Question about Texas Instruments TI-1795 SV Calculator

My TI-1795+ will neither do simple add, subtract or multiplying. When I enter a figure it shows only part of the numbers I enter and comes up with a wrong answer. HELP!

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I love that old, little calculator, the TI-1795+ (not the new one, SV).

Does anyone know where to get any more of these. I'd buy a few,

but they are probably out of production. I've had my three for years

and years and years. They still work fine.

Posted on Jan 02, 2009

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Has something contaminated the keyboard? Most likely something liquid. If it is not displaying the numbers as you enter them, there is something wrong with the keyboard. It will need to be taken apart and cleaned. MM85

Posted on Jul 27, 2008

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Posted on Jan 02, 2017

- Make sure you're working with two fractions.
- Multiply numerator x numerator, then multiply denominator x denominator.

- Make sure you're working with two fractions
- Flip the second fraction upside down.
- Change the division sign into a multiplication sign.
- Multiply top x top and bottom x bottom.

- Convert mixed numbers into improper fractions.
- Take the whole (non-fraction) number and multiply it by the denominator.
- Add that answer to the numerator.
- Put that amount over the original denominator and you will have an improper fraction.

- Find the lowest common denominator (bottom number). For both adding and subtracting fractions, you'll start with the same process.
- Multiply fractions to match the lowest common denominator.
- Add or subtract the two numerators (top number) but NOT the denominators.

Mar 07, 2017 | Homework

It probably uses adding machine logic. Try the following example.

3+

4-

5+

*

You should get 3, -1, and 4 on the screen, the running total. The tape should show the +3, -4, +5, and finally 4, the numbers that you entered and the total. Think of each entry as adding/subtracting integers on a number line rather than 3+4-5;)

Let me know if you have any questions.

Paul

3+

4-

5+

*

You should get 3, -1, and 4 on the screen, the running total. The tape should show the +3, -4, +5, and finally 4, the numbers that you entered and the total. Think of each entry as adding/subtracting integers on a number line rather than 3+4-5;)

Let me know if you have any questions.

Paul

Feb 04, 2016 | Office Equipment & Supplies

Moisture damage if exposed to humidity

Jul 24, 2014 | Canon MP11DX Desktop Calculator, 12-Digit...

Is it subtracting, multiplying, dividing? Check the way you are entering your numbers.

Oct 22, 2013 | Office Equipment & Supplies

About 56%. Divide 95000 by 215000, multiply by 100, then subtract from 100.

Aug 26, 2013 | Texas Instruments TI-1795 SV Calculator

In Algebra

Likewise when you see

Special Binomial Products So when you multiply binomials you get ... Binomial Products

And we are going to look at

1. Multiplying a Binomial by Itself What happens when you square a binomial (in other words, multiply it by itself) .. ?

(a+b)2 = (a+b)(a+b) = ... ?

The result:

(a+b)2 = a2 + 2ab + b2

You can easily see why it works, in this diagram:

2. Subtract Times Subtract
And what happens if you square a binomial with a **minus** inside?

(a-b)2 = (a-b)(a-b) = ... ?

The result:

(a-b)2 = a2 - 2ab + b2

3. Add Times Subtract
And then there is one more special case... what if you multiply (a+b) by (a-b) ?

(a+b)(a-b) = ... ?

The result:

(a+b)(a-b) = a2 - b2

That was interesting! It ended up very simple.

And it is called the "**difference of two squares**" (the two squares are **a2** and **b2**).

This illustration may help you see why it works:

a2 - b2 is equal to (a+b)(a-b)
Note: it does not matter if (a-b) comes first:

(a-b)(a+b) = a2 - b2

The Three Cases
Here are the three results we just got:

(a+b)2
= a2 + 2ab + b2
} (the "perfect square trinomials")
(a-b)2
= a2 - 2ab + b2
(a+b)(a-b)
= a2 - b2
(the "difference of squares")
Remember those patterns, they will save you time and help you solve many algebra puzzles.

Using Them
So far we have just used "a" and "b", but they could be anything.

Example: (y+1)2

We can use the (a+b)2 case where "a" is y, and "b" is 1:

(y+1)2 = (y)2 + 2(y)(1) + (1)2 = y2 + 2y + 1

Example: (3x-4)2

We can use the (a-b)2 case where "a" is 3x, and "b" is 4:

(3x-4)2 = (3x)2 - 2(3x)(4) + (4)2 = 9x2 - 24x + 16

Example: (4y+2)(4y-2)

We know that the result will be the difference of two squares, because:

(a+b)(a-b) = a2 - b2

so:

(4y+2)(4y-2) = (4y)2 - (2)2 = 16y2 - 4

Sometimes you can recognize the pattern of the answer:

Example: can you work out which binomials to multiply to get 4x2 - 9

Hmmm... is that the difference of two squares?

