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Finding the length of a triangle

I have a triangle 1 angle 90 degrees, 1 angle 53 degrees and one angle 37 degrees. I have the length between the 90 degree and the 37 degree which is 45 feet. I need to know what the length is between the 90 degree and the 53 degree angles. thanks

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  • Anonymous Mar 19, 2014

    I just want to know what the name of the of the joint used when two pieces of wood are joined on a 45 degree angle and both pieces of wood stays in a straight line

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45 tan(37) or about 39.1 feet.

Posted on Mar 29, 2014

Might try

(54tan)/45

I don't have a calc that will do it or I would try it and see.

Posted on Aug 01, 2008

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For a 10ft radius octagon, how long should each side be?


There is probably a formula for this or other ways of doing this, but I will give it a shot.

An octagon has 8 sides (octopus has 8 legs). To make an octagon, we effectively have 8 triangles joined at the centre. In the centre, we have 8 equal angles. Since a full circle is 360 degrees, each of these angles must be 360 / 8 or 45 degrees.

Now we can just focus on one of these triangles. We have an angle of 45 degrees at the centre and two arms extending out 10 feet.

At this point, we can use the cosine law to calculate the length of the side or we can recognize that it is an isosceles triangle and work out the other angles and determine the length of the side.

Using Cosine Law, a^2= b^2 + c^2 - 2xbxc Cos A
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Finding the area of a triangle in the coordinate Plane


I find the easiest way to solve these is to sketch them first (I'm a visual learner;) We get a nice right-angled triangle, with the right-angle at B. The formula for the area of a triangle is 1/2 * base* height or (base * height)/2.

We can use BC or AB as the base.

If we use BC as the base, the length is 9-4 or 5. The height is 6-2 or 4.

We can now but the base and the height in the formula to figure out the area.

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Mar 19, 2015 | Office Equipment & Supplies

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Finding area of a Triangle in the Coordinate Plane


The area of a triangle is 1/2 times base times height. A sketch of the triangle in the coordinate plane will determine how easy or hard this will be to be. From the sketch, you will see that this is a right-angled triangle with B being the right-angle. This makes it easier because we can easily determine the base and the height to use in the formula.

We can chose AB or BC to be the base, while the other will be the height. If we choose the base of AB, its length is 4, the 6 - 2. The height is 9-(-4) or 13.

We can now put the length and height into the formula to calculate the area of the triangle.

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The area of a triangle is 1/2 times base times height. A sketch of the triangle in the coordinate plane will determine how easy or hard this will be to be. From the sketch, you will see that this is a right-angled triangle with B being the right-angle. This makes it easier because we can easily determine the base and the height to use in the formula.

We can chose AB or BC to be the base, while the other will be the height. If we choose the base of AB, its length is 4, the 6 - 2. The height is 9-(-4) or 13.

We can now put the length and height into the formula to calculate the area of the triangle.

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I have a problem concerning radians and angles


About 146 and a half degrees.

If this is homework, be sure to show your work.

Oct 22, 2013 | Office Equipment & Supplies

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Their are three angle d first one is 128 degree, the second one is 37 degree, find x


I presume that x is the measure in degrees of the third angle. Use the fact the sum of the interior angle of a triangle is equal to 180 degrees.
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x=180-165=15 degrees.

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Given a length of 30 cm on the x axis and a length of 10 cm on the y axis and a angle of 90 at the x/y axis intersection is there a short cut to calculate interior angles and hypot. of the triangle?


Yes, there is shortcut because this is right triangle, so you can use Pythagorean theorem (see picture).
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  2. Sin(a)=longer cathetus/hypotenuse=0.949 so a=arcsin(0.949)=71.6 degrees
  3. Finally b=90-a=18.4 degrees.
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If this was helpful please rate 4 thumbs :)

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I am getting the wrong answers with the tan -1 function


Hello,
That habit of TI, Casio, and Sharp to label the inverse trigonometric functions with the -1 superscript can cause confusions.
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