talking about...

In one case the Hypot = 36/(cos(63)) meters. (about 79 meters)

The other case Hypot = 36/(cos(90-63)) meters (about 40 meters)

In one case the Hypot = 36/(cos(63)) meters. (about 79 meters)

The other case Hypot = 36/(cos(90-63)) meters (about 40 meters)

Sep 12, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

Debs,

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

this is solved by starting with the SECOND leg of the flight considered as a triangle.

Find how far DUE east the plane travels (100 km x Cos10 = 83.9 km) using 10 degrees because that is how much is left of the 90 degree quadrent after subtracting the 80 degrres course direction.

Similarly find out how far DUE north the plane travels (100 km x Cos80 = 11 km).

Now get the total flight NORTH = 300 + 11 = 311

- and total EAST = 83.9

Finally, use Pythagoras theorem.to get the total DISTANCE:

square root of ( 311 squared + 83 squared ) = 321 km

Also the DIRECTION from its Tangent of 83 /311 = 14.9 degrees

Dec 19, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

Hi Jehho soria

Draw a right triangle with the vertical portion of the triangle representing the 37 meters of the light house The base of the triangle is the distance we are trying to find. If the angle of depression is 15 degrees, the other angle is 75 degrees. This is the angle from the boat to the top of the lighthouse.

so The Tangent of 75 degrees is equal to the side opposite the angle (the height of the lighthouse) divided by the side adjacent (the distance we are trying to find.

solving for the distance we get distance = 37 divided by the tangent of 37 degrees

Looking up the tangent of 15 degrees on google give .2679

dividing 137 by .2679=138,1 meters

Hope this helps Loringh PS Please leave a rating for me.

Draw a right triangle with the vertical portion of the triangle representing the 37 meters of the light house The base of the triangle is the distance we are trying to find. If the angle of depression is 15 degrees, the other angle is 75 degrees. This is the angle from the boat to the top of the lighthouse.

so The Tangent of 75 degrees is equal to the side opposite the angle (the height of the lighthouse) divided by the side adjacent (the distance we are trying to find.

solving for the distance we get distance = 37 divided by the tangent of 37 degrees

Looking up the tangent of 15 degrees on google give .2679

dividing 137 by .2679=138,1 meters

Hope this helps Loringh PS Please leave a rating for me.

Nov 14, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

C = 3B = 2(A+B)

3/2 B = A+B

1/2B = A

C = 2 (1/2B + B)

C = 3B

**A = 1/2B

C = 3B

B = B

1/2B + 3B + B = 4 1/2 B

180/4.5B => B = 40

If B = 40, then A = 1/2B = 20 and C = 3B = 120.

**answer: A = 20 degrees, B = 40 degrees and C = 120 degrees.

3/2 B = A+B

1/2B = A

C = 2 (1/2B + B)

C = 3B

**A = 1/2B

C = 3B

B = B

1/2B + 3B + B = 4 1/2 B

180/4.5B => B = 40

If B = 40, then A = 1/2B = 20 and C = 3B = 120.

**answer: A = 20 degrees, B = 40 degrees and C = 120 degrees.

Jun 27, 2008 | Super Tutor Trigonometry (ESDTRIG) for PC

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