Question about Computers & Internet

You can get them from various vendors in the last few cities. does that help

Posted on Mar 15, 2011

Hi,

a 6ya expert can help you resolve that issue over the phone in a minute or two.

best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.

the service is completely free and covers almost anything you can think of (from cars to computers, handyman, and even drones).

click here to download the app (for users in the US for now) and get all the help you need.

goodluck!

Posted on Jan 02, 2017

y = x+1

y = (4) + 1

y = 5

y = x + 1

y = (-4) + 1

y = -3

2y - 2 = 2x

2y - 2 = 2 (4)

2y - 2 = 8

2y - 2 + 2 = 8 + 2

2y = 10

2y/2 = 10/2

y = 5

2y - 2 = 2(-4)

2y - 2 = -8

2y -2 + 2 = -8 + 2

2y = -6

2y / 2 = -6 /2

y = -3

The results are the same, implying that they are the same line.

Why?

2y - 2 = 2x

2y - 2 + 2 = 2x + 2

2y = 2x + 2

divide everything by 2

y = x + 1

Good luck,

Paul

y = (4) + 1

y = 5

y = x + 1

y = (-4) + 1

y = -3

2y - 2 = 2x

2y - 2 = 2 (4)

2y - 2 = 8

2y - 2 + 2 = 8 + 2

2y = 10

2y/2 = 10/2

y = 5

2y - 2 = 2(-4)

2y - 2 = -8

2y -2 + 2 = -8 + 2

2y = -6

2y / 2 = -6 /2

y = -3

The results are the same, implying that they are the same line.

Why?

2y - 2 = 2x

2y - 2 + 2 = 2x + 2

2y = 2x + 2

divide everything by 2

y = x + 1

Good luck,

Paul

Feb 07, 2017 | The Office Equipment & Supplies

Hi There!

To battle the Gengar you will need to have a Pokemon game boy advanced game (FireRed, LeafGreen, Ruby, Sapphire, or Emerald) in your GBA slot on the bottom of your DS, then go into the 2nd floor of the Old Chateau in Eterna Forest and enter the room with the portrait that has red eyes. You will have a small chance to encounter a wild Gengar then.

Have a fantastic day!

To battle the Gengar you will need to have a Pokemon game boy advanced game (FireRed, LeafGreen, Ruby, Sapphire, or Emerald) in your GBA slot on the bottom of your DS, then go into the 2nd floor of the Old Chateau in Eterna Forest and enter the room with the portrait that has red eyes. You will have a small chance to encounter a wild Gengar then.

Have a fantastic day!

May 22, 2014 | Nintendo Pokemon Platinum for DS

You can find wild Gengars in the Old Chateau, in the room with the picture hanging in it and the red eyes that follow you around the room. You must have any one of the Game Boy Advance games in your GBA slot of your DS in order to be able to find them.

May 22, 2014 | Nintendo Pokemon Platinum for DS

x^2+13x+15=0

Recall (x+a)^2=x^2+2ax+a^2

Write x^2+2*(13/2)x+15, and compare the terms in x.**a=13/2**

x^2+13x+15=x^2+2(13/2)x**+(13/2)^2-(13/2)^2**+15

The first three terms are the expansion of** (x+13/2)^2**

You expression is equivalent to

(x+13/2)^2-[(13/2)^2-15]=(x+13/2)^2-[SQRT(109)/2]^2

Use the identity for the difference of two squares a^2-b^2=(a-b)(a+b)

This gives

x^2+13x+15=(x+13/2)^2-[SQRT(109)/2]^2=

**[x+13/2 -SQRT(109)/2][x+13/2+SQRT(109)/2]**

The polynomial can be written as (x-a)(x-b) (Note a has nothing to do with the one used above to complete the square. You can use any name for the roots, x_1, x_2, anything.

The two roots are on the screen captures below.

PS. I prefer to manipulate exact expressions with radicals. If you do not like it use the decimal approximations.

Recall (x+a)^2=x^2+2ax+a^2

Write x^2+2*(13/2)x+15, and compare the terms in x.

x^2+13x+15=x^2+2(13/2)x

The first three terms are the expansion of

You expression is equivalent to

(x+13/2)^2-[(13/2)^2-15]=(x+13/2)^2-[SQRT(109)/2]^2

Use the identity for the difference of two squares a^2-b^2=(a-b)(a+b)

This gives

x^2+13x+15=(x+13/2)^2-[SQRT(109)/2]^2=

The polynomial can be written as (x-a)(x-b) (Note a has nothing to do with the one used above to complete the square. You can use any name for the roots, x_1, x_2, anything.

The two roots are on the screen captures below.