Yes! **4x2** is **(2x)2**, and **9** is **(3)2**, so we have:

4x2 - 9 = (2x)2 - (3)2

And that can be produced by the difference of squares formula:

(a+b)(a-b) = a2 - b2

Like this ("a" is 2x, and "b" is 3):

(2x+3)(2x-3) = (2x)2 - (3)2 = 4x2 - 9

So the answer is that you can multiply **(2x+3)** and **(2x-3)** to get **4x2 - 9**

Jul 26, 2011 | Computers & Internet

Calculator should be in [MATRIX] MODE

Try the matrices 2X2 matrices matA [1,2,3,4] matB [5,6,7,8], Add them, subtract them, multiply them, take the square of each. If that works for these matrices, then it must be your data. Be careful with negative numbers. To enter those, you must use the change sign (-).

There is also the possibility that the instructions were misread.

Try the matrices 2X2 matrices matA [1,2,3,4] matB [5,6,7,8], Add them, subtract them, multiply them, take the square of each. If that works for these matrices, then it must be your data. Be careful with negative numbers. To enter those, you must use the change sign (-).

There is also the possibility that the instructions were misread.

Dec 14, 2009 | Casio FX-115ES Scientific Calculator

Hello,

There is a rule of Algebra, that says

**(a^m)[x] (a^n) = a^(m+n) **

a is the base of the power, n, and m are the exponents. As you can see, multiplying two powers of the same base is equal to the power of the (common) base with the sum of the exponents.

If that is what you had in mind, the calculator uses the rule correctly and no intervention from you is necessary.

**If you enter (2^4)[x](2^6), the calculator will give 1024, which is 2^10. **

I may be wrong, but what you call add exponents refers really to performing addition where addends (the terms you add) are arbitrary powers, such as

2^7 + (5.5^3) - (1/3)^4

Once you enter a power term, the calculator calculates it and the result is now just a number. It can be added, subtracted, multiplied

For the exemple above

2 [Y to the x] 7 + (5.5)[Y to the x] 3 -(1/3) [Y to the x] 4 [=] yields 294.3626543

For the cube of 5.5 you can use the key combination [2nd][X^3]

Hope it helps.

There is a rule of Algebra, that says

a is the base of the power, n, and m are the exponents. As you can see, multiplying two powers of the same base is equal to the power of the (common) base with the sum of the exponents.

If that is what you had in mind, the calculator uses the rule correctly and no intervention from you is necessary.

I may be wrong, but what you call add exponents refers really to performing addition where addends (the terms you add) are arbitrary powers, such as

2^7 + (5.5^3) - (1/3)^4

Once you enter a power term, the calculator calculates it and the result is now just a number. It can be added, subtracted, multiplied

For the exemple above

2 [Y to the x] 7 + (5.5)[Y to the x] 3 -(1/3) [Y to the x] 4 [=] yields 294.3626543

For the cube of 5.5 you can use the key combination [2nd][X^3]

Hope it helps.

Oct 08, 2009 | Texas Instruments TI-30 XIIS Calculator

When you want to complete a problem on an adding machine, such as "7 - 3," you would not key in "7," then the subtraction sign, then "3" and then an equal sign. If you do, then you will get an answer of "-4," and you know that is not the correct answer. Again, you have to think like an accountant when you are working with your adding machine. To figure this subtraction problem on an adding machine, you would need to key in "7," the addition sign, "3" and then the subtraction sign; you would get the answer of 4. You are actually working the problem as "7 + (-3)." This would be true on most modern day machines. In order to subtract, you have to add the negative number.

Sep 25, 2009 | Victor 1208-2 Calculator

Ok, if your trying to do something like this: 2+2=4 then make it continue adding by 2's (6,8,10...)

What you do is after you type 2+2 and press enter, you need to press the "+" and u should see it show this "ans+" then type 2. Then this should continue adding by 2's. Hope this helped.

What you do is after you type 2+2 and press enter, you need to press the "+" and u should see it show this "ans+" then type 2. Then this should continue adding by 2's. Hope this helped.

Feb 28, 2009 | Texas Instruments TI-83 Plus Calculator

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Thanks for your input. I shall see about getting it cleaned. I don't have the right tools to take it apart. I appreciate your prompt reply.

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