PS. I prefer to manipulate exact expressions with radicals. If you do not like it use the decimal approximations.

Jan 18, 2014 | Texas Instruments TI-84 Plus Calculator

Hi,

**
ZIP Codes & Phone Area Code of the**** City of ****
Makati..**

Location ZIP Code Phone Area Code

Location ZIP Code Phone Area Code

Ayala-Paseo de Roxas

1226

2

Bangkal

1233

2

Bel-air

1209

2

Cembo

1214

2

Comembo

1217

2
Dasmarinas Village North
1221
2

Dasmarinas Village South

1222

2

Forbes Park North

1219

2

Forbes Park South

1220

2

Fort Bonifacio Naval Stn.

1202

2

Fort Bonifacio (Camp)

1201

2

Greenbelt

1228

2

Guadalupe Nuevo

1212

2
Guadalupe Viejo
1211
2
Kasilawan
1206
2
La Paz-Singkamas-Tejeros
1204
2
Legaspi Village
1229
2
Magallanes Village
1232
2
Makati Commercial Ctr.
1224
2
Makati CPO + Buendia Ave
1200
2
Olympia & Carmona
1207
2
Palanan
1235
2
Pasong Tamo & Ecology Vill
1231
2
Pembo
1218
2
Pinagkaisahan-Pitogo
1213
2
Pio del Pilar
1230
2
Poblacion
1210
2
Rembo (East)
1216
2
Rembo (West)
1215
2
Salcedo Village
1227
2
San Antonio Village
1203
2
San Isidro
1234
2
San Lorenzo Village
1223
2
Sta. Cruz
1205
2
Urdaneta Village
1225
2

Valenzuela, Santiago, Rizal

1208
2

Thanks for using FixYa.

Jun 22, 2011 | Computers & Internet

Well I think that the gamepack is broken or it might be due to this glitch on catching missingno that glitch can messup the gamepack then so buy a new one.

Feb 08, 2010 | Nintendo Pokemon Red

I don think u are in the right way to program the Matrix in C language, i found a lot of syntax error in your code, but nevermind i had correct it for u. Maybe still need a little correction for your own. Following code:

void matrix(int a[2][2],int b[2][2],int c[2][2]);

main()

{

int a[2][2]={{3,3},{4,4}};

int b[2][2]={{1,1},{2,2}};

int c[2][2]={0},i,j;

matrix(a,b,c);

printf("product of 2 matrix is");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

printf(" %d",c[i][j]);

printf(" ");

}

}

void matrix(int a[2][2],int b[2][2],int c[2][2])

{

int row,col,sum1=0,sum2=0;

for(col=0;col<2;col++)

{

row=0;

sum1=(a[row][col]*b[row][col])+(a[row][col]*b[row+1][col]);

c[row][col]=sum1;

sum2=(a[row+1][col]*b[row][col])+(a[row+1][col]*b[row+1][col]);

c[row+1][col]=sum2;

}

}

void matrix(int a[2][2],int b[2][2],int c[2][2]);

main()

{

int a[2][2]={{3,3},{4,4}};

int b[2][2]={{1,1},{2,2}};

int c[2][2]={0},i,j;

matrix(a,b,c);

printf("product of 2 matrix is");

for(i=0;i<2;i++)

{

for(j=0;j<2;j++)

printf(" %d",c[i][j]);

printf(" ");

}

}

void matrix(int a[2][2],int b[2][2],int c[2][2])

{

int row,col,sum1=0,sum2=0;

for(col=0;col<2;col++)

{

row=0;

sum1=(a[row][col]*b[row][col])+(a[row][col]*b[row+1][col]);

c[row][col]=sum1;

sum2=(a[row+1][col]*b[row][col])+(a[row+1][col]*b[row+1][col]);

c[row+1][col]=sum2;

}

}

Sep 10, 2009 | Intel Computers & Internet

its not possible

Dec 06, 2008 | Nokia 1100

Maybe he hacked into his Ds, it happens alot.

Nov 25, 2008 | Nintendo Pokemon Diamond for DS

can't quite make out the detail on buttons on the image I have of your calculator but here goes.

say for example, the geometric mean of 2 × 3 × 6 × 8 is the 4th root of 288, or approximately 4.12.

enter nth root first, in this case 4 then shift then root symbol then open bracket, 2x3x6x8, close bracket then = ,

should give you 4.1195 etc

say for example, the geometric mean of 2 × 3 × 6 × 8 is the 4th root of 288, or approximately 4.12.

enter nth root first, in this case 4 then shift then root symbol then open bracket, 2x3x6x8, close bracket then = ,

should give you 4.1195 etc

Jun 04, 2008 | Casio FX-300MS Calculator

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